Metamath Proof Explorer


Theorem mapdpglem2

Description: Lemma for mapdpg . Baer p. 45, lines 1 and 2: "we have (F(x-y))* = Gt where t necessarily belongs to (Fx)*+(Fy)*." (We scope $d t ph locally to avoid clashes with later substitutions into ph .) (Contributed by NM, 15-Mar-2015)

Ref Expression
Hypotheses mapdpglem.h ⊢ H = LHyp ⁡ K
mapdpglem.m ⊢ M = mapd ⁡ K ⁡ W
mapdpglem.u ⊢ U = DVecH ⁡ K ⁡ W
mapdpglem.v ⊢ V = Base U
mapdpglem.s ⊢ - ˙ = - U
mapdpglem.n ⊢ N = LSpan ⁡ U
mapdpglem.c ⊢ C = LCDual ⁡ K ⁡ W
mapdpglem.k ⊢ φ → K ∈ HL ∧ W ∈ H
mapdpglem.x ⊢ φ → X ∈ V
mapdpglem.y ⊢ φ → Y ∈ V
mapdpglem1.p ⊢ ⊕ ˙ = LSSum ⁡ C
mapdpglem2.j ⊢ J = LSpan ⁡ C
Assertion mapdpglem2 ⊢ φ → ∃ t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y M ⁡ N ⁡ X - ˙ Y = J ⁡ t

Proof

Step Hyp Ref Expression
1 mapdpglem.h ⊢ H = LHyp ⁡ K
2 mapdpglem.m ⊢ M = mapd ⁡ K ⁡ W
3 mapdpglem.u ⊢ U = DVecH ⁡ K ⁡ W
4 mapdpglem.v ⊢ V = Base U
5 mapdpglem.s ⊢ - ˙ = - U
6 mapdpglem.n ⊢ N = LSpan ⁡ U
7 mapdpglem.c ⊢ C = LCDual ⁡ K ⁡ W
8 mapdpglem.k ⊢ φ → K ∈ HL ∧ W ∈ H
9 mapdpglem.x ⊢ φ → X ∈ V
10 mapdpglem.y ⊢ φ → Y ∈ V
11 mapdpglem1.p ⊢ ⊕ ˙ = LSSum ⁡ C
12 mapdpglem2.j ⊢ J = LSpan ⁡ C
13 eqid ⊢ Base C = Base C
14 1 3 8 dvhlmod ⊢ φ → U ∈ LMod
15 4 5 lmodvsubcl ⊢ U ∈ LMod ∧ X ∈ V ∧ Y ∈ V → X - ˙ Y ∈ V
16 14 9 10 15 syl3anc ⊢ φ → X - ˙ Y ∈ V
17 1 2 3 4 6 7 13 12 8 16 mapdspex ⊢ φ → ∃ t ∈ Base C M ⁡ N ⁡ X - ˙ Y = J ⁡ t
18 1 7 8 lcdlmod ⊢ φ → C ∈ LMod
19 13 12 lspsnid ⊢ C ∈ LMod ∧ t ∈ Base C → t ∈ J ⁡ t
20 18 19 sylan ⊢ φ ∧ t ∈ Base C → t ∈ J ⁡ t
21 20 adantrr ⊢ φ ∧ t ∈ Base C ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ t → t ∈ J ⁡ t
22 simprr ⊢ φ ∧ t ∈ Base C ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ t → M ⁡ N ⁡ X - ˙ Y = J ⁡ t
23 21 22 eleqtrrd ⊢ φ ∧ t ∈ Base C ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ t → t ∈ M ⁡ N ⁡ X - ˙ Y
24 17 23 22 reximssdv ⊢ φ → ∃ t ∈ M ⁡ N ⁡ X - ˙ Y M ⁡ N ⁡ X - ˙ Y = J ⁡ t
25 1 2 3 4 5 6 7 8 9 10 11 mapdpglem1 ⊢ φ → M ⁡ N ⁡ X - ˙ Y ⊆ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y
26 25 sseld ⊢ φ → t ∈ M ⁡ N ⁡ X - ˙ Y → t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y
27 26 anim1d ⊢ φ → t ∈ M ⁡ N ⁡ X - ˙ Y ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ t → t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ t
28 27 reximdv2 ⊢ φ → ∃ t ∈ M ⁡ N ⁡ X - ˙ Y M ⁡ N ⁡ X - ˙ Y = J ⁡ t → ∃ t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y M ⁡ N ⁡ X - ˙ Y = J ⁡ t
29 24 28 mpd ⊢ φ → ∃ t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y M ⁡ N ⁡ X - ˙ Y = J ⁡ t