Metamath Proof Explorer


Theorem efi4p

Description: Separate out the first four terms of the infinite series expansion of the exponential function. (Contributed by Paul Chapman, 19-Jan-2008) (Revised by Mario Carneiro, 30-Apr-2014)

Ref Expression
Hypothesis efi4p.1 ⊢ F = n ∈ ℕ 0 ⟼ i ⁢ A n n !
Assertion efi4p ⊢ A ∈ ℂ → e i ⁢ A = 1 − A 2 2 + i ⁢ A − A 3 6 + ∑ k ∈ ℤ ≥ 4 F ⁡ k

Proof

Step Hyp Ref Expression
1 efi4p.1 ⊢ F = n ∈ ℕ 0 ⟼ i ⁢ A n n !
2 ax-icn ⊢ i ∈ ℂ
3 mulcl ⊢ i ∈ ℂ ∧ A ∈ ℂ → i ⁢ A ∈ ℂ
4 2 3 mpan ⊢ A ∈ ℂ → i ⁢ A ∈ ℂ
5 1 ef4p ⊢ i ⁢ A ∈ ℂ → e i ⁢ A = 1 + i ⁢ A + i ⁢ A 2 2 + i ⁢ A 3 6 + ∑ k ∈ ℤ ≥ 4 F ⁡ k
6 4 5 syl ⊢ A ∈ ℂ → e i ⁢ A = 1 + i ⁢ A + i ⁢ A 2 2 + i ⁢ A 3 6 + ∑ k ∈ ℤ ≥ 4 F ⁡ k
7 ax-1cn ⊢ 1 ∈ ℂ
8 addcl ⊢ 1 ∈ ℂ ∧ i ⁢ A ∈ ℂ → 1 + i ⁢ A ∈ ℂ
9 7 4 8 sylancr ⊢ A ∈ ℂ → 1 + i ⁢ A ∈ ℂ
10 4 sqcld ⊢ A ∈ ℂ → i ⁢ A 2 ∈ ℂ
11 10 halfcld ⊢ A ∈ ℂ → i ⁢ A 2 2 ∈ ℂ
12 3nn0 ⊢ 3 ∈ ℕ 0
13 expcl ⊢ i ⁢ A ∈ ℂ ∧ 3 ∈ ℕ 0 → i ⁢ A 3 ∈ ℂ
14 4 12 13 sylancl ⊢ A ∈ ℂ → i ⁢ A 3 ∈ ℂ
15 6cn ⊢ 6 ∈ ℂ
16 6re ⊢ 6 ∈ ℝ
17 6pos ⊢ 0 < 6
18 16 17 gt0ne0ii ⊢ 6 ≠ 0
19 divcl ⊢ i ⁢ A 3 ∈ ℂ ∧ 6 ∈ ℂ ∧ 6 ≠ 0 → i ⁢ A 3 6 ∈ ℂ
20 15 18 19 mp3an23 ⊢ i ⁢ A 3 ∈ ℂ → i ⁢ A 3 6 ∈ ℂ
21 14 20 syl ⊢ A ∈ ℂ → i ⁢ A 3 6 ∈ ℂ
22 9 11 21 addassd ⊢ A ∈ ℂ → 1 + i ⁢ A + i ⁢ A 2 2 + i ⁢ A 3 6 = 1 + i ⁢ A + i ⁢ A 2 2 + i ⁢ A 3 6
23 7 a1i ⊢ A ∈ ℂ → 1 ∈ ℂ
24 23 4 11 21 add4d ⊢ A ∈ ℂ → 1 + i ⁢ A + i ⁢ A 2 2 + i ⁢ A 3 6 = 1 + i ⁢ A 2 2 + i ⁢ A + i ⁢ A 3 6
25 2nn0 ⊢ 2 ∈ ℕ 0
26 mulexp ⊢ i ∈ ℂ ∧ A ∈ ℂ ∧ 2 ∈ ℕ 0 → i ⁢ A 2 = i 2 ⁢ A 2
27 2 25 26 mp3an13 ⊢ A ∈ ℂ → i ⁢ A 2 = i 2 ⁢ A 2
28 i2 ⊢ i 2 = − 1
29 28 oveq1i ⊢ i 2 ⁢ A 2 = -1 ⁢ A 2
30 29 a1i ⊢ A ∈ ℂ → i 2 ⁢ A 2 = -1 ⁢ A 2
31 sqcl ⊢ A ∈ ℂ → A 2 ∈ ℂ
32 31 mulm1d ⊢ A ∈ ℂ → -1 ⁢ A 2 = − A 2
33 27 30 32 3eqtrd ⊢ A ∈ ℂ → i ⁢ A 2 = − A 2
34 33 oveq1d ⊢ A ∈ ℂ → i ⁢ A 2 2 = − A 2 2
35 2cn ⊢ 2 ∈ ℂ
36 2ne0 ⊢ 2 ≠ 0
37 divneg ⊢ A 2 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → − A 2 2 = − A 2 2
38 35 36 37 mp3an23 ⊢ A 2 ∈ ℂ → − A 2 2 = − A 2 2
39 31 38 syl ⊢ A ∈ ℂ → − A 2 2 = − A 2 2
40 34 39 eqtr4d ⊢ A ∈ ℂ → i ⁢ A 2 2 = − A 2 2
41 40 oveq2d ⊢ A ∈ ℂ → 1 + i ⁢ A 2 2 = 1 + − A 2 2
42 31 halfcld ⊢ A ∈ ℂ → A 2 2 ∈ ℂ
43 negsub ⊢ 1 ∈ ℂ ∧ A 2 2 ∈ ℂ → 1 + − A 2 2 = 1 − A 2 2
44 7 42 43 sylancr ⊢ A ∈ ℂ → 1 + − A 2 2 = 1 − A 2 2
45 41 44 eqtrd ⊢ A ∈ ℂ → 1 + i ⁢ A 2 2 = 1 − A 2 2
46 mulexp ⊢ i ∈ ℂ ∧ A ∈ ℂ ∧ 3 ∈ ℕ 0 → i ⁢ A 3 = i 3 ⁢ A 3
47 2 12 46 mp3an13 ⊢ A ∈ ℂ → i ⁢ A 3 = i 3 ⁢ A 3
48 i3 ⊢ i 3 = − i
49 48 oveq1i ⊢ i 3 ⁢ A 3 = − i ⁢ A 3
50 47 49 eqtrdi ⊢ A ∈ ℂ → i ⁢ A 3 = − i ⁢ A 3
51 50 oveq1d ⊢ A ∈ ℂ → i ⁢ A 3 6 = − i ⁢ A 3 6
52 expcl ⊢ A ∈ ℂ ∧ 3 ∈ ℕ 0 → A 3 ∈ ℂ
53 12 52 mpan2 ⊢ A ∈ ℂ → A 3 ∈ ℂ
54 negicn ⊢ − i ∈ ℂ
55 15 18 pm3.2i ⊢ 6 ∈ ℂ ∧ 6 ≠ 0
56 divass ⊢ − i ∈ ℂ ∧ A 3 ∈ ℂ ∧ 6 ∈ ℂ ∧ 6 ≠ 0 → − i ⁢ A 3 6 = − i ⁢ A 3 6
57 54 55 56 mp3an13 ⊢ A 3 ∈ ℂ → − i ⁢ A 3 6 = − i ⁢ A 3 6
58 53 57 syl ⊢ A ∈ ℂ → − i ⁢ A 3 6 = − i ⁢ A 3 6
59 divcl ⊢ A 3 ∈ ℂ ∧ 6 ∈ ℂ ∧ 6 ≠ 0 → A 3 6 ∈ ℂ
60 15 18 59 mp3an23 ⊢ A 3 ∈ ℂ → A 3 6 ∈ ℂ
61 53 60 syl ⊢ A ∈ ℂ → A 3 6 ∈ ℂ
62 mulneg12 ⊢ i ∈ ℂ ∧ A 3 6 ∈ ℂ → − i ⁢ A 3 6 = i ⁢ − A 3 6
63 2 61 62 sylancr ⊢ A ∈ ℂ → − i ⁢ A 3 6 = i ⁢ − A 3 6
64 51 58 63 3eqtrd ⊢ A ∈ ℂ → i ⁢ A 3 6 = i ⁢ − A 3 6
65 64 oveq2d ⊢ A ∈ ℂ → i ⁢ A + i ⁢ A 3 6 = i ⁢ A + i ⁢ − A 3 6
66 61 negcld ⊢ A ∈ ℂ → − A 3 6 ∈ ℂ
67 adddi ⊢ i ∈ ℂ ∧ A ∈ ℂ ∧ − A 3 6 ∈ ℂ → i ⁢ A + − A 3 6 = i ⁢ A + i ⁢ − A 3 6
68 2 67 mp3an1 ⊢ A ∈ ℂ ∧ − A 3 6 ∈ ℂ → i ⁢ A + − A 3 6 = i ⁢ A + i ⁢ − A 3 6
69 66 68 mpdan ⊢ A ∈ ℂ → i ⁢ A + − A 3 6 = i ⁢ A + i ⁢ − A 3 6
70 negsub ⊢ A ∈ ℂ ∧ A 3 6 ∈ ℂ → A + − A 3 6 = A − A 3 6
71 61 70 mpdan ⊢ A ∈ ℂ → A + − A 3 6 = A − A 3 6
72 71 oveq2d ⊢ A ∈ ℂ → i ⁢ A + − A 3 6 = i ⁢ A − A 3 6
73 65 69 72 3eqtr2d ⊢ A ∈ ℂ → i ⁢ A + i ⁢ A 3 6 = i ⁢ A − A 3 6
74 45 73 oveq12d ⊢ A ∈ ℂ → 1 + i ⁢ A 2 2 + i ⁢ A + i ⁢ A 3 6 = 1 - A 2 2 + i ⁢ A − A 3 6
75 22 24 74 3eqtrd ⊢ A ∈ ℂ → 1 + i ⁢ A + i ⁢ A 2 2 + i ⁢ A 3 6 = 1 - A 2 2 + i ⁢ A − A 3 6
76 75 oveq1d ⊢ A ∈ ℂ → 1 + i ⁢ A + i ⁢ A 2 2 + i ⁢ A 3 6 + ∑ k ∈ ℤ ≥ 4 F ⁡ k = 1 − A 2 2 + i ⁢ A − A 3 6 + ∑ k ∈ ℤ ≥ 4 F ⁡ k
77 6 76 eqtrd ⊢ A ∈ ℂ → e i ⁢ A = 1 − A 2 2 + i ⁢ A − A 3 6 + ∑ k ∈ ℤ ≥ 4 F ⁡ k