Metamath Proof Explorer


Theorem omessre

Description: If the outer measure of a set is real, then the outer measure of any of its subset is real. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Hypotheses omessre.o ⊢ φ → O ∈ OutMeas
omessre.x ⊢ X = ⋃ dom ⁡ O
omessre.a ⊢ φ → A ⊆ X
omessre.re ⊢ φ → O ⁡ A ∈ ℝ
omessre.b ⊢ φ → B ⊆ A
Assertion omessre ⊢ φ → O ⁡ B ∈ ℝ

Proof

Step Hyp Ref Expression
1 omessre.o ⊢ φ → O ∈ OutMeas
2 omessre.x ⊢ X = ⋃ dom ⁡ O
3 omessre.a ⊢ φ → A ⊆ X
4 omessre.re ⊢ φ → O ⁡ A ∈ ℝ
5 omessre.b ⊢ φ → B ⊆ A
6 rge0ssre ⊢ 0 +∞ ⊆ ℝ
7 0xr ⊢ 0 ∈ ℝ *
8 7 a1i ⊢ φ → 0 ∈ ℝ *
9 pnfxr ⊢ +∞ ∈ ℝ *
10 9 a1i ⊢ φ → +∞ ∈ ℝ *
11 5 3 sstrd ⊢ φ → B ⊆ X
12 1 2 11 omexrcl ⊢ φ → O ⁡ B ∈ ℝ *
13 1 2 11 omecl ⊢ φ → O ⁡ B ∈ 0 +∞
14 iccgelb ⊢ 0 ∈ ℝ * ∧ +∞ ∈ ℝ * ∧ O ⁡ B ∈ 0 +∞ → 0 ≤ O ⁡ B
15 8 10 13 14 syl3anc ⊢ φ → 0 ≤ O ⁡ B
16 4 rexrd ⊢ φ → O ⁡ A ∈ ℝ *
17 1 2 3 5 omessle ⊢ φ → O ⁡ B ≤ O ⁡ A
18 4 ltpnfd ⊢ φ → O ⁡ A < +∞
19 12 16 10 17 18 xrlelttrd ⊢ φ → O ⁡ B < +∞
20 8 10 12 15 19 elicod ⊢ φ → O ⁡ B ∈ 0 +∞
21 6 20 sselid ⊢ φ → O ⁡ B ∈ ℝ