Metamath Proof Explorer


Theorem dvdsrval

Description: Value of the divides relation. (Contributed by Mario Carneiro, 1-Dec-2014) (Revised by Mario Carneiro, 6-Jan-2015)

Ref Expression
Hypotheses dvdsr.1 ⊢ B = Base R
dvdsr.2 ⊢ ∥ ˙ = ∥ r ⁡ R
dvdsr.3 ⊢ · ˙ = ⋅ R
Assertion dvdsrval ⊢ ∥ ˙ = x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y

Proof

Step Hyp Ref Expression
1 dvdsr.1 ⊢ B = Base R
2 dvdsr.2 ⊢ ∥ ˙ = ∥ r ⁡ R
3 dvdsr.3 ⊢ · ˙ = ⋅ R
4 fveq2 ⊢ r = R → Base r = Base R
5 4 1 eqtr4di ⊢ r = R → Base r = B
6 5 eleq2d ⊢ r = R → x ∈ Base r ↔ x ∈ B
7 5 rexeqdv ⊢ r = R → ∃ z ∈ Base r z ⋅ r x = y ↔ ∃ z ∈ B z ⋅ r x = y
8 6 7 anbi12d ⊢ r = R → x ∈ Base r ∧ ∃ z ∈ Base r z ⋅ r x = y ↔ x ∈ B ∧ ∃ z ∈ B z ⋅ r x = y
9 fveq2 ⊢ r = R → ⋅ r = ⋅ R
10 9 3 eqtr4di ⊢ r = R → ⋅ r = · ˙
11 10 oveqd ⊢ r = R → z ⋅ r x = z · ˙ x
12 11 eqeq1d ⊢ r = R → z ⋅ r x = y ↔ z · ˙ x = y
13 12 rexbidv ⊢ r = R → ∃ z ∈ B z ⋅ r x = y ↔ ∃ z ∈ B z · ˙ x = y
14 13 anbi2d ⊢ r = R → x ∈ B ∧ ∃ z ∈ B z ⋅ r x = y ↔ x ∈ B ∧ ∃ z ∈ B z · ˙ x = y
15 8 14 bitrd ⊢ r = R → x ∈ Base r ∧ ∃ z ∈ Base r z ⋅ r x = y ↔ x ∈ B ∧ ∃ z ∈ B z · ˙ x = y
16 15 opabbidv ⊢ r = R → x y | x ∈ Base r ∧ ∃ z ∈ Base r z ⋅ r x = y = x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y
17 df-dvdsr ⊢ ∥ r = r ∈ V ⟼ x y | x ∈ Base r ∧ ∃ z ∈ Base r z ⋅ r x = y
18 1 fvexi ⊢ B ∈ V
19 eqcom ⊢ z · ˙ x = y ↔ y = z · ˙ x
20 19 rexbii ⊢ ∃ z ∈ B z · ˙ x = y ↔ ∃ z ∈ B y = z · ˙ x
21 20 abbii ⊢ y | ∃ z ∈ B z · ˙ x = y = y | ∃ z ∈ B y = z · ˙ x
22 18 abrexex ⊢ y | ∃ z ∈ B y = z · ˙ x ∈ V
23 21 22 eqeltri ⊢ y | ∃ z ∈ B z · ˙ x = y ∈ V
24 23 a1i ⊢ x ∈ B → y | ∃ z ∈ B z · ˙ x = y ∈ V
25 18 24 opabex3 ⊢ x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y ∈ V
26 16 17 25 fvmpt ⊢ R ∈ V → ∥ r ⁡ R = x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y
27 2 26 eqtrid ⊢ R ∈ V → ∥ ˙ = x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y
28 fvprc ⊢ ¬ R ∈ V → ∥ r ⁡ R = ∅
29 2 28 eqtrid ⊢ ¬ R ∈ V → ∥ ˙ = ∅
30 opabn0 ⊢ x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y ≠ ∅ ↔ ∃ x ∃ y x ∈ B ∧ ∃ z ∈ B z · ˙ x = y
31 n0i ⊢ x ∈ B → ¬ B = ∅
32 fvprc ⊢ ¬ R ∈ V → Base R = ∅
33 1 32 eqtrid ⊢ ¬ R ∈ V → B = ∅
34 31 33 nsyl2 ⊢ x ∈ B → R ∈ V
35 34 adantr ⊢ x ∈ B ∧ ∃ z ∈ B z · ˙ x = y → R ∈ V
36 35 exlimivv ⊢ ∃ x ∃ y x ∈ B ∧ ∃ z ∈ B z · ˙ x = y → R ∈ V
37 30 36 sylbi ⊢ x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y ≠ ∅ → R ∈ V
38 37 necon1bi ⊢ ¬ R ∈ V → x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y = ∅
39 29 38 eqtr4d ⊢ ¬ R ∈ V → ∥ ˙ = x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y
40 27 39 pm2.61i ⊢ ∥ ˙ = x y | x ∈ B ∧ ∃ z ∈ B z · ˙ x = y