Metamath Proof Explorer


Theorem lmodvsinv2

Description: Multiplying a negated vector by a scalar. (Contributed by Stefan O'Rear, 5-Sep-2015)

Ref Expression
Hypotheses lmodvsinv2.b ⊢ B = Base W
lmodvsinv2.f ⊢ F = Scalar ⁡ W
lmodvsinv2.s ⊢ · ˙ = ⋅ W
lmodvsinv2.n ⊢ N = inv g ⁡ W
lmodvsinv2.k ⊢ K = Base F
Assertion lmodvsinv2 ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ N ⁡ X = N ⁡ R · ˙ X

Proof

Step Hyp Ref Expression
1 lmodvsinv2.b ⊢ B = Base W
2 lmodvsinv2.f ⊢ F = Scalar ⁡ W
3 lmodvsinv2.s ⊢ · ˙ = ⋅ W
4 lmodvsinv2.n ⊢ N = inv g ⁡ W
5 lmodvsinv2.k ⊢ K = Base F
6 simp1 ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → W ∈ LMod
7 lmodgrp ⊢ W ∈ LMod → W ∈ Grp
8 6 7 syl ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → W ∈ Grp
9 simp3 ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → X ∈ B
10 eqid ⊢ + W = + W
11 eqid ⊢ 0 W = 0 W
12 1 10 11 4 grprinv ⊢ W ∈ Grp ∧ X ∈ B → X + W N ⁡ X = 0 W
13 8 9 12 syl2anc ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → X + W N ⁡ X = 0 W
14 13 oveq2d ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ X + W N ⁡ X = R · ˙ 0 W
15 simp2 ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R ∈ K
16 1 4 grpinvcl ⊢ W ∈ Grp ∧ X ∈ B → N ⁡ X ∈ B
17 8 9 16 syl2anc ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → N ⁡ X ∈ B
18 1 10 2 3 5 lmodvsdi ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B ∧ N ⁡ X ∈ B → R · ˙ X + W N ⁡ X = R · ˙ X + W R · ˙ N ⁡ X
19 6 15 9 17 18 syl13anc ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ X + W N ⁡ X = R · ˙ X + W R · ˙ N ⁡ X
20 2 3 5 11 lmodvs0 ⊢ W ∈ LMod ∧ R ∈ K → R · ˙ 0 W = 0 W
21 6 15 20 syl2anc ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ 0 W = 0 W
22 14 19 21 3eqtr3d ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ X + W R · ˙ N ⁡ X = 0 W
23 1 2 3 5 lmodvscl ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ X ∈ B
24 1 2 3 5 lmodvscl ⊢ W ∈ LMod ∧ R ∈ K ∧ N ⁡ X ∈ B → R · ˙ N ⁡ X ∈ B
25 6 15 17 24 syl3anc ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ N ⁡ X ∈ B
26 1 10 11 4 grpinvid1 ⊢ W ∈ Grp ∧ R · ˙ X ∈ B ∧ R · ˙ N ⁡ X ∈ B → N ⁡ R · ˙ X = R · ˙ N ⁡ X ↔ R · ˙ X + W R · ˙ N ⁡ X = 0 W
27 8 23 25 26 syl3anc ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → N ⁡ R · ˙ X = R · ˙ N ⁡ X ↔ R · ˙ X + W R · ˙ N ⁡ X = 0 W
28 22 27 mpbird ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → N ⁡ R · ˙ X = R · ˙ N ⁡ X
29 28 eqcomd ⊢ W ∈ LMod ∧ R ∈ K ∧ X ∈ B → R · ˙ N ⁡ X = N ⁡ R · ˙ X