Metamath Proof Explorer


Theorem ioc0

Description: An empty open interval of extended reals. (Contributed by FL, 30-May-2014)

Ref Expression
Assertion ioc0 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A B = ∅ ↔ B ≤ A

Proof

Step Hyp Ref Expression
1 iocval ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A B = x ∈ ℝ * | A < x ∧ x ≤ B
2 1 eqeq1d ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A B = ∅ ↔ x ∈ ℝ * | A < x ∧ x ≤ B = ∅
3 df-ne ⊢ x ∈ ℝ * | A < x ∧ x ≤ B ≠ ∅ ↔ ¬ x ∈ ℝ * | A < x ∧ x ≤ B = ∅
4 rabn0 ⊢ x ∈ ℝ * | A < x ∧ x ≤ B ≠ ∅ ↔ ∃ x ∈ ℝ * A < x ∧ x ≤ B
5 3 4 bitr3i ⊢ ¬ x ∈ ℝ * | A < x ∧ x ≤ B = ∅ ↔ ∃ x ∈ ℝ * A < x ∧ x ≤ B
6 xrltletr ⊢ A ∈ ℝ * ∧ x ∈ ℝ * ∧ B ∈ ℝ * → A < x ∧ x ≤ B → A < B
7 6 3com23 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ x ∈ ℝ * → A < x ∧ x ≤ B → A < B
8 7 3expa ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ x ∈ ℝ * → A < x ∧ x ≤ B → A < B
9 8 rexlimdva ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → ∃ x ∈ ℝ * A < x ∧ x ≤ B → A < B
10 qbtwnxr ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → ∃ x ∈ ℚ A < x ∧ x < B
11 qre ⊢ x ∈ ℚ → x ∈ ℝ
12 11 rexrd ⊢ x ∈ ℚ → x ∈ ℝ *
13 12 a1i ⊢ x ∈ ℝ * ∧ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → x ∈ ℚ → x ∈ ℝ *
14 xrltle ⊢ x ∈ ℝ * ∧ B ∈ ℝ * → x < B → x ≤ B
15 14 3ad2antr2 ⊢ x ∈ ℝ * ∧ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → x < B → x ≤ B
16 15 anim2d ⊢ x ∈ ℝ * ∧ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → A < x ∧ x < B → A < x ∧ x ≤ B
17 13 16 anim12d ⊢ x ∈ ℝ * ∧ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → x ∈ ℚ ∧ A < x ∧ x < B → x ∈ ℝ * ∧ A < x ∧ x ≤ B
18 17 ex ⊢ x ∈ ℝ * → A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → x ∈ ℚ ∧ A < x ∧ x < B → x ∈ ℝ * ∧ A < x ∧ x ≤ B
19 12 18 syl ⊢ x ∈ ℚ → A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → x ∈ ℚ ∧ A < x ∧ x < B → x ∈ ℝ * ∧ A < x ∧ x ≤ B
20 19 adantr ⊢ x ∈ ℚ ∧ A < x ∧ x < B → A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → x ∈ ℚ ∧ A < x ∧ x < B → x ∈ ℝ * ∧ A < x ∧ x ≤ B
21 20 pm2.43b ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → x ∈ ℚ ∧ A < x ∧ x < B → x ∈ ℝ * ∧ A < x ∧ x ≤ B
22 21 reximdv2 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → ∃ x ∈ ℚ A < x ∧ x < B → ∃ x ∈ ℝ * A < x ∧ x ≤ B
23 10 22 mpd ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A < B → ∃ x ∈ ℝ * A < x ∧ x ≤ B
24 23 3expia ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A < B → ∃ x ∈ ℝ * A < x ∧ x ≤ B
25 9 24 impbid ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → ∃ x ∈ ℝ * A < x ∧ x ≤ B ↔ A < B
26 5 25 bitrid ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → ¬ x ∈ ℝ * | A < x ∧ x ≤ B = ∅ ↔ A < B
27 xrltnle ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A < B ↔ ¬ B ≤ A
28 26 27 bitrd ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → ¬ x ∈ ℝ * | A < x ∧ x ≤ B = ∅ ↔ ¬ B ≤ A
29 28 con4bid ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → x ∈ ℝ * | A < x ∧ x ≤ B = ∅ ↔ B ≤ A
30 2 29 bitrd ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A B = ∅ ↔ B ≤ A