Metamath Proof Explorer


Theorem trirn

Description: Triangle inequality in R^n. (Contributed by Jeff Madsen, 2-Sep-2009) (Revised by Mario Carneiro, 4-Jun-2014)

Ref Expression
Hypotheses csbrn.1 ⊢ φ → A ∈ Fin
csbrn.2 ⊢ φ ∧ k ∈ A → B ∈ ℝ
csbrn.3 ⊢ φ ∧ k ∈ A → C ∈ ℝ
Assertion trirn ⊢ φ → ∑ k ∈ A B + C 2 ≤ ∑ k ∈ A B 2 + ∑ k ∈ A C 2

Proof

Step Hyp Ref Expression
1 csbrn.1 ⊢ φ → A ∈ Fin
2 csbrn.2 ⊢ φ ∧ k ∈ A → B ∈ ℝ
3 csbrn.3 ⊢ φ ∧ k ∈ A → C ∈ ℝ
4 2 resqcld ⊢ φ ∧ k ∈ A → B 2 ∈ ℝ
5 2re ⊢ 2 ∈ ℝ
6 2 3 remulcld ⊢ φ ∧ k ∈ A → B ⁢ C ∈ ℝ
7 remulcl ⊢ 2 ∈ ℝ ∧ B ⁢ C ∈ ℝ → 2 ⁢ B ⁢ C ∈ ℝ
8 5 6 7 sylancr ⊢ φ ∧ k ∈ A → 2 ⁢ B ⁢ C ∈ ℝ
9 4 8 readdcld ⊢ φ ∧ k ∈ A → B 2 + 2 ⁢ B ⁢ C ∈ ℝ
10 1 9 fsumrecl ⊢ φ → ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C ∈ ℝ
11 1 4 fsumrecl ⊢ φ → ∑ k ∈ A B 2 ∈ ℝ
12 3 resqcld ⊢ φ ∧ k ∈ A → C 2 ∈ ℝ
13 1 12 fsumrecl ⊢ φ → ∑ k ∈ A C 2 ∈ ℝ
14 11 13 remulcld ⊢ φ → ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ
15 2 sqge0d ⊢ φ ∧ k ∈ A → 0 ≤ B 2
16 1 4 15 fsumge0 ⊢ φ → 0 ≤ ∑ k ∈ A B 2
17 3 sqge0d ⊢ φ ∧ k ∈ A → 0 ≤ C 2
18 1 12 17 fsumge0 ⊢ φ → 0 ≤ ∑ k ∈ A C 2
19 11 13 16 18 mulge0d ⊢ φ → 0 ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
20 14 19 resqrtcld ⊢ φ → ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ
21 remulcl ⊢ 2 ∈ ℝ ∧ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ → 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ
22 5 20 21 sylancr ⊢ φ → 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ
23 11 22 readdcld ⊢ φ → ∑ k ∈ A B 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ
24 4 recnd ⊢ φ ∧ k ∈ A → B 2 ∈ ℂ
25 8 recnd ⊢ φ ∧ k ∈ A → 2 ⁢ B ⁢ C ∈ ℂ
26 1 24 25 fsumadd ⊢ φ → ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C = ∑ k ∈ A B 2 + ∑ k ∈ A 2 ⁢ B ⁢ C
27 1 8 fsumrecl ⊢ φ → ∑ k ∈ A 2 ⁢ B ⁢ C ∈ ℝ
28 2cnd ⊢ φ → 2 ∈ ℂ
29 6 recnd ⊢ φ ∧ k ∈ A → B ⁢ C ∈ ℂ
30 1 28 29 fsummulc2 ⊢ φ → 2 ⁢ ∑ k ∈ A B ⁢ C = ∑ k ∈ A 2 ⁢ B ⁢ C
31 1 6 fsumrecl ⊢ φ → ∑ k ∈ A B ⁢ C ∈ ℝ
32 31 recnd ⊢ φ → ∑ k ∈ A B ⁢ C ∈ ℂ
33 32 abscld ⊢ φ → ∑ k ∈ A B ⁢ C ∈ ℝ
34 31 leabsd ⊢ φ → ∑ k ∈ A B ⁢ C ≤ ∑ k ∈ A B ⁢ C
35 1 2 3 csbren ⊢ φ → ∑ k ∈ A B ⁢ C 2 ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
36 absresq ⊢ ∑ k ∈ A B ⁢ C ∈ ℝ → ∑ k ∈ A B ⁢ C 2 = ∑ k ∈ A B ⁢ C 2
37 31 36 syl ⊢ φ → ∑ k ∈ A B ⁢ C 2 = ∑ k ∈ A B ⁢ C 2
38 resqrtth ⊢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ ∧ 0 ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 → ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 2 = ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
39 14 19 38 syl2anc ⊢ φ → ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 2 = ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
40 35 37 39 3brtr4d ⊢ φ → ∑ k ∈ A B ⁢ C 2 ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 2
41 32 absge0d ⊢ φ → 0 ≤ ∑ k ∈ A B ⁢ C
42 14 19 sqrtge0d ⊢ φ → 0 ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
43 33 20 41 42 le2sqd ⊢ φ → ∑ k ∈ A B ⁢ C ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ↔ ∑ k ∈ A B ⁢ C 2 ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 2
44 40 43 mpbird ⊢ φ → ∑ k ∈ A B ⁢ C ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
45 31 33 20 34 44 letrd ⊢ φ → ∑ k ∈ A B ⁢ C ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
46 5 a1i ⊢ φ → 2 ∈ ℝ
47 2pos ⊢ 0 < 2
48 47 a1i ⊢ φ → 0 < 2
49 lemul2 ⊢ ∑ k ∈ A B ⁢ C ∈ ℝ ∧ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ∈ ℝ ∧ 2 ∈ ℝ ∧ 0 < 2 → ∑ k ∈ A B ⁢ C ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ↔ 2 ⁢ ∑ k ∈ A B ⁢ C ≤ 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
50 31 20 46 48 49 syl112anc ⊢ φ → ∑ k ∈ A B ⁢ C ≤ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 ↔ 2 ⁢ ∑ k ∈ A B ⁢ C ≤ 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
51 45 50 mpbid ⊢ φ → 2 ⁢ ∑ k ∈ A B ⁢ C ≤ 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
52 30 51 eqbrtrrd ⊢ φ → ∑ k ∈ A 2 ⁢ B ⁢ C ≤ 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
53 27 22 11 52 leadd2dd ⊢ φ → ∑ k ∈ A B 2 + ∑ k ∈ A 2 ⁢ B ⁢ C ≤ ∑ k ∈ A B 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
54 26 53 eqbrtrd ⊢ φ → ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C ≤ ∑ k ∈ A B 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
55 10 23 13 54 leadd1dd ⊢ φ → ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C + ∑ k ∈ A C 2 ≤ ∑ k ∈ A B 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 + ∑ k ∈ A C 2
56 2 3 readdcld ⊢ φ ∧ k ∈ A → B + C ∈ ℝ
57 56 resqcld ⊢ φ ∧ k ∈ A → B + C 2 ∈ ℝ
58 1 57 fsumrecl ⊢ φ → ∑ k ∈ A B + C 2 ∈ ℝ
59 56 sqge0d ⊢ φ ∧ k ∈ A → 0 ≤ B + C 2
60 1 57 59 fsumge0 ⊢ φ → 0 ≤ ∑ k ∈ A B + C 2
61 resqrtth ⊢ ∑ k ∈ A B + C 2 ∈ ℝ ∧ 0 ≤ ∑ k ∈ A B + C 2 → ∑ k ∈ A B + C 2 2 = ∑ k ∈ A B + C 2
62 58 60 61 syl2anc ⊢ φ → ∑ k ∈ A B + C 2 2 = ∑ k ∈ A B + C 2
63 2 recnd ⊢ φ ∧ k ∈ A → B ∈ ℂ
64 3 recnd ⊢ φ ∧ k ∈ A → C ∈ ℂ
65 binom2 ⊢ B ∈ ℂ ∧ C ∈ ℂ → B + C 2 = B 2 + 2 ⁢ B ⁢ C + C 2
66 63 64 65 syl2anc ⊢ φ ∧ k ∈ A → B + C 2 = B 2 + 2 ⁢ B ⁢ C + C 2
67 66 sumeq2dv ⊢ φ → ∑ k ∈ A B + C 2 = ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C + C 2
68 9 recnd ⊢ φ ∧ k ∈ A → B 2 + 2 ⁢ B ⁢ C ∈ ℂ
69 12 recnd ⊢ φ ∧ k ∈ A → C 2 ∈ ℂ
70 1 68 69 fsumadd ⊢ φ → ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C + C 2 = ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C + ∑ k ∈ A C 2
71 67 70 eqtrd ⊢ φ → ∑ k ∈ A B + C 2 = ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C + ∑ k ∈ A C 2
72 62 71 eqtrd ⊢ φ → ∑ k ∈ A B + C 2 2 = ∑ k ∈ A B 2 + 2 ⁢ B ⁢ C + ∑ k ∈ A C 2
73 11 16 resqrtcld ⊢ φ → ∑ k ∈ A B 2 ∈ ℝ
74 73 recnd ⊢ φ → ∑ k ∈ A B 2 ∈ ℂ
75 13 18 resqrtcld ⊢ φ → ∑ k ∈ A C 2 ∈ ℝ
76 75 recnd ⊢ φ → ∑ k ∈ A C 2 ∈ ℂ
77 binom2 ⊢ ∑ k ∈ A B 2 ∈ ℂ ∧ ∑ k ∈ A C 2 ∈ ℂ → ∑ k ∈ A B 2 + ∑ k ∈ A C 2 2 = ∑ k ∈ A B 2 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 + ∑ k ∈ A C 2 2
78 74 76 77 syl2anc ⊢ φ → ∑ k ∈ A B 2 + ∑ k ∈ A C 2 2 = ∑ k ∈ A B 2 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 + ∑ k ∈ A C 2 2
79 resqrtth ⊢ ∑ k ∈ A B 2 ∈ ℝ ∧ 0 ≤ ∑ k ∈ A B 2 → ∑ k ∈ A B 2 2 = ∑ k ∈ A B 2
80 11 16 79 syl2anc ⊢ φ → ∑ k ∈ A B 2 2 = ∑ k ∈ A B 2
81 11 16 13 18 sqrtmuld ⊢ φ → ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 = ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
82 81 eqcomd ⊢ φ → ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 = ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
83 82 oveq2d ⊢ φ → 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 = 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
84 80 83 oveq12d ⊢ φ → ∑ k ∈ A B 2 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 = ∑ k ∈ A B 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2
85 resqrtth ⊢ ∑ k ∈ A C 2 ∈ ℝ ∧ 0 ≤ ∑ k ∈ A C 2 → ∑ k ∈ A C 2 2 = ∑ k ∈ A C 2
86 13 18 85 syl2anc ⊢ φ → ∑ k ∈ A C 2 2 = ∑ k ∈ A C 2
87 84 86 oveq12d ⊢ φ → ∑ k ∈ A B 2 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 + ∑ k ∈ A C 2 2 = ∑ k ∈ A B 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 + ∑ k ∈ A C 2
88 78 87 eqtrd ⊢ φ → ∑ k ∈ A B 2 + ∑ k ∈ A C 2 2 = ∑ k ∈ A B 2 + 2 ⁢ ∑ k ∈ A B 2 ⁢ ∑ k ∈ A C 2 + ∑ k ∈ A C 2
89 55 72 88 3brtr4d ⊢ φ → ∑ k ∈ A B + C 2 2 ≤ ∑ k ∈ A B 2 + ∑ k ∈ A C 2 2
90 58 60 resqrtcld ⊢ φ → ∑ k ∈ A B + C 2 ∈ ℝ
91 73 75 readdcld ⊢ φ → ∑ k ∈ A B 2 + ∑ k ∈ A C 2 ∈ ℝ
92 58 60 sqrtge0d ⊢ φ → 0 ≤ ∑ k ∈ A B + C 2
93 11 16 sqrtge0d ⊢ φ → 0 ≤ ∑ k ∈ A B 2
94 13 18 sqrtge0d ⊢ φ → 0 ≤ ∑ k ∈ A C 2
95 73 75 93 94 addge0d ⊢ φ → 0 ≤ ∑ k ∈ A B 2 + ∑ k ∈ A C 2
96 90 91 92 95 le2sqd ⊢ φ → ∑ k ∈ A B + C 2 ≤ ∑ k ∈ A B 2 + ∑ k ∈ A C 2 ↔ ∑ k ∈ A B + C 2 2 ≤ ∑ k ∈ A B 2 + ∑ k ∈ A C 2 2
97 89 96 mpbird ⊢ φ → ∑ k ∈ A B + C 2 ≤ ∑ k ∈ A B 2 + ∑ k ∈ A C 2