Metamath Proof Explorer


Theorem lcmineqlem17

Description: Inequality of 2^{2n}. (Contributed by metakunt, 29-Apr-2024)

Ref Expression
Hypothesis lcmineqlem17.1 ⊢ φ → N ∈ ℕ 0
Assertion lcmineqlem17 ⊢ φ → 2 2 ⋅ N ≤ 2 ⋅ N + 1 ⁢ ( 2 ⋅ N N)

Proof

Step Hyp Ref Expression
1 lcmineqlem17.1 ⊢ φ → N ∈ ℕ 0
2 2nn0 ⊢ 2 ∈ ℕ 0
3 2 a1i ⊢ φ → 2 ∈ ℕ 0
4 3 1 nn0mulcld ⊢ φ → 2 ⋅ N ∈ ℕ 0
5 binom11 ⊢ 2 ⋅ N ∈ ℕ 0 → 2 2 ⋅ N = ∑ k = 0 2 ⋅ N ( 2 ⋅ N k)
6 4 5 syl ⊢ φ → 2 2 ⋅ N = ∑ k = 0 2 ⋅ N ( 2 ⋅ N k)
7 fzfid ⊢ φ → 0 … 2 ⋅ N ∈ Fin
8 4 adantr ⊢ φ ∧ k ∈ 0 … 2 ⋅ N → 2 ⋅ N ∈ ℕ 0
9 elfzelz ⊢ k ∈ 0 … 2 ⋅ N → k ∈ ℤ
10 9 adantl ⊢ φ ∧ k ∈ 0 … 2 ⋅ N → k ∈ ℤ
11 8 10 jca ⊢ φ ∧ k ∈ 0 … 2 ⋅ N → 2 ⋅ N ∈ ℕ 0 ∧ k ∈ ℤ
12 bccl ⊢ 2 ⋅ N ∈ ℕ 0 ∧ k ∈ ℤ → ( 2 ⋅ N k) ∈ ℕ 0
13 11 12 syl ⊢ φ ∧ k ∈ 0 … 2 ⋅ N → ( 2 ⋅ N k) ∈ ℕ 0
14 13 nn0red ⊢ φ ∧ k ∈ 0 … 2 ⋅ N → ( 2 ⋅ N k) ∈ ℝ
15 1 nn0zd ⊢ φ → N ∈ ℤ
16 bccl ⊢ 2 ⋅ N ∈ ℕ 0 ∧ N ∈ ℤ → ( 2 ⋅ N N) ∈ ℕ 0
17 4 15 16 syl2anc ⊢ φ → ( 2 ⋅ N N) ∈ ℕ 0
18 17 nn0red ⊢ φ → ( 2 ⋅ N N) ∈ ℝ
19 18 adantr ⊢ φ ∧ k ∈ 0 … 2 ⋅ N → ( 2 ⋅ N N) ∈ ℝ
20 bcmax ⊢ N ∈ ℕ 0 ∧ k ∈ ℤ → ( 2 ⋅ N k) ≤ ( 2 ⋅ N N)
21 1 9 20 syl2an ⊢ φ ∧ k ∈ 0 … 2 ⋅ N → ( 2 ⋅ N k) ≤ ( 2 ⋅ N N)
22 7 14 19 21 fsumle ⊢ φ → ∑ k = 0 2 ⋅ N ( 2 ⋅ N k) ≤ ∑ k = 0 2 ⋅ N ( 2 ⋅ N N)
23 6 22 eqbrtrd ⊢ φ → 2 2 ⋅ N ≤ ∑ k = 0 2 ⋅ N ( 2 ⋅ N N)
24 17 nn0cnd ⊢ φ → ( 2 ⋅ N N) ∈ ℂ
25 fsumconst ⊢ 0 … 2 ⋅ N ∈ Fin ∧ ( 2 ⋅ N N) ∈ ℂ → ∑ k = 0 2 ⋅ N ( 2 ⋅ N N) = 0 … 2 ⋅ N ⁢ ( 2 ⋅ N N)
26 7 24 25 syl2anc ⊢ φ → ∑ k = 0 2 ⋅ N ( 2 ⋅ N N) = 0 … 2 ⋅ N ⁢ ( 2 ⋅ N N)
27 hashfz0 ⊢ 2 ⋅ N ∈ ℕ 0 → 0 … 2 ⋅ N = 2 ⋅ N + 1
28 4 27 syl ⊢ φ → 0 … 2 ⋅ N = 2 ⋅ N + 1
29 28 oveq1d ⊢ φ → 0 … 2 ⋅ N ⁢ ( 2 ⋅ N N) = 2 ⋅ N + 1 ⁢ ( 2 ⋅ N N)
30 26 29 eqtrd ⊢ φ → ∑ k = 0 2 ⋅ N ( 2 ⋅ N N) = 2 ⋅ N + 1 ⁢ ( 2 ⋅ N N)
31 23 30 breqtrd ⊢ φ → 2 2 ⋅ N ≤ 2 ⋅ N + 1 ⁢ ( 2 ⋅ N N)