Metamath Proof Explorer


Theorem tendoid

Description: The identity value of a trace-preserving endomorphism. (Contributed by NM, 21-Jun-2013)

Ref Expression
Hypotheses tendoid.b ⊢ B = Base K
tendoid.h ⊢ H = LHyp ⁡ K
tendoid.e ⊢ E = TEndo ⁡ K ⁡ W
Assertion tendoid ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → S ⁡ I ↾ B = I ↾ B

Proof

Step Hyp Ref Expression
1 tendoid.b ⊢ B = Base K
2 tendoid.h ⊢ H = LHyp ⁡ K
3 tendoid.e ⊢ E = TEndo ⁡ K ⁡ W
4 eqid ⊢ LTrn ⁡ K ⁡ W = LTrn ⁡ K ⁡ W
5 1 2 4 idltrn ⊢ K ∈ HL ∧ W ∈ H → I ↾ B ∈ LTrn ⁡ K ⁡ W
6 5 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → I ↾ B ∈ LTrn ⁡ K ⁡ W
7 eqid ⊢ ≤ K = ≤ K
8 eqid ⊢ trL ⁡ K ⁡ W = trL ⁡ K ⁡ W
9 7 2 4 8 3 tendotp ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E ∧ I ↾ B ∈ LTrn ⁡ K ⁡ W → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ≤ K trL ⁡ K ⁡ W ⁡ I ↾ B
10 6 9 mpd3an3 ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ≤ K trL ⁡ K ⁡ W ⁡ I ↾ B
11 eqid ⊢ 0. ⁡ K = 0. ⁡ K
12 1 11 2 8 trlid0 ⊢ K ∈ HL ∧ W ∈ H → trL ⁡ K ⁡ W ⁡ I ↾ B = 0. ⁡ K
13 12 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → trL ⁡ K ⁡ W ⁡ I ↾ B = 0. ⁡ K
14 10 13 breqtrd ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ≤ K 0. ⁡ K
15 hlop ⊢ K ∈ HL → K ∈ OP
16 15 ad2antrr ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → K ∈ OP
17 2 4 3 tendocl ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E ∧ I ↾ B ∈ LTrn ⁡ K ⁡ W → S ⁡ I ↾ B ∈ LTrn ⁡ K ⁡ W
18 6 17 mpd3an3 ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → S ⁡ I ↾ B ∈ LTrn ⁡ K ⁡ W
19 1 2 4 8 trlcl ⊢ K ∈ HL ∧ W ∈ H ∧ S ⁡ I ↾ B ∈ LTrn ⁡ K ⁡ W → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ∈ B
20 18 19 syldan ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ∈ B
21 1 7 11 ople0 ⊢ K ∈ OP ∧ trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ∈ B → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ≤ K 0. ⁡ K ↔ trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B = 0. ⁡ K
22 16 20 21 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B ≤ K 0. ⁡ K ↔ trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B = 0. ⁡ K
23 14 22 mpbid ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B = 0. ⁡ K
24 1 11 2 4 8 trlid0b ⊢ K ∈ HL ∧ W ∈ H ∧ S ⁡ I ↾ B ∈ LTrn ⁡ K ⁡ W → S ⁡ I ↾ B = I ↾ B ↔ trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B = 0. ⁡ K
25 18 24 syldan ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → S ⁡ I ↾ B = I ↾ B ↔ trL ⁡ K ⁡ W ⁡ S ⁡ I ↾ B = 0. ⁡ K
26 23 25 mpbird ⊢ K ∈ HL ∧ W ∈ H ∧ S ∈ E → S ⁡ I ↾ B = I ↾ B