Metamath Proof Explorer


Theorem pzriprnglem14

Description: Lemma 14 for pzriprng : The ring unity of the ring Q . (Contributed by AV, 23-Mar-2025)

Ref Expression
Hypotheses pzriprng.r ⊢ R = ℤ ring × 𝑠 ℤ ring
pzriprng.i ⊢ I = ℤ × 0
pzriprng.j ⊢ J = R ↾ 𝑠 I
pzriprng.1 ⊢ 1 ˙ = 1 J
pzriprng.g ⊢ ∼ ˙ = R ~ QG I
pzriprng.q ⊢ Q = R / 𝑠 ∼ ˙
Assertion pzriprnglem14 ⊢ 1 Q = ℤ × 1

Proof

Step Hyp Ref Expression
1 pzriprng.r ⊢ R = ℤ ring × 𝑠 ℤ ring
2 pzriprng.i ⊢ I = ℤ × 0
3 pzriprng.j ⊢ J = R ↾ 𝑠 I
4 pzriprng.1 ⊢ 1 ˙ = 1 J
5 pzriprng.g ⊢ ∼ ˙ = R ~ QG I
6 pzriprng.q ⊢ Q = R / 𝑠 ∼ ˙
7 1z ⊢ 1 ∈ ℤ
8 sneq ⊢ y = 1 → y = 1
9 8 xpeq2d ⊢ y = 1 → ℤ × y = ℤ × 1
10 9 sneqd ⊢ y = 1 → ℤ × y = ℤ × 1
11 10 eleq2d ⊢ y = 1 → ℤ × 1 ∈ ℤ × y ↔ ℤ × 1 ∈ ℤ × 1
12 id ⊢ 1 ∈ ℤ → 1 ∈ ℤ
13 zex ⊢ ℤ ∈ V
14 snex ⊢ 1 ∈ V
15 13 14 xpex ⊢ ℤ × 1 ∈ V
16 15 snid ⊢ ℤ × 1 ∈ ℤ × 1
17 16 a1i ⊢ 1 ∈ ℤ → ℤ × 1 ∈ ℤ × 1
18 11 12 17 rspcedvdw ⊢ 1 ∈ ℤ → ∃ y ∈ ℤ ℤ × 1 ∈ ℤ × y
19 7 18 ax-mp ⊢ ∃ y ∈ ℤ ℤ × 1 ∈ ℤ × y
20 1 2 3 4 5 6 pzriprnglem11 ⊢ Base Q = ⋃ y ∈ ℤ ℤ × y
21 20 eleq2i ⊢ ℤ × 1 ∈ Base Q ↔ ℤ × 1 ∈ ⋃ y ∈ ℤ ℤ × y
22 eliun ⊢ ℤ × 1 ∈ ⋃ y ∈ ℤ ℤ × y ↔ ∃ y ∈ ℤ ℤ × 1 ∈ ℤ × y
23 21 22 bitri ⊢ ℤ × 1 ∈ Base Q ↔ ∃ y ∈ ℤ ℤ × 1 ∈ ℤ × y
24 19 23 mpbir ⊢ ℤ × 1 ∈ Base Q
25 1 2 3 4 5 6 pzriprnglem12 ⊢ x ∈ Base Q → ℤ × 1 ⋅ Q x = x ∧ x ⋅ Q ℤ × 1 = x
26 25 rgen ⊢ ∀ x ∈ Base Q ℤ × 1 ⋅ Q x = x ∧ x ⋅ Q ℤ × 1 = x
27 24 26 pm3.2i ⊢ ℤ × 1 ∈ Base Q ∧ ∀ x ∈ Base Q ℤ × 1 ⋅ Q x = x ∧ x ⋅ Q ℤ × 1 = x
28 1 2 3 4 5 6 pzriprnglem13 ⊢ Q ∈ Ring
29 eqid ⊢ Base Q = Base Q
30 eqid ⊢ ⋅ Q = ⋅ Q
31 eqid ⊢ 1 Q = 1 Q
32 29 30 31 isringid ⊢ Q ∈ Ring → ℤ × 1 ∈ Base Q ∧ ∀ x ∈ Base Q ℤ × 1 ⋅ Q x = x ∧ x ⋅ Q ℤ × 1 = x ↔ 1 Q = ℤ × 1
33 28 32 ax-mp ⊢ ℤ × 1 ∈ Base Q ∧ ∀ x ∈ Base Q ℤ × 1 ⋅ Q x = x ∧ x ⋅ Q ℤ × 1 = x ↔ 1 Q = ℤ × 1
34 27 33 mpbi ⊢ 1 Q = ℤ × 1