Metamath Proof Explorer


Theorem hdmap1vallem

Description: Value of preliminary map from vectors to functionals in the closed kernel dual space. (Contributed by NM, 15-May-2015)

Ref Expression
Hypotheses hdmap1val.h ⊢ H = LHyp ⁡ K
hdmap1fval.u ⊢ U = DVecH ⁡ K ⁡ W
hdmap1fval.v ⊢ V = Base U
hdmap1fval.s ⊢ - ˙ = - U
hdmap1fval.o ⊢ 0 ˙ = 0 U
hdmap1fval.n ⊢ N = LSpan ⁡ U
hdmap1fval.c ⊢ C = LCDual ⁡ K ⁡ W
hdmap1fval.d ⊢ D = Base C
hdmap1fval.r ⊢ R = - C
hdmap1fval.q ⊢ Q = 0 C
hdmap1fval.j ⊢ J = LSpan ⁡ C
hdmap1fval.m ⊢ M = mapd ⁡ K ⁡ W
hdmap1fval.i ⊢ I = HDMap1 ⁡ K ⁡ W
hdmap1fval.k ⊢ φ → K ∈ A ∧ W ∈ H
hdmap1val.t ⊢ φ → T ∈ V × D × V
Assertion hdmap1vallem ⊢ φ → I ⁡ T = if 2 nd ⁡ T = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h

Proof

Step Hyp Ref Expression
1 hdmap1val.h ⊢ H = LHyp ⁡ K
2 hdmap1fval.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmap1fval.v ⊢ V = Base U
4 hdmap1fval.s ⊢ - ˙ = - U
5 hdmap1fval.o ⊢ 0 ˙ = 0 U
6 hdmap1fval.n ⊢ N = LSpan ⁡ U
7 hdmap1fval.c ⊢ C = LCDual ⁡ K ⁡ W
8 hdmap1fval.d ⊢ D = Base C
9 hdmap1fval.r ⊢ R = - C
10 hdmap1fval.q ⊢ Q = 0 C
11 hdmap1fval.j ⊢ J = LSpan ⁡ C
12 hdmap1fval.m ⊢ M = mapd ⁡ K ⁡ W
13 hdmap1fval.i ⊢ I = HDMap1 ⁡ K ⁡ W
14 hdmap1fval.k ⊢ φ → K ∈ A ∧ W ∈ H
15 hdmap1val.t ⊢ φ → T ∈ V × D × V
16 1 2 3 4 5 6 7 8 9 10 11 12 13 14 hdmap1fval ⊢ φ → I = x ∈ V × D × V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
17 16 fveq1d ⊢ φ → I ⁡ T = x ∈ V × D × V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h ⁡ T
18 10 fvexi ⊢ Q ∈ V
19 riotaex ⊢ ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h ∈ V
20 18 19 ifex ⊢ if 2 nd ⁡ T = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h ∈ V
21 fveqeq2 ⊢ x = T → 2 nd ⁡ x = 0 ˙ ↔ 2 nd ⁡ T = 0 ˙
22 fveq2 ⊢ x = T → 2 nd ⁡ x = 2 nd ⁡ T
23 22 sneqd ⊢ x = T → 2 nd ⁡ x = 2 nd ⁡ T
24 23 fveq2d ⊢ x = T → N ⁡ 2 nd ⁡ x = N ⁡ 2 nd ⁡ T
25 24 fveqeq2d ⊢ x = T → M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ↔ M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h
26 2fveq3 ⊢ x = T → 1 st ⁡ 1 st ⁡ x = 1 st ⁡ 1 st ⁡ T
27 26 22 oveq12d ⊢ x = T → 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T
28 27 sneqd ⊢ x = T → 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T
29 28 fveq2d ⊢ x = T → N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T
30 29 fveq2d ⊢ x = T → M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T
31 2fveq3 ⊢ x = T → 2 nd ⁡ 1 st ⁡ x = 2 nd ⁡ 1 st ⁡ T
32 31 oveq1d ⊢ x = T → 2 nd ⁡ 1 st ⁡ x R h = 2 nd ⁡ 1 st ⁡ T R h
33 32 sneqd ⊢ x = T → 2 nd ⁡ 1 st ⁡ x R h = 2 nd ⁡ 1 st ⁡ T R h
34 33 fveq2d ⊢ x = T → J ⁡ 2 nd ⁡ 1 st ⁡ x R h = J ⁡ 2 nd ⁡ 1 st ⁡ T R h
35 30 34 eqeq12d ⊢ x = T → M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h ↔ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h
36 25 35 anbi12d ⊢ x = T → M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h ↔ M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h
37 36 riotabidv ⊢ x = T → ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h = ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h
38 21 37 ifbieq2d ⊢ x = T → if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h = if 2 nd ⁡ T = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h
39 eqid ⊢ x ∈ V × D × V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h = x ∈ V × D × V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
40 38 39 fvmptg ⊢ T ∈ V × D × V ∧ if 2 nd ⁡ T = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h ∈ V → x ∈ V × D × V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h ⁡ T = if 2 nd ⁡ T = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h
41 15 20 40 sylancl ⊢ φ → x ∈ V × D × V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h ⁡ T = if 2 nd ⁡ T = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h
42 17 41 eqtrd ⊢ φ → I ⁡ T = if 2 nd ⁡ T = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ T = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ T - ˙ 2 nd ⁡ T = J ⁡ 2 nd ⁡ 1 st ⁡ T R h