Metamath Proof Explorer


Theorem el2xptp0

Description: A member of a nested Cartesian product is an ordered triple. (Contributed by Alexander van der Vekens, 15-Feb-2018)

Ref Expression
Assertion el2xptp0 ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z ↔ A = X Y Z

Proof

Step Hyp Ref Expression
1 xp1st ⊢ A ∈ U × V × W → 1 st ⁡ A ∈ U × V
2 1 ad2antrl ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → 1 st ⁡ A ∈ U × V
3 3simpa ⊢ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y
4 3 adantl ⊢ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y
5 4 adantl ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y
6 eqopi ⊢ 1 st ⁡ A ∈ U × V ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y → 1 st ⁡ A = X Y
7 2 5 6 syl2anc ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → 1 st ⁡ A = X Y
8 simprr3 ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → 2 nd ⁡ A = Z
9 7 8 jca ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → 1 st ⁡ A = X Y ∧ 2 nd ⁡ A = Z
10 df-ot ⊢ X Y Z = X Y Z
11 10 eqeq2i ⊢ A = X Y Z ↔ A = X Y Z
12 eqop ⊢ A ∈ U × V × W → A = X Y Z ↔ 1 st ⁡ A = X Y ∧ 2 nd ⁡ A = Z
13 11 12 bitrid ⊢ A ∈ U × V × W → A = X Y Z ↔ 1 st ⁡ A = X Y ∧ 2 nd ⁡ A = Z
14 13 ad2antrl ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → A = X Y Z ↔ 1 st ⁡ A = X Y ∧ 2 nd ⁡ A = Z
15 9 14 mpbird ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z → A = X Y Z
16 opelxpi ⊢ X ∈ U ∧ Y ∈ V → X Y ∈ U × V
17 16 3adant3 ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → X Y ∈ U × V
18 simp3 ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → Z ∈ W
19 17 18 opelxpd ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → X Y Z ∈ U × V × W
20 10 19 eqeltrid ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → X Y Z ∈ U × V × W
21 20 adantr ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → X Y Z ∈ U × V × W
22 eleq1 ⊢ A = X Y Z → A ∈ U × V × W ↔ X Y Z ∈ U × V × W
23 22 adantl ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → A ∈ U × V × W ↔ X Y Z ∈ U × V × W
24 21 23 mpbird ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → A ∈ U × V × W
25 2fveq3 ⊢ A = X Y Z → 1 st ⁡ 1 st ⁡ A = 1 st ⁡ 1 st ⁡ X Y Z
26 ot1stg ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → 1 st ⁡ 1 st ⁡ X Y Z = X
27 25 26 sylan9eqr ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → 1 st ⁡ 1 st ⁡ A = X
28 2fveq3 ⊢ A = X Y Z → 2 nd ⁡ 1 st ⁡ A = 2 nd ⁡ 1 st ⁡ X Y Z
29 ot2ndg ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → 2 nd ⁡ 1 st ⁡ X Y Z = Y
30 28 29 sylan9eqr ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → 2 nd ⁡ 1 st ⁡ A = Y
31 fveq2 ⊢ A = X Y Z → 2 nd ⁡ A = 2 nd ⁡ X Y Z
32 ot3rdg ⊢ Z ∈ W → 2 nd ⁡ X Y Z = Z
33 32 3ad2ant3 ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → 2 nd ⁡ X Y Z = Z
34 31 33 sylan9eqr ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → 2 nd ⁡ A = Z
35 27 30 34 3jca ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z
36 24 35 jca ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W ∧ A = X Y Z → A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z
37 15 36 impbida ⊢ X ∈ U ∧ Y ∈ V ∧ Z ∈ W → A ∈ U × V × W ∧ 1 st ⁡ 1 st ⁡ A = X ∧ 2 nd ⁡ 1 st ⁡ A = Y ∧ 2 nd ⁡ A = Z ↔ A = X Y Z