Metamath Proof Explorer


Theorem gchdomtri

Description: Under certain conditions, a GCH-set can demonstrate trichotomy of dominance. Lemma for gchac . (Contributed by Mario Carneiro, 15-May-2015)

Ref Expression
Assertion gchdomtri ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → A ≼ B ∨ B ≼ A

Proof

Step Hyp Ref Expression
1 sdomdom ⊢ A ≺ B → A ≼ B
2 1 con3i ⊢ ¬ A ≼ B → ¬ A ≺ B
3 reldom ⊢ Rel ⁡ ≼
4 3 brrelex1i ⊢ B ≼ 𝒫 A → B ∈ V
5 4 3ad2ant3 ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → B ∈ V
6 fidomtri2 ⊢ B ∈ V ∧ A ∈ Fin → B ≼ A ↔ ¬ A ≺ B
7 5 6 sylan ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ∈ Fin → B ≼ A ↔ ¬ A ≺ B
8 2 7 imbitrrid ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ∈ Fin → ¬ A ≼ B → B ≼ A
9 8 orrd ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ∈ Fin → A ≼ B ∨ B ≼ A
10 simp1 ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → A ∈ GCH
11 10 adantr ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ ¬ A ∈ Fin → A ∈ GCH
12 simpr ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ ¬ A ∈ Fin → ¬ A ∈ Fin
13 djudoml ⊢ A ∈ GCH ∧ B ∈ V → A ≼ A ⊔︀ B
14 10 5 13 syl2anc ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → A ≼ A ⊔︀ B
15 14 adantr ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ ¬ A ∈ Fin → A ≼ A ⊔︀ B
16 djulepw ⊢ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → A ⊔︀ B ≼ 𝒫 A
17 16 3adant1 ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → A ⊔︀ B ≼ 𝒫 A
18 17 adantr ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ ¬ A ∈ Fin → A ⊔︀ B ≼ 𝒫 A
19 gchor ⊢ A ∈ GCH ∧ ¬ A ∈ Fin ∧ A ≼ A ⊔︀ B ∧ A ⊔︀ B ≼ 𝒫 A → A ≈ A ⊔︀ B ∨ A ⊔︀ B ≈ 𝒫 A
20 11 12 15 18 19 syl22anc ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ ¬ A ∈ Fin → A ≈ A ⊔︀ B ∨ A ⊔︀ B ≈ 𝒫 A
21 djudoml ⊢ B ∈ V ∧ A ∈ GCH → B ≼ B ⊔︀ A
22 5 10 21 syl2anc ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → B ≼ B ⊔︀ A
23 djucomen ⊢ B ∈ V ∧ A ∈ GCH → B ⊔︀ A ≈ A ⊔︀ B
24 5 10 23 syl2anc ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → B ⊔︀ A ≈ A ⊔︀ B
25 domentr ⊢ B ≼ B ⊔︀ A ∧ B ⊔︀ A ≈ A ⊔︀ B → B ≼ A ⊔︀ B
26 22 24 25 syl2anc ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → B ≼ A ⊔︀ B
27 domen2 ⊢ A ≈ A ⊔︀ B → B ≼ A ↔ B ≼ A ⊔︀ B
28 26 27 syl5ibrcom ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → A ≈ A ⊔︀ B → B ≼ A
29 28 imp ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ≈ A ⊔︀ B → B ≼ A
30 29 olcd ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ≈ A ⊔︀ B → A ≼ B ∨ B ≼ A
31 simpl1 ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → A ∈ GCH
32 canth2g ⊢ A ∈ GCH → A ≺ 𝒫 A
33 sdomdom ⊢ A ≺ 𝒫 A → A ≼ 𝒫 A
34 31 32 33 3syl ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → A ≼ 𝒫 A
35 simpl2 ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → A ⊔︀ A ≈ A
36 pwen ⊢ A ⊔︀ A ≈ A → 𝒫 A ⊔︀ A ≈ 𝒫 A
37 35 36 syl ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → 𝒫 A ⊔︀ A ≈ 𝒫 A
38 enen2 ⊢ A ⊔︀ B ≈ 𝒫 A → 𝒫 A ⊔︀ A ≈ A ⊔︀ B ↔ 𝒫 A ⊔︀ A ≈ 𝒫 A
39 38 adantl ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → 𝒫 A ⊔︀ A ≈ A ⊔︀ B ↔ 𝒫 A ⊔︀ A ≈ 𝒫 A
40 37 39 mpbird ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → 𝒫 A ⊔︀ A ≈ A ⊔︀ B
41 endom ⊢ 𝒫 A ⊔︀ A ≈ A ⊔︀ B → 𝒫 A ⊔︀ A ≼ A ⊔︀ B
42 pwdjudom ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ≼ B
43 40 41 42 3syl ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → 𝒫 A ≼ B
44 domtr ⊢ A ≼ 𝒫 A ∧ 𝒫 A ≼ B → A ≼ B
45 34 43 44 syl2anc ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → A ≼ B
46 45 orcd ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ⊔︀ B ≈ 𝒫 A → A ≼ B ∨ B ≼ A
47 30 46 jaodan ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ A ≈ A ⊔︀ B ∨ A ⊔︀ B ≈ 𝒫 A → A ≼ B ∨ B ≼ A
48 20 47 syldan ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A ∧ ¬ A ∈ Fin → A ≼ B ∨ B ≼ A
49 9 48 pm2.61dan ⊢ A ∈ GCH ∧ A ⊔︀ A ≈ A ∧ B ≼ 𝒫 A → A ≼ B ∨ B ≼ A