Metamath Proof Explorer


Theorem cvmliftiota

Description: Write out a function H that is the unique lift of F . (Contributed by Mario Carneiro, 16-Feb-2015)

Ref Expression
Hypotheses cvmliftiota.b ⊢ B = ⋃ C
cvmliftiota.h ⊢ H = ι f ∈ II Cn C | F ∘ f = G ∧ f ⁡ 0 = P
cvmliftiota.f ⊢ φ → F ∈ C CovMap J
cvmliftiota.g ⊢ φ → G ∈ II Cn J
cvmliftiota.p ⊢ φ → P ∈ B
cvmliftiota.e ⊢ φ → F ⁡ P = G ⁡ 0
Assertion cvmliftiota ⊢ φ → H ∈ II Cn C ∧ F ∘ H = G ∧ H ⁡ 0 = P

Proof

Step Hyp Ref Expression
1 cvmliftiota.b ⊢ B = ⋃ C
2 cvmliftiota.h ⊢ H = ι f ∈ II Cn C | F ∘ f = G ∧ f ⁡ 0 = P
3 cvmliftiota.f ⊢ φ → F ∈ C CovMap J
4 cvmliftiota.g ⊢ φ → G ∈ II Cn J
5 cvmliftiota.p ⊢ φ → P ∈ B
6 cvmliftiota.e ⊢ φ → F ⁡ P = G ⁡ 0
7 coeq2 ⊢ f = g → F ∘ f = F ∘ g
8 7 eqeq1d ⊢ f = g → F ∘ f = G ↔ F ∘ g = G
9 fveq1 ⊢ f = g → f ⁡ 0 = g ⁡ 0
10 9 eqeq1d ⊢ f = g → f ⁡ 0 = P ↔ g ⁡ 0 = P
11 8 10 anbi12d ⊢ f = g → F ∘ f = G ∧ f ⁡ 0 = P ↔ F ∘ g = G ∧ g ⁡ 0 = P
12 11 cbvriotavw ⊢ ι f ∈ II Cn C | F ∘ f = G ∧ f ⁡ 0 = P = ι g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P
13 2 12 eqtri ⊢ H = ι g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P
14 1 cvmlift ⊢ F ∈ C CovMap J ∧ G ∈ II Cn J ∧ P ∈ B ∧ F ⁡ P = G ⁡ 0 → ∃! g ∈ II Cn C F ∘ g = G ∧ g ⁡ 0 = P
15 3 4 5 6 14 syl22anc ⊢ φ → ∃! g ∈ II Cn C F ∘ g = G ∧ g ⁡ 0 = P
16 riotacl2 ⊢ ∃! g ∈ II Cn C F ∘ g = G ∧ g ⁡ 0 = P → ι g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P ∈ g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P
17 15 16 syl ⊢ φ → ι g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P ∈ g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P
18 13 17 eqeltrid ⊢ φ → H ∈ g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P
19 coeq2 ⊢ g = H → F ∘ g = F ∘ H
20 19 eqeq1d ⊢ g = H → F ∘ g = G ↔ F ∘ H = G
21 fveq1 ⊢ g = H → g ⁡ 0 = H ⁡ 0
22 21 eqeq1d ⊢ g = H → g ⁡ 0 = P ↔ H ⁡ 0 = P
23 20 22 anbi12d ⊢ g = H → F ∘ g = G ∧ g ⁡ 0 = P ↔ F ∘ H = G ∧ H ⁡ 0 = P
24 23 elrab ⊢ H ∈ g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P ↔ H ∈ II Cn C ∧ F ∘ H = G ∧ H ⁡ 0 = P
25 3anass ⊢ H ∈ II Cn C ∧ F ∘ H = G ∧ H ⁡ 0 = P ↔ H ∈ II Cn C ∧ F ∘ H = G ∧ H ⁡ 0 = P
26 24 25 bitr4i ⊢ H ∈ g ∈ II Cn C | F ∘ g = G ∧ g ⁡ 0 = P ↔ H ∈ II Cn C ∧ F ∘ H = G ∧ H ⁡ 0 = P
27 18 26 sylib ⊢ φ → H ∈ II Cn C ∧ F ∘ H = G ∧ H ⁡ 0 = P