Metamath Proof Explorer


Theorem hdmapglem5

Description: Part 1.2 in Baer p. 110 line 34, f(u,v) alpha = f(v,u). (Contributed by NM, 12-Jun-2015)

Ref Expression
Hypotheses hdmapglem5.h ⊢ H = LHyp ⁡ K
hdmapglem5.e ⊢ E = I ↾ Base K I ↾ LTrn ⁡ K ⁡ W
hdmapglem5.o ⊢ O = ocH ⁡ K ⁡ W
hdmapglem5.u ⊢ U = DVecH ⁡ K ⁡ W
hdmapglem5.v ⊢ V = Base U
hdmapglem5.p ⊢ + ˙ = + U
hdmapglem5.m ⊢ - ˙ = - U
hdmapglem5.q ⊢ · ˙ = ⋅ U
hdmapglem5.r ⊢ R = Scalar ⁡ U
hdmapglem5.b ⊢ B = Base R
hdmapglem5.t ⊢ × ˙ = ⋅ R
hdmapglem5.z ⊢ 0 ˙ = 0 R
hdmapglem5.s ⊢ S = HDMap ⁡ K ⁡ W
hdmapglem5.g ⊢ G = HGMap ⁡ K ⁡ W
hdmapglem5.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmapglem5.c ⊢ φ → C ∈ O ⁡ E
hdmapglem5.d ⊢ φ → D ∈ O ⁡ E
hdmapglem5.i ⊢ φ → I ∈ B
hdmapglem5.j ⊢ φ → J ∈ B
Assertion hdmapglem5 ⊢ φ → G ⁡ S ⁡ D ⁡ C = S ⁡ C ⁡ D

Proof

Step Hyp Ref Expression
1 hdmapglem5.h ⊢ H = LHyp ⁡ K
2 hdmapglem5.e ⊢ E = I ↾ Base K I ↾ LTrn ⁡ K ⁡ W
3 hdmapglem5.o ⊢ O = ocH ⁡ K ⁡ W
4 hdmapglem5.u ⊢ U = DVecH ⁡ K ⁡ W
5 hdmapglem5.v ⊢ V = Base U
6 hdmapglem5.p ⊢ + ˙ = + U
7 hdmapglem5.m ⊢ - ˙ = - U
8 hdmapglem5.q ⊢ · ˙ = ⋅ U
9 hdmapglem5.r ⊢ R = Scalar ⁡ U
10 hdmapglem5.b ⊢ B = Base R
11 hdmapglem5.t ⊢ × ˙ = ⋅ R
12 hdmapglem5.z ⊢ 0 ˙ = 0 R
13 hdmapglem5.s ⊢ S = HDMap ⁡ K ⁡ W
14 hdmapglem5.g ⊢ G = HGMap ⁡ K ⁡ W
15 hdmapglem5.k ⊢ φ → K ∈ HL ∧ W ∈ H
16 hdmapglem5.c ⊢ φ → C ∈ O ⁡ E
17 hdmapglem5.d ⊢ φ → D ∈ O ⁡ E
18 hdmapglem5.i ⊢ φ → I ∈ B
19 hdmapglem5.j ⊢ φ → J ∈ B
20 1 4 15 dvhlmod ⊢ φ → U ∈ LMod
21 9 lmodring ⊢ U ∈ LMod → R ∈ Ring
22 20 21 syl ⊢ φ → R ∈ Ring
23 eqid ⊢ Base K = Base K
24 eqid ⊢ LTrn ⁡ K ⁡ W = LTrn ⁡ K ⁡ W
25 eqid ⊢ 0 U = 0 U
26 1 23 24 4 5 25 2 15 dvheveccl ⊢ φ → E ∈ V ∖ 0 U
27 26 eldifad ⊢ φ → E ∈ V
28 27 snssd ⊢ φ → E ⊆ V
29 1 4 5 3 dochssv ⊢ K ∈ HL ∧ W ∈ H ∧ E ⊆ V → O ⁡ E ⊆ V
30 15 28 29 syl2anc ⊢ φ → O ⁡ E ⊆ V
31 30 16 sseldd ⊢ φ → C ∈ V
32 30 17 sseldd ⊢ φ → D ∈ V
33 1 4 5 9 10 13 15 31 32 hdmapipcl ⊢ φ → S ⁡ D ⁡ C ∈ B
34 1 4 9 10 14 15 33 hgmapcl ⊢ φ → G ⁡ S ⁡ D ⁡ C ∈ B
35 eqid ⊢ 1 R = 1 R
36 10 11 35 ringlidm ⊢ R ∈ Ring ∧ G ⁡ S ⁡ D ⁡ C ∈ B → 1 R × ˙ G ⁡ S ⁡ D ⁡ C = G ⁡ S ⁡ D ⁡ C
37 22 34 36 syl2anc ⊢ φ → 1 R × ˙ G ⁡ S ⁡ D ⁡ C = G ⁡ S ⁡ D ⁡ C
38 10 35 ringidcl ⊢ R ∈ Ring → 1 R ∈ B
39 22 38 syl ⊢ φ → 1 R ∈ B
40 1 4 9 35 14 15 hgmapval1 ⊢ φ → G ⁡ 1 R = 1 R
41 40 oveq2d ⊢ φ → S ⁡ D ⁡ C × ˙ G ⁡ 1 R = S ⁡ D ⁡ C × ˙ 1 R
42 10 11 35 ringridm ⊢ R ∈ Ring ∧ S ⁡ D ⁡ C ∈ B → S ⁡ D ⁡ C × ˙ 1 R = S ⁡ D ⁡ C
43 22 33 42 syl2anc ⊢ φ → S ⁡ D ⁡ C × ˙ 1 R = S ⁡ D ⁡ C
44 41 43 eqtrd ⊢ φ → S ⁡ D ⁡ C × ˙ G ⁡ 1 R = S ⁡ D ⁡ C
45 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 33 39 44 hdmapinvlem4 ⊢ φ → 1 R × ˙ G ⁡ S ⁡ D ⁡ C = S ⁡ C ⁡ D
46 37 45 eqtr3d ⊢ φ → G ⁡ S ⁡ D ⁡ C = S ⁡ C ⁡ D