Metamath Proof Explorer


Theorem fsumsplit1

Description: Separate out a term in a finite sum. (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypotheses fsumsplit1.kph ⊢ Ⅎ k φ
fsumsplit1.kd ⊢ Ⅎ _ k D
fsumsplit1.a ⊢ φ → A ∈ Fin
fsumsplit1.b ⊢ φ ∧ k ∈ A → B ∈ ℂ
fsumsplit1.c ⊢ φ → C ∈ A
fsumsplit1.bd ⊢ k = C → B = D
Assertion fsumsplit1 ⊢ φ → ∑ k ∈ A B = D + ∑ k ∈ A ∖ C B

Proof

Step Hyp Ref Expression
1 fsumsplit1.kph ⊢ Ⅎ k φ
2 fsumsplit1.kd ⊢ Ⅎ _ k D
3 fsumsplit1.a ⊢ φ → A ∈ Fin
4 fsumsplit1.b ⊢ φ ∧ k ∈ A → B ∈ ℂ
5 fsumsplit1.c ⊢ φ → C ∈ A
6 fsumsplit1.bd ⊢ k = C → B = D
7 uncom ⊢ A ∖ C ∪ C = C ∪ A ∖ C
8 7 a1i ⊢ φ → A ∖ C ∪ C = C ∪ A ∖ C
9 5 snssd ⊢ φ → C ⊆ A
10 undif ⊢ C ⊆ A ↔ C ∪ A ∖ C = A
11 9 10 sylib ⊢ φ → C ∪ A ∖ C = A
12 eqidd ⊢ φ → A = A
13 8 11 12 3eqtrrd ⊢ φ → A = A ∖ C ∪ C
14 13 sumeq1d ⊢ φ → ∑ k ∈ A B = ∑ k ∈ A ∖ C ∪ C B
15 diffi ⊢ A ∈ Fin → A ∖ C ∈ Fin
16 3 15 syl ⊢ φ → A ∖ C ∈ Fin
17 neldifsnd ⊢ φ → ¬ C ∈ A ∖ C
18 simpl ⊢ φ ∧ k ∈ A ∖ C → φ
19 eldifi ⊢ k ∈ A ∖ C → k ∈ A
20 19 adantl ⊢ φ ∧ k ∈ A ∖ C → k ∈ A
21 18 20 4 syl2anc ⊢ φ ∧ k ∈ A ∖ C → B ∈ ℂ
22 2 a1i ⊢ φ → Ⅎ _ k D
23 simpr ⊢ φ ∧ k = C → k = C
24 23 6 syl ⊢ φ ∧ k = C → B = D
25 1 22 5 24 csbiedf ⊢ φ → ⦋ C / k⦌ B = D
26 25 eqcomd ⊢ φ → D = ⦋ C / k⦌ B
27 5 ancli ⊢ φ → φ ∧ C ∈ A
28 nfcv ⊢ Ⅎ _ k C
29 nfv ⊢ Ⅎ k C ∈ A
30 1 29 nfan ⊢ Ⅎ k φ ∧ C ∈ A
31 28 nfcsb1 ⊢ Ⅎ _ k ⦋ C / k⦌ B
32 nfcv ⊢ Ⅎ _ k ℂ
33 31 32 nfel ⊢ Ⅎ k ⦋ C / k⦌ B ∈ ℂ
34 30 33 nfim ⊢ Ⅎ k φ ∧ C ∈ A → ⦋ C / k⦌ B ∈ ℂ
35 eleq1 ⊢ k = C → k ∈ A ↔ C ∈ A
36 35 anbi2d ⊢ k = C → φ ∧ k ∈ A ↔ φ ∧ C ∈ A
37 csbeq1a ⊢ k = C → B = ⦋ C / k⦌ B
38 37 eleq1d ⊢ k = C → B ∈ ℂ ↔ ⦋ C / k⦌ B ∈ ℂ
39 36 38 imbi12d ⊢ k = C → φ ∧ k ∈ A → B ∈ ℂ ↔ φ ∧ C ∈ A → ⦋ C / k⦌ B ∈ ℂ
40 28 34 39 4 vtoclgf ⊢ C ∈ A → φ ∧ C ∈ A → ⦋ C / k⦌ B ∈ ℂ
41 5 27 40 sylc ⊢ φ → ⦋ C / k⦌ B ∈ ℂ
42 26 41 eqeltrd ⊢ φ → D ∈ ℂ
43 1 2 16 5 17 21 6 42 fsumsplitsn ⊢ φ → ∑ k ∈ A ∖ C ∪ C B = ∑ k ∈ A ∖ C B + D
44 1 16 21 fsumclf ⊢ φ → ∑ k ∈ A ∖ C B ∈ ℂ
45 44 42 addcomd ⊢ φ → ∑ k ∈ A ∖ C B + D = D + ∑ k ∈ A ∖ C B
46 14 43 45 3eqtrd ⊢ φ → ∑ k ∈ A B = D + ∑ k ∈ A ∖ C B