Metamath Proof Explorer


Theorem bday1

Description: The birthday of surreal one is ordinal one. (Contributed by Scott Fenton, 8-Aug-2024)

Ref Expression
Assertion bday1 ⊢ bday ⁡ 1 s = 1 𝑜

Proof

Step Hyp Ref Expression
1 df-1s ⊢ 1 s = 0 s | s ∅
2 1 fveq2i ⊢ bday ⁡ 1 s = bday ⁡ 0 s | s ∅
3 0no ⊢ 0 s ∈ No
4 snelpwi ⊢ 0 s ∈ No → 0 s ∈ 𝒫 No
5 3 4 ax-mp ⊢ 0 s ∈ 𝒫 No
6 nulsgts ⊢ 0 s ∈ 𝒫 No → 0 s ≪ s ∅
7 5 6 ax-mp ⊢ 0 s ≪ s ∅
8 cutbdaybnd2 ⊢ 0 s ≪ s ∅ → bday ⁡ 0 s | s ∅ ⊆ suc ⁡ ⋃ bday 0 s ∪ ∅
9 7 8 ax-mp ⊢ bday ⁡ 0 s | s ∅ ⊆ suc ⁡ ⋃ bday 0 s ∪ ∅
10 un0 ⊢ 0 s ∪ ∅ = 0 s
11 10 imaeq2i ⊢ bday 0 s ∪ ∅ = bday 0 s
12 bdayfn ⊢ bday Fn No
13 fnsnfv ⊢ bday Fn No ∧ 0 s ∈ No → bday ⁡ 0 s = bday 0 s
14 12 3 13 mp2an ⊢ bday ⁡ 0 s = bday 0 s
15 bday0 ⊢ bday ⁡ 0 s = ∅
16 15 sneqi ⊢ bday ⁡ 0 s = ∅
17 11 14 16 3eqtr2i ⊢ bday 0 s ∪ ∅ = ∅
18 17 unieqi ⊢ ⋃ bday 0 s ∪ ∅ = ⋃ ∅
19 0ex ⊢ ∅ ∈ V
20 19 unisn ⊢ ⋃ ∅ = ∅
21 18 20 eqtri ⊢ ⋃ bday 0 s ∪ ∅ = ∅
22 suceq ⊢ ⋃ bday 0 s ∪ ∅ = ∅ → suc ⁡ ⋃ bday 0 s ∪ ∅ = suc ⁡ ∅
23 21 22 ax-mp ⊢ suc ⁡ ⋃ bday 0 s ∪ ∅ = suc ⁡ ∅
24 df-1o ⊢ 1 𝑜 = suc ⁡ ∅
25 23 24 eqtr4i ⊢ suc ⁡ ⋃ bday 0 s ∪ ∅ = 1 𝑜
26 9 25 sseqtri ⊢ bday ⁡ 0 s | s ∅ ⊆ 1 𝑜
27 ssrab2 ⊢ x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ ⊆ No
28 fnssintima ⊢ bday Fn No ∧ x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ ⊆ No → 1 𝑜 ⊆ ⋂ bday x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ ↔ ∀ y ∈ x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ 1 𝑜 ⊆ bday ⁡ y
29 12 27 28 mp2an ⊢ 1 𝑜 ⊆ ⋂ bday x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ ↔ ∀ y ∈ x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ 1 𝑜 ⊆ bday ⁡ y
30 sneq ⊢ x = y → x = y
31 30 breq2d ⊢ x = y → 0 s ≪ s x ↔ 0 s ≪ s y
32 30 breq1d ⊢ x = y → x ≪ s ∅ ↔ y ≪ s ∅
33 31 32 anbi12d ⊢ x = y → 0 s ≪ s x ∧ x ≪ s ∅ ↔ 0 s ≪ s y ∧ y ≪ s ∅
34 33 elrab ⊢ y ∈ x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ ↔ y ∈ No ∧ 0 s ≪ s y ∧ y ≪ s ∅
35 ltsirr ⊢ 0 s ∈ No → ¬ 0 s < s 0 s
36 3 35 ax-mp ⊢ ¬ 0 s < s 0 s
37 breq2 ⊢ y = 0 s → 0 s < s y ↔ 0 s < s 0 s
38 36 37 mtbiri ⊢ y = 0 s → ¬ 0 s < s y
39 38 necon2ai ⊢ 0 s < s y → y ≠ 0 s
40 bday0b ⊢ y ∈ No → bday ⁡ y = ∅ ↔ y = 0 s
41 40 necon3bid ⊢ y ∈ No → bday ⁡ y ≠ ∅ ↔ y ≠ 0 s
42 39 41 imbitrrid ⊢ y ∈ No → 0 s < s y → bday ⁡ y ≠ ∅
43 bdayon ⊢ bday ⁡ y ∈ On
44 43 onordi ⊢ Ord ⁡ bday ⁡ y
45 ordge1n0 ⊢ Ord ⁡ bday ⁡ y → 1 𝑜 ⊆ bday ⁡ y ↔ bday ⁡ y ≠ ∅
46 44 45 ax-mp ⊢ 1 𝑜 ⊆ bday ⁡ y ↔ bday ⁡ y ≠ ∅
47 42 46 imbitrrdi ⊢ y ∈ No → 0 s < s y → 1 𝑜 ⊆ bday ⁡ y
48 sltssep ⊢ 0 s ≪ s y → ∀ x ∈ 0 s ∀ z ∈ y x < s z
49 vex ⊢ y ∈ V
50 breq2 ⊢ z = y → x < s z ↔ x < s y
51 49 50 ralsn ⊢ ∀ z ∈ y x < s z ↔ x < s y
52 51 ralbii ⊢ ∀ x ∈ 0 s ∀ z ∈ y x < s z ↔ ∀ x ∈ 0 s x < s y
53 3 elexi ⊢ 0 s ∈ V
54 breq1 ⊢ x = 0 s → x < s y ↔ 0 s < s y
55 53 54 ralsn ⊢ ∀ x ∈ 0 s x < s y ↔ 0 s < s y
56 52 55 bitri ⊢ ∀ x ∈ 0 s ∀ z ∈ y x < s z ↔ 0 s < s y
57 48 56 sylib ⊢ 0 s ≪ s y → 0 s < s y
58 47 57 impel ⊢ y ∈ No ∧ 0 s ≪ s y → 1 𝑜 ⊆ bday ⁡ y
59 58 adantrr ⊢ y ∈ No ∧ 0 s ≪ s y ∧ y ≪ s ∅ → 1 𝑜 ⊆ bday ⁡ y
60 34 59 sylbi ⊢ y ∈ x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅ → 1 𝑜 ⊆ bday ⁡ y
61 29 60 mprgbir ⊢ 1 𝑜 ⊆ ⋂ bday x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅
62 cutbday ⊢ 0 s ≪ s ∅ → bday ⁡ 0 s | s ∅ = ⋂ bday x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅
63 7 62 ax-mp ⊢ bday ⁡ 0 s | s ∅ = ⋂ bday x ∈ No | 0 s ≪ s x ∧ x ≪ s ∅
64 61 63 sseqtrri ⊢ 1 𝑜 ⊆ bday ⁡ 0 s | s ∅
65 26 64 eqssi ⊢ bday ⁡ 0 s | s ∅ = 1 𝑜
66 2 65 eqtri ⊢ bday ⁡ 1 s = 1 𝑜