Metamath Proof Explorer


Theorem axrnegex

Description: Existence of negative of real number. Axiom 15 of 22 for real and complex numbers, derived from ZF set theory. This construction-dependent theorem should not be referenced directly; instead, use ax-rnegex . (Contributed by NM, 15-May-1996) (New usage is discouraged.)

Ref Expression
Assertion axrnegex ⊢ A ∈ ℝ → ∃ x ∈ ℝ A + x = 0

Proof

Step Hyp Ref Expression
1 elreal2 ⊢ A ∈ ℝ ↔ 1 st ⁡ A ∈ 𝑹 ∧ A = 1 st ⁡ A 0 𝑹
2 1 simplbi ⊢ A ∈ ℝ → 1 st ⁡ A ∈ 𝑹
3 m1r ⊢ -1 𝑹 ∈ 𝑹
4 mulclsr ⊢ 1 st ⁡ A ∈ 𝑹 ∧ -1 𝑹 ∈ 𝑹 → 1 st ⁡ A ⋅ 𝑹 -1 𝑹 ∈ 𝑹
5 2 3 4 sylancl ⊢ A ∈ ℝ → 1 st ⁡ A ⋅ 𝑹 -1 𝑹 ∈ 𝑹
6 opelreal ⊢ 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 ∈ ℝ ↔ 1 st ⁡ A ⋅ 𝑹 -1 𝑹 ∈ 𝑹
7 5 6 sylibr ⊢ A ∈ ℝ → 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 ∈ ℝ
8 1 simprbi ⊢ A ∈ ℝ → A = 1 st ⁡ A 0 𝑹
9 8 oveq1d ⊢ A ∈ ℝ → A + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 1 st ⁡ A 0 𝑹 + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹
10 addresr ⊢ 1 st ⁡ A ∈ 𝑹 ∧ 1 st ⁡ A ⋅ 𝑹 -1 𝑹 ∈ 𝑹 → 1 st ⁡ A 0 𝑹 + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 1 st ⁡ A + 𝑹 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹
11 2 5 10 syl2anc ⊢ A ∈ ℝ → 1 st ⁡ A 0 𝑹 + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 1 st ⁡ A + 𝑹 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹
12 pn0sr ⊢ 1 st ⁡ A ∈ 𝑹 → 1 st ⁡ A + 𝑹 1 st ⁡ A ⋅ 𝑹 -1 𝑹 = 0 𝑹
13 12 opeq1d ⊢ 1 st ⁡ A ∈ 𝑹 → 1 st ⁡ A + 𝑹 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 0 𝑹 0 𝑹
14 df-0 ⊢ 0 = 0 𝑹 0 𝑹
15 13 14 eqtr4di ⊢ 1 st ⁡ A ∈ 𝑹 → 1 st ⁡ A + 𝑹 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 0
16 2 15 syl ⊢ A ∈ ℝ → 1 st ⁡ A + 𝑹 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 0
17 9 11 16 3eqtrd ⊢ A ∈ ℝ → A + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 0
18 oveq2 ⊢ x = 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 → A + x = A + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹
19 18 eqeq1d ⊢ x = 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 → A + x = 0 ↔ A + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 0
20 19 rspcev ⊢ 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 ∈ ℝ ∧ A + 1 st ⁡ A ⋅ 𝑹 -1 𝑹 0 𝑹 = 0 → ∃ x ∈ ℝ A + x = 0
21 7 17 20 syl2anc ⊢ A ∈ ℝ → ∃ x ∈ ℝ A + x = 0