Metamath Proof Explorer


Theorem pgnbgreunbgrlem6

Description: Lemma 6 for pgnbgreunbgr . (Contributed by AV, 20-Nov-2025)

Ref Expression
Hypotheses pgnbgreunbgr.g No typesetting found for |- G = ( 5 gPetersenGr 2 ) with typecode |-
pgnbgreunbgr.v ⊢ V = Vtx ⁡ G
pgnbgreunbgr.e ⊢ E = Edg ⁡ G
pgnbgreunbgr.n ⊢ N = G NeighbVtx X
Assertion pgnbgreunbgrlem6 ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b

Proof

Step Hyp Ref Expression
1 pgnbgreunbgr.g Could not format G = ( 5 gPetersenGr 2 ) : No typesetting found for |- G = ( 5 gPetersenGr 2 ) with typecode |-
2 pgnbgreunbgr.v ⊢ V = Vtx ⁡ G
3 pgnbgreunbgr.e ⊢ E = Edg ⁡ G
4 pgnbgreunbgr.n ⊢ N = G NeighbVtx X
5 2 nbgrcl ⊢ K ∈ G NeighbVtx X → X ∈ V
6 5 4 eleq2s ⊢ K ∈ N → X ∈ V
7 6 3ad2ant1 ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L → X ∈ V
8 5eluz3 ⊢ 5 ∈ ℤ ≥ 3
9 pglem ⊢ 2 ∈ 1 ..^ 5 2
10 eqid ⊢ 0 ..^ 5 = 0 ..^ 5
11 eqid ⊢ 1 ..^ 5 2 = 1 ..^ 5 2
12 10 11 1 2 gpgvtxel ⊢ 5 ∈ ℤ ≥ 3 ∧ 2 ∈ 1 ..^ 5 2 → X ∈ V ↔ ∃ x ∈ 0 1 ∃ y ∈ 0 ..^ 5 X = x y
13 8 9 12 mp2an ⊢ X ∈ V ↔ ∃ x ∈ 0 1 ∃ y ∈ 0 ..^ 5 X = x y
14 13 biimpi ⊢ X ∈ V → ∃ x ∈ 0 1 ∃ y ∈ 0 ..^ 5 X = x y
15 14 adantl ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V → ∃ x ∈ 0 1 ∃ y ∈ 0 ..^ 5 X = x y
16 vex ⊢ x ∈ V
17 16 elpr ⊢ x ∈ 0 1 ↔ x = 0 ∨ x = 1
18 8 9 pm3.2i ⊢ 5 ∈ ℤ ≥ 3 ∧ 2 ∈ 1 ..^ 5 2
19 c0ex ⊢ 0 ∈ V
20 vex ⊢ y ∈ V
21 19 20 op1std ⊢ X = 0 y → 1 st ⁡ X = 0
22 21 anim1ci ⊢ X = 0 y ∧ X ∈ V → X ∈ V ∧ 1 st ⁡ X = 0
23 11 1 2 4 gpgnbgrvtx0 ⊢ 5 ∈ ℤ ≥ 3 ∧ 2 ∈ 1 ..^ 5 2 ∧ X ∈ V ∧ 1 st ⁡ X = 0 → N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5
24 18 22 23 sylancr ⊢ X = 0 y ∧ X ∈ V → N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5
25 eleq2 ⊢ N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K ∈ N ↔ K ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5
26 eleq2 ⊢ N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → L ∈ N ↔ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5
27 25 26 anbi12d ⊢ N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K ∈ N ∧ L ∈ N ↔ K ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 ∧ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5
28 27 adantl ⊢ X = 0 y ∧ X ∈ V ∧ N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K ∈ N ∧ L ∈ N ↔ K ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 ∧ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5
29 eltpi ⊢ K ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K = 0 2 nd ⁡ X + 1 mod 5 ∨ K = 1 2 nd ⁡ X ∨ K = 0 2 nd ⁡ X − 1 mod 5
30 eltpi ⊢ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → L = 0 2 nd ⁡ X + 1 mod 5 ∨ L = 1 2 nd ⁡ X ∨ L = 0 2 nd ⁡ X − 1 mod 5
31 1 2 3 4 pgnbgreunbgrlem5 ⊢ L = 0 2 nd ⁡ X + 1 mod 5 ∨ L = 1 2 nd ⁡ X ∨ L = 0 2 nd ⁡ X − 1 mod 5 → K = 0 2 nd ⁡ X + 1 mod 5 ∨ K = 1 2 nd ⁡ X ∨ K = 0 2 nd ⁡ X − 1 mod 5 → X = 0 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
32 30 31 syl ⊢ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K = 0 2 nd ⁡ X + 1 mod 5 ∨ K = 1 2 nd ⁡ X ∨ K = 0 2 nd ⁡ X − 1 mod 5 → X = 0 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
33 29 32 mpan9 ⊢ K ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 ∧ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → X = 0 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
34 33 com12 ⊢ X = 0 y ∧ X ∈ V → K ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 ∧ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
35 34 adantr ⊢ X = 0 y ∧ X ∈ V ∧ N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 ∧ L ∈ 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
36 28 35 sylbid ⊢ X = 0 y ∧ X ∈ V ∧ N = 0 2 nd ⁡ X + 1 mod 5 1 2 nd ⁡ X 0 2 nd ⁡ X − 1 mod 5 → K ∈ N ∧ L ∈ N → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
37 24 36 mpdan ⊢ X = 0 y ∧ X ∈ V → K ∈ N ∧ L ∈ N → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
38 37 com12 ⊢ K ∈ N ∧ L ∈ N → X = 0 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
39 38 expd ⊢ K ∈ N ∧ L ∈ N → X = 0 y → X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
40 39 com24 ⊢ K ∈ N ∧ L ∈ N → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → X ∈ V → X = 0 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
41 40 expd ⊢ K ∈ N ∧ L ∈ N → K ≠ L → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → X ∈ V → X = 0 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
42 41 3impia ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → X ∈ V → X = 0 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
43 42 expdimp ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 → y ∈ 0 ..^ 5 → X ∈ V → X = 0 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
44 43 com23 ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 → X ∈ V → y ∈ 0 ..^ 5 → X = 0 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
45 44 imp31 ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = 0 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
46 opeq1 ⊢ x = 0 → x y = 0 y
47 46 eqeq2d ⊢ x = 0 → X = x y ↔ X = 0 y
48 47 imbi1d ⊢ x = 0 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b ↔ X = 0 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
49 45 48 imbitrrid ⊢ x = 0 → K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
50 opeq1 ⊢ x = 1 → x y = 1 y
51 50 eqeq2d ⊢ x = 1 → X = x y ↔ X = 1 y
52 51 adantr ⊢ x = 1 ∧ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = x y ↔ X = 1 y
53 2 eleq2i ⊢ X ∈ V ↔ X ∈ Vtx ⁡ G
54 53 biimpi ⊢ X ∈ V → X ∈ Vtx ⁡ G
55 1ex ⊢ 1 ∈ V
56 55 20 op1std ⊢ X = 1 y → 1 st ⁡ X = 1
57 54 56 anim12i ⊢ X ∈ V ∧ X = 1 y → X ∈ Vtx ⁡ G ∧ 1 st ⁡ X = 1
58 eqid ⊢ Vtx ⁡ G = Vtx ⁡ G
59 11 1 58 4 gpgnbgrvtx1 ⊢ 5 ∈ ℤ ≥ 3 ∧ 2 ∈ 1 ..^ 5 2 ∧ X ∈ Vtx ⁡ G ∧ 1 st ⁡ X = 1 → N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5
60 18 57 59 sylancr ⊢ X ∈ V ∧ X = 1 y → N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5
61 eleq2 ⊢ N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K ∈ N ↔ K ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5
62 eleq2 ⊢ N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → L ∈ N ↔ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5
63 61 62 anbi12d ⊢ N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K ∈ N ∧ L ∈ N ↔ K ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 ∧ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5
64 63 adantl ⊢ X ∈ V ∧ X = 1 y ∧ N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K ∈ N ∧ L ∈ N ↔ K ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 ∧ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5
65 eltpi ⊢ K ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5
66 eltpi ⊢ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → L = 1 2 nd ⁡ X + 2 mod 5 ∨ L = 0 2 nd ⁡ X ∨ L = 1 2 nd ⁡ X − 2 mod 5
67 1 2 3 4 pgnbgreunbgrlem4 ⊢ L = 1 2 nd ⁡ X + 2 mod 5 ∨ L = 0 2 nd ⁡ X ∨ L = 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5 → X ∈ V ∧ X = 1 y → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
68 66 67 syl ⊢ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5 → X ∈ V ∧ X = 1 y → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
69 65 68 mpan9 ⊢ K ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 ∧ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → X ∈ V ∧ X = 1 y → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
70 69 com12 ⊢ X ∈ V ∧ X = 1 y → K ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 ∧ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
71 70 adantr ⊢ X ∈ V ∧ X = 1 y ∧ N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 ∧ L ∈ 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
72 64 71 sylbid ⊢ X ∈ V ∧ X = 1 y ∧ N = 1 2 nd ⁡ X + 2 mod 5 0 2 nd ⁡ X 1 2 nd ⁡ X − 2 mod 5 → K ∈ N ∧ L ∈ N → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
73 60 72 mpdan ⊢ X ∈ V ∧ X = 1 y → K ∈ N ∧ L ∈ N → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
74 73 com12 ⊢ K ∈ N ∧ L ∈ N → X ∈ V ∧ X = 1 y → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
75 74 expd ⊢ K ∈ N ∧ L ∈ N → X ∈ V → X = 1 y → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
76 75 com23 ⊢ K ∈ N ∧ L ∈ N → X = 1 y → X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
77 76 com24 ⊢ K ∈ N ∧ L ∈ N → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → X ∈ V → X = 1 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
78 77 expd ⊢ K ∈ N ∧ L ∈ N → K ≠ L → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → X ∈ V → X = 1 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
79 78 3impia ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → X ∈ V → X = 1 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
80 79 expdimp ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 → y ∈ 0 ..^ 5 → X ∈ V → X = 1 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
81 80 com23 ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 → X ∈ V → y ∈ 0 ..^ 5 → X = 1 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
82 81 imp31 ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = 1 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
83 82 adantl ⊢ x = 1 ∧ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = 1 y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
84 52 83 sylbid ⊢ x = 1 ∧ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
85 84 ex ⊢ x = 1 → K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
86 49 85 jaoi ⊢ x = 0 ∨ x = 1 → K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
87 17 86 sylbi ⊢ x ∈ 0 1 → K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V ∧ y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
88 87 expd ⊢ x ∈ 0 1 → K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V → y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
89 88 com12 ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V → x ∈ 0 1 → y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
90 89 impd ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V → x ∈ 0 1 ∧ y ∈ 0 ..^ 5 → X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
91 90 rexlimdvv ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V → ∃ x ∈ 0 1 ∃ y ∈ 0 ..^ 5 X = x y → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
92 15 91 mpd ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 ∧ X ∈ V → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b
93 7 92 mpidan ⊢ K ∈ N ∧ L ∈ N ∧ K ≠ L ∧ b ∈ 0 ..^ 5 → K 1 b ∈ E ∧ 1 b L ∈ E → X = 1 b