Metamath Proof Explorer


Theorem 0.999...

Description: The recurring decimal 0.999..., which is defined as the infinite sum 0.9 + 0.09 + 0.009 + ... i.e. 9 / 1 0 ^ 1 + 9 / 1 0 ^ 2 + 9 / 1 0 ^ 3 + ... , is exactly equal to 1, according to ZF set theory. Interestingly, about 40% of the people responding to a poll at http://forum.physorg.com/index.php?showtopic=13177 disagree. (Contributed by NM, 2-Nov-2007) (Revised by AV, 8-Sep-2021)

Ref Expression
Assertion 0.999... ⊢ ∑ k ∈ ℕ 9 10 k = 1

Proof

Step Hyp Ref Expression
1 9cn ⊢ 9 ∈ ℂ
2 10re ⊢ 10 ∈ ℝ
3 2 recni ⊢ 10 ∈ ℂ
4 nnnn0 ⊢ k ∈ ℕ → k ∈ ℕ 0
5 expcl ⊢ 10 ∈ ℂ ∧ k ∈ ℕ 0 → 10 k ∈ ℂ
6 3 4 5 sylancr ⊢ k ∈ ℕ → 10 k ∈ ℂ
7 3 a1i ⊢ k ∈ ℕ → 10 ∈ ℂ
8 10pos ⊢ 0 < 10
9 2 8 gt0ne0ii ⊢ 10 ≠ 0
10 9 a1i ⊢ k ∈ ℕ → 10 ≠ 0
11 nnz ⊢ k ∈ ℕ → k ∈ ℤ
12 7 10 11 expne0d ⊢ k ∈ ℕ → 10 k ≠ 0
13 divrec ⊢ 9 ∈ ℂ ∧ 10 k ∈ ℂ ∧ 10 k ≠ 0 → 9 10 k = 9 ⁢ 1 10 k
14 1 6 12 13 mp3an2i ⊢ k ∈ ℕ → 9 10 k = 9 ⁢ 1 10 k
15 7 10 11 exprecd ⊢ k ∈ ℕ → 1 10 k = 1 10 k
16 15 oveq2d ⊢ k ∈ ℕ → 9 ⁢ 1 10 k = 9 ⁢ 1 10 k
17 14 16 eqtr4d ⊢ k ∈ ℕ → 9 10 k = 9 ⁢ 1 10 k
18 17 sumeq2i ⊢ ∑ k ∈ ℕ 9 10 k = ∑ k ∈ ℕ 9 ⁢ 1 10 k
19 2 9 rereccli ⊢ 1 10 ∈ ℝ
20 19 recni ⊢ 1 10 ∈ ℂ
21 0re ⊢ 0 ∈ ℝ
22 2 8 recgt0ii ⊢ 0 < 1 10
23 21 19 22 ltleii ⊢ 0 ≤ 1 10
24 19 absidi ⊢ 0 ≤ 1 10 → 1 10 = 1 10
25 23 24 ax-mp ⊢ 1 10 = 1 10
26 1lt10 ⊢ 1 < 10
27 recgt1 ⊢ 10 ∈ ℝ ∧ 0 < 10 → 1 < 10 ↔ 1 10 < 1
28 2 8 27 mp2an ⊢ 1 < 10 ↔ 1 10 < 1
29 26 28 mpbi ⊢ 1 10 < 1
30 25 29 eqbrtri ⊢ 1 10 < 1
31 geoisum1c ⊢ 9 ∈ ℂ ∧ 1 10 ∈ ℂ ∧ 1 10 < 1 → ∑ k ∈ ℕ 9 ⁢ 1 10 k = 9 ⁢ 1 10 1 − 1 10
32 1 20 30 31 mp3an ⊢ ∑ k ∈ ℕ 9 ⁢ 1 10 k = 9 ⁢ 1 10 1 − 1 10
33 1 3 9 divreci ⊢ 9 10 = 9 ⁢ 1 10
34 1 3 9 divcan2i ⊢ 10 ⁢ 9 10 = 9
35 ax-1cn ⊢ 1 ∈ ℂ
36 3 35 20 subdii ⊢ 10 ⁢ 1 − 1 10 = 10 ⋅ 1 − 10 ⁢ 1 10
37 3 mulridi ⊢ 10 ⋅ 1 = 10
38 3 9 recidi ⊢ 10 ⁢ 1 10 = 1
39 37 38 oveq12i ⊢ 10 ⋅ 1 − 10 ⁢ 1 10 = 10 − 1
40 10m1e9 ⊢ 10 − 1 = 9
41 36 39 40 3eqtrri ⊢ 9 = 10 ⁢ 1 − 1 10
42 34 41 eqtri ⊢ 10 ⁢ 9 10 = 10 ⁢ 1 − 1 10
43 9re ⊢ 9 ∈ ℝ
44 43 2 9 redivcli ⊢ 9 10 ∈ ℝ
45 44 recni ⊢ 9 10 ∈ ℂ
46 35 20 subcli ⊢ 1 − 1 10 ∈ ℂ
47 45 46 3 9 mulcani ⊢ 10 ⁢ 9 10 = 10 ⁢ 1 − 1 10 ↔ 9 10 = 1 − 1 10
48 42 47 mpbi ⊢ 9 10 = 1 − 1 10
49 33 48 oveq12i ⊢ 9 10 9 10 = 9 ⁢ 1 10 1 − 1 10
50 9pos ⊢ 0 < 9
51 43 2 50 8 divgt0ii ⊢ 0 < 9 10
52 44 51 gt0ne0ii ⊢ 9 10 ≠ 0
53 45 52 dividi ⊢ 9 10 9 10 = 1
54 32 49 53 3eqtr2i ⊢ ∑ k ∈ ℕ 9 ⁢ 1 10 k = 1
55 18 54 eqtri ⊢ ∑ k ∈ ℕ 9 10 k = 1