Metamath Proof Explorer


Theorem efifo

Description: The exponential function of an imaginary number maps the reals onto the unit circle. (Contributed by Mario Carneiro, 13-May-2014)

Ref Expression
Hypotheses efifo.1 ⊢ F = z ∈ ℝ ⟼ e i ⁢ z
efifo.2 ⊢ C = abs -1 1
Assertion efifo ⊢ F : ℝ ⟶ onto C

Proof

Step Hyp Ref Expression
1 efifo.1 ⊢ F = z ∈ ℝ ⟼ e i ⁢ z
2 efifo.2 ⊢ C = abs -1 1
3 ax-icn ⊢ i ∈ ℂ
4 recn ⊢ z ∈ ℝ → z ∈ ℂ
5 mulcl ⊢ i ∈ ℂ ∧ z ∈ ℂ → i ⁢ z ∈ ℂ
6 3 4 5 sylancr ⊢ z ∈ ℝ → i ⁢ z ∈ ℂ
7 efcl ⊢ i ⁢ z ∈ ℂ → e i ⁢ z ∈ ℂ
8 6 7 syl ⊢ z ∈ ℝ → e i ⁢ z ∈ ℂ
9 absefi ⊢ z ∈ ℝ → e i ⁢ z = 1
10 absf ⊢ abs : ℂ ⟶ ℝ
11 ffn ⊢ abs : ℂ ⟶ ℝ → abs Fn ℂ
12 fniniseg ⊢ abs Fn ℂ → e i ⁢ z ∈ abs -1 1 ↔ e i ⁢ z ∈ ℂ ∧ e i ⁢ z = 1
13 10 11 12 mp2b ⊢ e i ⁢ z ∈ abs -1 1 ↔ e i ⁢ z ∈ ℂ ∧ e i ⁢ z = 1
14 8 9 13 sylanbrc ⊢ z ∈ ℝ → e i ⁢ z ∈ abs -1 1
15 14 2 eleqtrrdi ⊢ z ∈ ℝ → e i ⁢ z ∈ C
16 1 15 fmpti ⊢ F : ℝ ⟶ C
17 ffn ⊢ F : ℝ ⟶ C → F Fn ℝ
18 16 17 ax-mp ⊢ F Fn ℝ
19 frn ⊢ F : ℝ ⟶ C → ran ⁡ F ⊆ C
20 16 19 ax-mp ⊢ ran ⁡ F ⊆ C
21 df-ima ⊢ F 0 2 ⁢ π = ran ⁡ F ↾ 0 2 ⁢ π
22 1 reseq1i ⊢ F ↾ 0 2 ⁢ π = z ∈ ℝ ⟼ e i ⁢ z ↾ 0 2 ⁢ π
23 0xr ⊢ 0 ∈ ℝ *
24 2re ⊢ 2 ∈ ℝ
25 pire ⊢ π ∈ ℝ
26 24 25 remulcli ⊢ 2 ⁢ π ∈ ℝ
27 elioc2 ⊢ 0 ∈ ℝ * ∧ 2 ⁢ π ∈ ℝ → z ∈ 0 2 ⁢ π ↔ z ∈ ℝ ∧ 0 < z ∧ z ≤ 2 ⁢ π
28 23 26 27 mp2an ⊢ z ∈ 0 2 ⁢ π ↔ z ∈ ℝ ∧ 0 < z ∧ z ≤ 2 ⁢ π
29 28 simp1bi ⊢ z ∈ 0 2 ⁢ π → z ∈ ℝ
30 29 ssriv ⊢ 0 2 ⁢ π ⊆ ℝ
31 resmpt ⊢ 0 2 ⁢ π ⊆ ℝ → z ∈ ℝ ⟼ e i ⁢ z ↾ 0 2 ⁢ π = z ∈ 0 2 ⁢ π ⟼ e i ⁢ z
32 30 31 ax-mp ⊢ z ∈ ℝ ⟼ e i ⁢ z ↾ 0 2 ⁢ π = z ∈ 0 2 ⁢ π ⟼ e i ⁢ z
33 22 32 eqtri ⊢ F ↾ 0 2 ⁢ π = z ∈ 0 2 ⁢ π ⟼ e i ⁢ z
34 33 rneqi ⊢ ran ⁡ F ↾ 0 2 ⁢ π = ran ⁡ z ∈ 0 2 ⁢ π ⟼ e i ⁢ z
35 0re ⊢ 0 ∈ ℝ
36 eqid ⊢ z ∈ 0 2 ⁢ π ⟼ e i ⁢ z = z ∈ 0 2 ⁢ π ⟼ e i ⁢ z
37 26 recni ⊢ 2 ⁢ π ∈ ℂ
38 37 addlidi ⊢ 0 + 2 ⁢ π = 2 ⁢ π
39 38 oveq2i ⊢ 0 0 + 2 ⁢ π = 0 2 ⁢ π
40 39 eqcomi ⊢ 0 2 ⁢ π = 0 0 + 2 ⁢ π
41 36 2 40 efif1o ⊢ 0 ∈ ℝ → z ∈ 0 2 ⁢ π ⟼ e i ⁢ z : 0 2 ⁢ π ⟶ 1-1 onto C
42 35 41 ax-mp ⊢ z ∈ 0 2 ⁢ π ⟼ e i ⁢ z : 0 2 ⁢ π ⟶ 1-1 onto C
43 f1ofo ⊢ z ∈ 0 2 ⁢ π ⟼ e i ⁢ z : 0 2 ⁢ π ⟶ 1-1 onto C → z ∈ 0 2 ⁢ π ⟼ e i ⁢ z : 0 2 ⁢ π ⟶ onto C
44 forn ⊢ z ∈ 0 2 ⁢ π ⟼ e i ⁢ z : 0 2 ⁢ π ⟶ onto C → ran ⁡ z ∈ 0 2 ⁢ π ⟼ e i ⁢ z = C
45 42 43 44 mp2b ⊢ ran ⁡ z ∈ 0 2 ⁢ π ⟼ e i ⁢ z = C
46 34 45 eqtri ⊢ ran ⁡ F ↾ 0 2 ⁢ π = C
47 21 46 eqtri ⊢ F 0 2 ⁢ π = C
48 imassrn ⊢ F 0 2 ⁢ π ⊆ ran ⁡ F
49 47 48 eqsstrri ⊢ C ⊆ ran ⁡ F
50 20 49 eqssi ⊢ ran ⁡ F = C
51 df-fo ⊢ F : ℝ ⟶ onto C ↔ F Fn ℝ ∧ ran ⁡ F = C
52 18 50 51 mpbir2an ⊢ F : ℝ ⟶ onto C