Metamath Proof Explorer


Theorem itcovalt2lem2lem2

Description: Lemma 2 for itcovalt2lem2 . (Contributed by AV, 7-May-2024)

Ref Expression
Assertion itcovalt2lem2lem2 ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y − C + C = N + C ⁢ 2 Y + 1 − C

Proof

Step Hyp Ref Expression
1 2cnd ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ∈ ℂ
2 simpr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → N ∈ ℕ 0
3 simpr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 → C ∈ ℕ 0
4 3 adantr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → C ∈ ℕ 0
5 2 4 nn0addcld ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → N + C ∈ ℕ 0
6 5 nn0cnd ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → N + C ∈ ℂ
7 2nn0 ⊢ 2 ∈ ℕ 0
8 7 a1i ⊢ Y ∈ ℕ 0 → 2 ∈ ℕ 0
9 id ⊢ Y ∈ ℕ 0 → Y ∈ ℕ 0
10 8 9 nn0expcld ⊢ Y ∈ ℕ 0 → 2 Y ∈ ℕ 0
11 10 nn0cnd ⊢ Y ∈ ℕ 0 → 2 Y ∈ ℂ
12 11 ad2antrr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 Y ∈ ℂ
13 6 12 mulcld ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → N + C ⁢ 2 Y ∈ ℂ
14 nn0cn ⊢ C ∈ ℕ 0 → C ∈ ℂ
15 14 ad2antlr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → C ∈ ℂ
16 1 13 15 subdid ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y − C = 2 ⁢ N + C ⁢ 2 Y − 2 ⁢ C
17 16 oveq1d ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y − C + C = 2 ⁢ N + C ⁢ 2 Y - 2 ⁢ C + C
18 7 a1i ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ∈ ℕ 0
19 10 ad2antrr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 Y ∈ ℕ 0
20 5 19 nn0mulcld ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → N + C ⁢ 2 Y ∈ ℕ 0
21 18 20 nn0mulcld ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y ∈ ℕ 0
22 21 nn0cnd ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y ∈ ℂ
23 7 a1i ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 → 2 ∈ ℕ 0
24 23 3 nn0mulcld ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 → 2 ⁢ C ∈ ℕ 0
25 24 adantr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ C ∈ ℕ 0
26 25 nn0cnd ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ C ∈ ℂ
27 4 nn0cnd ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → C ∈ ℂ
28 22 26 27 subsubd ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y − 2 ⁢ C − C = 2 ⁢ N + C ⁢ 2 Y - 2 ⁢ C + C
29 1 6 12 mul12d ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y = N + C ⁢ 2 ⁢ 2 Y
30 2cnd ⊢ Y ∈ ℕ 0 → 2 ∈ ℂ
31 30 11 mulcomd ⊢ Y ∈ ℕ 0 → 2 ⁢ 2 Y = 2 Y ⋅ 2
32 30 9 expp1d ⊢ Y ∈ ℕ 0 → 2 Y + 1 = 2 Y ⋅ 2
33 31 32 eqtr4d ⊢ Y ∈ ℕ 0 → 2 ⁢ 2 Y = 2 Y + 1
34 33 ad2antrr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ 2 Y = 2 Y + 1
35 34 oveq2d ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → N + C ⁢ 2 ⁢ 2 Y = N + C ⁢ 2 Y + 1
36 29 35 eqtrd ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y = N + C ⁢ 2 Y + 1
37 2txmxeqx ⊢ C ∈ ℂ → 2 ⁢ C − C = C
38 14 37 syl ⊢ C ∈ ℕ 0 → 2 ⁢ C − C = C
39 38 ad2antlr ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ C − C = C
40 36 39 oveq12d ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y − 2 ⁢ C − C = N + C ⁢ 2 Y + 1 − C
41 17 28 40 3eqtr2d ⊢ Y ∈ ℕ 0 ∧ C ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 ⁢ N + C ⁢ 2 Y − C + C = N + C ⁢ 2 Y + 1 − C