Metamath Proof Explorer


Theorem ssblex

Description: A nested ball exists whose radius is less than any desired amount. (Contributed by NM, 20-Sep-2007) (Revised by Mario Carneiro, 12-Nov-2013)

Ref Expression
Assertion ssblex ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → ∃ x ∈ ℝ + x < R ∧ P ball ⁡ D x ⊆ P ball ⁡ D S

Proof

Step Hyp Ref Expression
1 simprl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → R ∈ ℝ +
2 1 rphalfcld ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → R 2 ∈ ℝ +
3 simprr ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → S ∈ ℝ +
4 2 3 ifcld ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → if R 2 ≤ S R 2 S ∈ ℝ +
5 4 rpred ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → if R 2 ≤ S R 2 S ∈ ℝ
6 2 rpred ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → R 2 ∈ ℝ
7 1 rpred ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → R ∈ ℝ
8 3 rpred ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → S ∈ ℝ
9 min1 ⊢ R 2 ∈ ℝ ∧ S ∈ ℝ → if R 2 ≤ S R 2 S ≤ R 2
10 6 8 9 syl2anc ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → if R 2 ≤ S R 2 S ≤ R 2
11 1 rpgt0d ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → 0 < R
12 halfpos ⊢ R ∈ ℝ → 0 < R ↔ R 2 < R
13 7 12 syl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → 0 < R ↔ R 2 < R
14 11 13 mpbid ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → R 2 < R
15 5 6 7 10 14 lelttrd ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → if R 2 ≤ S R 2 S < R
16 simpl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → D ∈ ∞Met ⁡ X ∧ P ∈ X
17 4 rpxrd ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → if R 2 ≤ S R 2 S ∈ ℝ *
18 3 rpxrd ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → S ∈ ℝ *
19 min2 ⊢ R 2 ∈ ℝ ∧ S ∈ ℝ → if R 2 ≤ S R 2 S ≤ S
20 6 8 19 syl2anc ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → if R 2 ≤ S R 2 S ≤ S
21 ssbl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ if R 2 ≤ S R 2 S ∈ ℝ * ∧ S ∈ ℝ * ∧ if R 2 ≤ S R 2 S ≤ S → P ball ⁡ D if R 2 ≤ S R 2 S ⊆ P ball ⁡ D S
22 16 17 18 20 21 syl121anc ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → P ball ⁡ D if R 2 ≤ S R 2 S ⊆ P ball ⁡ D S
23 breq1 ⊢ x = if R 2 ≤ S R 2 S → x < R ↔ if R 2 ≤ S R 2 S < R
24 oveq2 ⊢ x = if R 2 ≤ S R 2 S → P ball ⁡ D x = P ball ⁡ D if R 2 ≤ S R 2 S
25 24 sseq1d ⊢ x = if R 2 ≤ S R 2 S → P ball ⁡ D x ⊆ P ball ⁡ D S ↔ P ball ⁡ D if R 2 ≤ S R 2 S ⊆ P ball ⁡ D S
26 23 25 anbi12d ⊢ x = if R 2 ≤ S R 2 S → x < R ∧ P ball ⁡ D x ⊆ P ball ⁡ D S ↔ if R 2 ≤ S R 2 S < R ∧ P ball ⁡ D if R 2 ≤ S R 2 S ⊆ P ball ⁡ D S
27 26 rspcev ⊢ if R 2 ≤ S R 2 S ∈ ℝ + ∧ if R 2 ≤ S R 2 S < R ∧ P ball ⁡ D if R 2 ≤ S R 2 S ⊆ P ball ⁡ D S → ∃ x ∈ ℝ + x < R ∧ P ball ⁡ D x ⊆ P ball ⁡ D S
28 4 15 22 27 syl12anc ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ + ∧ S ∈ ℝ + → ∃ x ∈ ℝ + x < R ∧ P ball ⁡ D x ⊆ P ball ⁡ D S