Metamath Proof Explorer


Theorem itg2val

Description: Value of the integral on nonnegative real functions. (Contributed by Mario Carneiro, 28-Jun-2014)

Ref Expression
Hypothesis itg2val.1 ⊢ L = x | ∃ g ∈ dom ⁡ ∫ 1 g ≤ f F ∧ x = ∫ 1 ⁡ g
Assertion itg2val ⊢ F : ℝ ⟶ 0 +∞ → ∫ 2 ⁡ F = sup L ℝ * <

Proof

Step Hyp Ref Expression
1 itg2val.1 ⊢ L = x | ∃ g ∈ dom ⁡ ∫ 1 g ≤ f F ∧ x = ∫ 1 ⁡ g
2 xrltso ⊢ < Or ℝ *
3 2 supex ⊢ sup L ℝ * < ∈ V
4 reex ⊢ ℝ ∈ V
5 ovex ⊢ 0 +∞ ∈ V
6 breq2 ⊢ f = F → g ≤ f f ↔ g ≤ f F
7 6 anbi1d ⊢ f = F → g ≤ f f ∧ x = ∫ 1 ⁡ g ↔ g ≤ f F ∧ x = ∫ 1 ⁡ g
8 7 rexbidv ⊢ f = F → ∃ g ∈ dom ⁡ ∫ 1 g ≤ f f ∧ x = ∫ 1 ⁡ g ↔ ∃ g ∈ dom ⁡ ∫ 1 g ≤ f F ∧ x = ∫ 1 ⁡ g
9 8 abbidv ⊢ f = F → x | ∃ g ∈ dom ⁡ ∫ 1 g ≤ f f ∧ x = ∫ 1 ⁡ g = x | ∃ g ∈ dom ⁡ ∫ 1 g ≤ f F ∧ x = ∫ 1 ⁡ g
10 9 1 eqtr4di ⊢ f = F → x | ∃ g ∈ dom ⁡ ∫ 1 g ≤ f f ∧ x = ∫ 1 ⁡ g = L
11 10 supeq1d ⊢ f = F → sup x | ∃ g ∈ dom ⁡ ∫ 1 g ≤ f f ∧ x = ∫ 1 ⁡ g ℝ * < = sup L ℝ * <
12 df-itg2 ⊢ ∫ 2 = f ∈ 0 +∞ ℝ ⟼ sup x | ∃ g ∈ dom ⁡ ∫ 1 g ≤ f f ∧ x = ∫ 1 ⁡ g ℝ * <
13 3 4 5 11 12 fvmptmap ⊢ F : ℝ ⟶ 0 +∞ → ∫ 2 ⁡ F = sup L ℝ * <