Metamath Proof Explorer


Theorem pwsinvg

Description: Negation in a structure power. (Contributed by Mario Carneiro, 11-Jan-2015)

Ref Expression
Hypotheses pwsgrp.y ⊢ Y = R ↑ 𝑠 I
pwsinvg.b ⊢ B = Base Y
pwsinvg.m ⊢ M = inv g ⁡ R
pwsinvg.n ⊢ N = inv g ⁡ Y
Assertion pwsinvg ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → N ⁡ X = M ∘ X

Proof

Step Hyp Ref Expression
1 pwsgrp.y ⊢ Y = R ↑ 𝑠 I
2 pwsinvg.b ⊢ B = Base Y
3 pwsinvg.m ⊢ M = inv g ⁡ R
4 pwsinvg.n ⊢ N = inv g ⁡ Y
5 eqid ⊢ Scalar ⁡ R ⨉ 𝑠 I × R = Scalar ⁡ R ⨉ 𝑠 I × R
6 simp2 ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → I ∈ V
7 fvexd ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → Scalar ⁡ R ∈ V
8 simp1 ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → R ∈ Grp
9 fconst6g ⊢ R ∈ Grp → I × R : I ⟶ Grp
10 8 9 syl ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → I × R : I ⟶ Grp
11 eqid ⊢ Base Scalar ⁡ R ⨉ 𝑠 I × R = Base Scalar ⁡ R ⨉ 𝑠 I × R
12 eqid ⊢ inv g ⁡ Scalar ⁡ R ⨉ 𝑠 I × R = inv g ⁡ Scalar ⁡ R ⨉ 𝑠 I × R
13 simp3 ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → X ∈ B
14 eqid ⊢ Scalar ⁡ R = Scalar ⁡ R
15 1 14 pwsval ⊢ R ∈ Grp ∧ I ∈ V → Y = Scalar ⁡ R ⨉ 𝑠 I × R
16 15 3adant3 ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → Y = Scalar ⁡ R ⨉ 𝑠 I × R
17 16 fveq2d ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → Base Y = Base Scalar ⁡ R ⨉ 𝑠 I × R
18 2 17 eqtrid ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → B = Base Scalar ⁡ R ⨉ 𝑠 I × R
19 13 18 eleqtrd ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → X ∈ Base Scalar ⁡ R ⨉ 𝑠 I × R
20 5 6 7 10 11 12 19 prdsinvgd ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → inv g ⁡ Scalar ⁡ R ⨉ 𝑠 I × R ⁡ X = x ∈ I ⟼ inv g ⁡ I × R ⁡ x ⁡ X ⁡ x
21 fvconst2g ⊢ R ∈ Grp ∧ x ∈ I → I × R ⁡ x = R
22 8 21 sylan ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B ∧ x ∈ I → I × R ⁡ x = R
23 22 fveq2d ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B ∧ x ∈ I → inv g ⁡ I × R ⁡ x = inv g ⁡ R
24 23 3 eqtr4di ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B ∧ x ∈ I → inv g ⁡ I × R ⁡ x = M
25 24 fveq1d ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B ∧ x ∈ I → inv g ⁡ I × R ⁡ x ⁡ X ⁡ x = M ⁡ X ⁡ x
26 25 mpteq2dva ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → x ∈ I ⟼ inv g ⁡ I × R ⁡ x ⁡ X ⁡ x = x ∈ I ⟼ M ⁡ X ⁡ x
27 20 26 eqtrd ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → inv g ⁡ Scalar ⁡ R ⨉ 𝑠 I × R ⁡ X = x ∈ I ⟼ M ⁡ X ⁡ x
28 16 fveq2d ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → inv g ⁡ Y = inv g ⁡ Scalar ⁡ R ⨉ 𝑠 I × R
29 4 28 eqtrid ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → N = inv g ⁡ Scalar ⁡ R ⨉ 𝑠 I × R
30 29 fveq1d ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → N ⁡ X = inv g ⁡ Scalar ⁡ R ⨉ 𝑠 I × R ⁡ X
31 eqid ⊢ Base R = Base R
32 1 31 2 8 6 13 pwselbas ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → X : I ⟶ Base R
33 32 ffvelcdmda ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B ∧ x ∈ I → X ⁡ x ∈ Base R
34 32 feqmptd ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → X = x ∈ I ⟼ X ⁡ x
35 31 3 grpinvf ⊢ R ∈ Grp → M : Base R ⟶ Base R
36 8 35 syl ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → M : Base R ⟶ Base R
37 36 feqmptd ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → M = y ∈ Base R ⟼ M ⁡ y
38 fveq2 ⊢ y = X ⁡ x → M ⁡ y = M ⁡ X ⁡ x
39 33 34 37 38 fmptco ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → M ∘ X = x ∈ I ⟼ M ⁡ X ⁡ x
40 27 30 39 3eqtr4d ⊢ R ∈ Grp ∧ I ∈ V ∧ X ∈ B → N ⁡ X = M ∘ X