Description: Lemma for nosupbnd1 . When there is no maximum, if any member of A is a prolongment of S , then so are all elements of A above it. (Contributed by Scott Fenton, 5-Dec-2021)
Ref | Expression | ||
---|---|---|---|
Hypothesis | nosupbnd1.1 | |
|
Assertion | nosupbnd1lem2 | |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | nosupbnd1.1 | |
|
2 | simp3rr | |
|
3 | simp2l | |
|
4 | simp3rl | |
|
5 | 3 4 | sseldd | |
6 | simp3ll | |
|
7 | 3 6 | sseldd | |
8 | 1 | nosupno | |
9 | 8 | 3ad2ant2 | |
10 | nodmon | |
|
11 | 9 10 | syl | |
12 | sltres | |
|
13 | 5 7 11 12 | syl3anc | |
14 | 2 13 | mtod | |
15 | simp3lr | |
|
16 | 15 | breq2d | |
17 | 14 16 | mtbid | |
18 | 1 | nosupbnd1lem1 | |
19 | 4 18 | syld3an3 | |
20 | noreson | |
|
21 | 5 11 20 | syl2anc | |
22 | sltso | |
|
23 | sotrieq2 | |
|
24 | 22 23 | mpan | |
25 | 21 9 24 | syl2anc | |
26 | 17 19 25 | mpbir2and | |