Metamath Proof Explorer


Theorem sitg0

Description: The integral of the constant zero function is zero. (Contributed by Thierry Arnoux, 13-Mar-2018)

Ref Expression
Hypotheses sitgval.b ⊢ B = Base W
sitgval.j ⊢ J = TopOpen ⁡ W
sitgval.s ⊢ S = 𝛔 ⁡ J
sitgval.0 ⊢ 0 ˙ = 0 W
sitgval.x ⊢ · ˙ = ⋅ W
sitgval.h ⊢ H = ℝHom ⁡ Scalar ⁡ W
sitgval.1 ⊢ φ → W ∈ V
sitgval.2 ⊢ φ → M ∈ ⋃ ran ⁡ measures
sitg0.1 ⊢ φ → W ∈ TopSp
sitg0.2 ⊢ φ → W ∈ Mnd
Assertion sitg0 ⊢ φ → ∫ ℑ W ⋃ dom ⁡ M × 0 ˙ dM = 0 ˙

Proof

Step Hyp Ref Expression
1 sitgval.b ⊢ B = Base W
2 sitgval.j ⊢ J = TopOpen ⁡ W
3 sitgval.s ⊢ S = 𝛔 ⁡ J
4 sitgval.0 ⊢ 0 ˙ = 0 W
5 sitgval.x ⊢ · ˙ = ⋅ W
6 sitgval.h ⊢ H = ℝHom ⁡ Scalar ⁡ W
7 sitgval.1 ⊢ φ → W ∈ V
8 sitgval.2 ⊢ φ → M ∈ ⋃ ran ⁡ measures
9 sitg0.1 ⊢ φ → W ∈ TopSp
10 sitg0.2 ⊢ φ → W ∈ Mnd
11 1 2 3 4 5 6 7 8 9 10 sibf0 ⊢ φ → ⋃ dom ⁡ M × 0 ˙ ∈ ℑ M W
12 1 2 3 4 5 6 7 8 11 sitgfval ⊢ φ → ∫ ℑ W ⋃ dom ⁡ M × 0 ˙ dM = ∑ W x ∈ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x
13 rnxpss ⊢ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ⊆ 0 ˙
14 ssdif0 ⊢ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ⊆ 0 ˙ ↔ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ = ∅
15 13 14 mpbi ⊢ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ = ∅
16 mpteq1 ⊢ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ = ∅ → x ∈ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ ⟼ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x = x ∈ ∅ ⟼ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x
17 15 16 ax-mp ⊢ x ∈ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ ⟼ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x = x ∈ ∅ ⟼ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x
18 mpt0 ⊢ x ∈ ∅ ⟼ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x = ∅
19 17 18 eqtri ⊢ x ∈ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ ⟼ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x = ∅
20 19 oveq2i ⊢ ∑ W x ∈ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x = ∑ W ∅
21 4 gsum0 ⊢ ∑ W ∅ = 0 ˙
22 20 21 eqtri ⊢ ∑ W x ∈ ran ⁡ ⋃ dom ⁡ M × 0 ˙ ∖ 0 ˙ H ⁡ M ⁡ ⋃ dom ⁡ M × 0 ˙ -1 x · ˙ x = 0 ˙
23 12 22 eqtrdi ⊢ φ → ∫ ℑ W ⋃ dom ⁡ M × 0 ˙ dM = 0 ˙