Metamath Proof Explorer


Theorem fcnvgreu

Description: If the converse of a relation A is a function, exactly one point of its graph has a given second element (that is, function value). (Contributed by Thierry Arnoux, 1-Apr-2018)

Ref Expression
Assertion fcnvgreu ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑌 ∈ ran 𝐴 ) → ∃! 𝑝𝐴 𝑌 = ( 2nd𝑝 ) )

Proof

Step Hyp Ref Expression
1 df-rn ran 𝐴 = dom 𝐴
2 1 eleq2i ( 𝑌 ∈ ran 𝐴𝑌 ∈ dom 𝐴 )
3 fgreu ( ( Fun 𝐴𝑌 ∈ dom 𝐴 ) → ∃! 𝑞 𝐴 𝑌 = ( 1st𝑞 ) )
4 3 adantll ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑌 ∈ dom 𝐴 ) → ∃! 𝑞 𝐴 𝑌 = ( 1st𝑞 ) )
5 2 4 sylan2b ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑌 ∈ ran 𝐴 ) → ∃! 𝑞 𝐴 𝑌 = ( 1st𝑞 ) )
6 cnvcnvss 𝐴𝐴
7 cnvssrndm 𝐴 ⊆ ( ran 𝐴 × dom 𝐴 )
8 7 sseli ( 𝑞 𝐴𝑞 ∈ ( ran 𝐴 × dom 𝐴 ) )
9 dfdm4 dom 𝐴 = ran 𝐴
10 1 9 xpeq12i ( ran 𝐴 × dom 𝐴 ) = ( dom 𝐴 × ran 𝐴 )
11 8 10 eleqtrdi ( 𝑞 𝐴𝑞 ∈ ( dom 𝐴 × ran 𝐴 ) )
12 2nd1st ( 𝑞 ∈ ( dom 𝐴 × ran 𝐴 ) → { 𝑞 } = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ )
13 11 12 syl ( 𝑞 𝐴 { 𝑞 } = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ )
14 13 eqcomd ( 𝑞 𝐴 → ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ = { 𝑞 } )
15 relcnv Rel 𝐴
16 cnvf1olem ( ( Rel 𝐴 ∧ ( 𝑞 𝐴 ∧ ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ = { 𝑞 } ) ) → ( ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ∈ 𝐴𝑞 = { ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ } ) )
17 16 simpld ( ( Rel 𝐴 ∧ ( 𝑞 𝐴 ∧ ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ = { 𝑞 } ) ) → ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ∈ 𝐴 )
18 15 17 mpan ( ( 𝑞 𝐴 ∧ ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ = { 𝑞 } ) → ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ∈ 𝐴 )
19 14 18 mpdan ( 𝑞 𝐴 → ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ∈ 𝐴 )
20 6 19 sseldi ( 𝑞 𝐴 → ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ∈ 𝐴 )
21 20 adantl ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑞 𝐴 ) → ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ∈ 𝐴 )
22 simpll ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → Rel 𝐴 )
23 simpr ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → 𝑝𝐴 )
24 relssdmrn ( Rel 𝐴𝐴 ⊆ ( dom 𝐴 × ran 𝐴 ) )
25 24 adantr ( ( Rel 𝐴 ∧ Fun 𝐴 ) → 𝐴 ⊆ ( dom 𝐴 × ran 𝐴 ) )
26 25 sselda ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → 𝑝 ∈ ( dom 𝐴 × ran 𝐴 ) )
27 2nd1st ( 𝑝 ∈ ( dom 𝐴 × ran 𝐴 ) → { 𝑝 } = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ )
28 26 27 syl ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → { 𝑝 } = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ )
29 28 eqcomd ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ = { 𝑝 } )
30 cnvf1olem ( ( Rel 𝐴 ∧ ( 𝑝𝐴 ∧ ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ = { 𝑝 } ) ) → ( ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ∈ 𝐴𝑝 = { ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ } ) )
31 30 simpld ( ( Rel 𝐴 ∧ ( 𝑝𝐴 ∧ ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ = { 𝑝 } ) ) → ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ∈ 𝐴 )
32 22 23 29 31 syl12anc ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ∈ 𝐴 )
33 15 a1i ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → Rel 𝐴 )
34 simplr ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → 𝑞 𝐴 )
35 14 ad2antlr ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ = { 𝑞 } )
36 16 simprd ( ( Rel 𝐴 ∧ ( 𝑞 𝐴 ∧ ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ = { 𝑞 } ) ) → 𝑞 = { ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ } )
37 33 34 35 36 syl12anc ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → 𝑞 = { ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ } )
38 simpr ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ )
39 38 sneqd ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → { 𝑝 } = { ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ } )
40 39 cnveqd ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → { 𝑝 } = { ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ } )
41 40 unieqd ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → { 𝑝 } = { ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ } )
42 28 ad2antrr ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → { 𝑝 } = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ )
43 37 41 42 3eqtr2d ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ )
44 30 simprd ( ( Rel 𝐴 ∧ ( 𝑝𝐴 ∧ ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ = { 𝑝 } ) ) → 𝑝 = { ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ } )
45 22 23 29 44 syl12anc ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → 𝑝 = { ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ } )
46 45 ad2antrr ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) → 𝑝 = { ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ } )
47 simpr ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) → 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ )
48 47 sneqd ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) → { 𝑞 } = { ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ } )
49 48 cnveqd ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) → { 𝑞 } = { ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ } )
50 49 unieqd ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) → { 𝑞 } = { ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ } )
51 13 ad2antlr ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) → { 𝑞 } = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ )
52 46 50 51 3eqtr2d ( ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) ∧ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) → 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ )
53 43 52 impbida ( ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) ∧ 𝑞 𝐴 ) → ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) )
54 53 ralrimiva ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → ∀ 𝑞 𝐴 ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) )
55 eqeq2 ( 𝑟 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ → ( 𝑞 = 𝑟𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) )
56 55 bibi2d ( 𝑟 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ → ( ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = 𝑟 ) ↔ ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) ) )
57 56 ralbidv ( 𝑟 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ → ( ∀ 𝑞 𝐴 ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = 𝑟 ) ↔ ∀ 𝑞 𝐴 ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) ) )
58 57 rspcev ( ( ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ∈ 𝐴 ∧ ∀ 𝑞 𝐴 ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = ⟨ ( 2nd𝑝 ) , ( 1st𝑝 ) ⟩ ) ) → ∃ 𝑟 𝐴𝑞 𝐴 ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = 𝑟 ) )
59 32 54 58 syl2anc ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → ∃ 𝑟 𝐴𝑞 𝐴 ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = 𝑟 ) )
60 reu6 ( ∃! 𝑞 𝐴 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ ∃ 𝑟 𝐴𝑞 𝐴 ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ↔ 𝑞 = 𝑟 ) )
61 59 60 sylibr ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝𝐴 ) → ∃! 𝑞 𝐴 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ )
62 fvex ( 2nd𝑞 ) ∈ V
63 fvex ( 1st𝑞 ) ∈ V
64 62 63 op2ndd ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ → ( 2nd𝑝 ) = ( 1st𝑞 ) )
65 64 eqeq2d ( 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ → ( 𝑌 = ( 2nd𝑝 ) ↔ 𝑌 = ( 1st𝑞 ) ) )
66 65 adantl ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑝 = ⟨ ( 2nd𝑞 ) , ( 1st𝑞 ) ⟩ ) → ( 𝑌 = ( 2nd𝑝 ) ↔ 𝑌 = ( 1st𝑞 ) ) )
67 21 61 66 reuxfr1d ( ( Rel 𝐴 ∧ Fun 𝐴 ) → ( ∃! 𝑝𝐴 𝑌 = ( 2nd𝑝 ) ↔ ∃! 𝑞 𝐴 𝑌 = ( 1st𝑞 ) ) )
68 67 adantr ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑌 ∈ ran 𝐴 ) → ( ∃! 𝑝𝐴 𝑌 = ( 2nd𝑝 ) ↔ ∃! 𝑞 𝐴 𝑌 = ( 1st𝑞 ) ) )
69 5 68 mpbird ( ( ( Rel 𝐴 ∧ Fun 𝐴 ) ∧ 𝑌 ∈ ran 𝐴 ) → ∃! 𝑝𝐴 𝑌 = ( 2nd𝑝 ) )