Metamath Proof Explorer


Theorem difsnen

Description: All decrements of a set are equinumerous. (Contributed by Stefan O'Rear, 19-Feb-2015)

Ref Expression
Assertion difsnen ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X → X ∖ A ≈ X ∖ B

Proof

Step Hyp Ref Expression
1 difexg ⊢ X ∈ V → X ∖ A ∈ V
2 enrefg ⊢ X ∖ A ∈ V → X ∖ A ≈ X ∖ A
3 1 2 syl ⊢ X ∈ V → X ∖ A ≈ X ∖ A
4 3 3ad2ant1 ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X → X ∖ A ≈ X ∖ A
5 sneq ⊢ A = B → A = B
6 5 difeq2d ⊢ A = B → X ∖ A = X ∖ B
7 6 breq2d ⊢ A = B → X ∖ A ≈ X ∖ A ↔ X ∖ A ≈ X ∖ B
8 4 7 syl5ibcom ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X → A = B → X ∖ A ≈ X ∖ B
9 8 imp ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A = B → X ∖ A ≈ X ∖ B
10 simpl1 ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∈ V
11 difexg ⊢ X ∖ A ∈ V → X ∖ A ∖ B ∈ V
12 enrefg ⊢ X ∖ A ∖ B ∈ V → X ∖ A ∖ B ≈ X ∖ A ∖ B
13 10 1 11 12 4syl ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ A ∖ B ≈ X ∖ A ∖ B
14 dif32 ⊢ X ∖ A ∖ B = X ∖ B ∖ A
15 13 14 breqtrdi ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ A ∖ B ≈ X ∖ B ∖ A
16 simpl3 ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → B ∈ X
17 simpl2 ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → A ∈ X
18 en2sn ⊢ B ∈ X ∧ A ∈ X → B ≈ A
19 16 17 18 syl2anc ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → B ≈ A
20 disjdifr ⊢ X ∖ A ∖ B ∩ B = ∅
21 20 a1i ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ A ∖ B ∩ B = ∅
22 disjdifr ⊢ X ∖ B ∖ A ∩ A = ∅
23 22 a1i ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ B ∖ A ∩ A = ∅
24 unen ⊢ X ∖ A ∖ B ≈ X ∖ B ∖ A ∧ B ≈ A ∧ X ∖ A ∖ B ∩ B = ∅ ∧ X ∖ B ∖ A ∩ A = ∅ → X ∖ A ∖ B ∪ B ≈ X ∖ B ∖ A ∪ A
25 15 19 21 23 24 syl22anc ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ A ∖ B ∪ B ≈ X ∖ B ∖ A ∪ A
26 simpr ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → A ≠ B
27 26 necomd ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → B ≠ A
28 eldifsn ⊢ B ∈ X ∖ A ↔ B ∈ X ∧ B ≠ A
29 16 27 28 sylanbrc ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → B ∈ X ∖ A
30 difsnid ⊢ B ∈ X ∖ A → X ∖ A ∖ B ∪ B = X ∖ A
31 29 30 syl ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ A ∖ B ∪ B = X ∖ A
32 eldifsn ⊢ A ∈ X ∖ B ↔ A ∈ X ∧ A ≠ B
33 17 26 32 sylanbrc ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → A ∈ X ∖ B
34 difsnid ⊢ A ∈ X ∖ B → X ∖ B ∖ A ∪ A = X ∖ B
35 33 34 syl ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ B ∖ A ∪ A = X ∖ B
36 25 31 35 3brtr3d ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X ∧ A ≠ B → X ∖ A ≈ X ∖ B
37 9 36 pm2.61dane ⊢ X ∈ V ∧ A ∈ X ∧ B ∈ X → X ∖ A ≈ X ∖ B