Metamath Proof Explorer


Theorem fltne

Description: If a counterexample to FLT exists, its addends are not equal. (Contributed by SN, 1-Jun-2023)

Ref Expression
Hypotheses fltne.a ⊢ φ → A ∈ ℕ
fltne.b ⊢ φ → B ∈ ℕ
fltne.c ⊢ φ → C ∈ ℕ
fltne.n ⊢ φ → N ∈ ℤ ≥ 2
fltne.1 ⊢ φ → A N + B N = C N
Assertion fltne ⊢ φ → A ≠ B

Proof

Step Hyp Ref Expression
1 fltne.a ⊢ φ → A ∈ ℕ
2 fltne.b ⊢ φ → B ∈ ℕ
3 fltne.c ⊢ φ → C ∈ ℕ
4 fltne.n ⊢ φ → N ∈ ℤ ≥ 2
5 fltne.1 ⊢ φ → A N + B N = C N
6 2prm ⊢ 2 ∈ ℙ
7 rtprmirr ⊢ 2 ∈ ℙ ∧ N ∈ ℤ ≥ 2 → 2 1 N ∈ ℝ ∖ ℚ
8 6 4 7 sylancr ⊢ φ → 2 1 N ∈ ℝ ∖ ℚ
9 8 eldifbd ⊢ φ → ¬ 2 1 N ∈ ℚ
10 3 nnzd ⊢ φ → C ∈ ℤ
11 znq ⊢ C ∈ ℤ ∧ A ∈ ℕ → C A ∈ ℚ
12 10 1 11 syl2anc ⊢ φ → C A ∈ ℚ
13 eleq1a ⊢ C A ∈ ℚ → 2 1 N = C A → 2 1 N ∈ ℚ
14 12 13 syl ⊢ φ → 2 1 N = C A → 2 1 N ∈ ℚ
15 14 necon3bd ⊢ φ → ¬ 2 1 N ∈ ℚ → 2 1 N ≠ C A
16 9 15 mpd ⊢ φ → 2 1 N ≠ C A
17 2rp ⊢ 2 ∈ ℝ +
18 17 a1i ⊢ φ → 2 ∈ ℝ +
19 eluz2nn ⊢ N ∈ ℤ ≥ 2 → N ∈ ℕ
20 4 19 syl ⊢ φ → N ∈ ℕ
21 20 nnrecred ⊢ φ → 1 N ∈ ℝ
22 18 21 rpcxpcld ⊢ φ → 2 1 N ∈ ℝ +
23 22 adantr ⊢ φ ∧ A = B → 2 1 N ∈ ℝ +
24 3 nnrpd ⊢ φ → C ∈ ℝ +
25 1 nnrpd ⊢ φ → A ∈ ℝ +
26 24 25 rpdivcld ⊢ φ → C A ∈ ℝ +
27 26 adantr ⊢ φ ∧ A = B → C A ∈ ℝ +
28 20 adantr ⊢ φ ∧ A = B → N ∈ ℕ
29 20 nnnn0d ⊢ φ → N ∈ ℕ 0
30 1 29 nnexpcld ⊢ φ → A N ∈ ℕ
31 30 adantr ⊢ φ ∧ A = B → A N ∈ ℕ
32 31 nncnd ⊢ φ ∧ A = B → A N ∈ ℂ
33 2cnd ⊢ φ ∧ A = B → 2 ∈ ℂ
34 31 nnne0d ⊢ φ ∧ A = B → A N ≠ 0
35 30 nncnd ⊢ φ → A N ∈ ℂ
36 35 times2d ⊢ φ → A N ⋅ 2 = A N + A N
37 36 adantr ⊢ φ ∧ A = B → A N ⋅ 2 = A N + A N
38 simpr ⊢ φ ∧ A = B → A = B
39 38 oveq1d ⊢ φ ∧ A = B → A N = B N
40 39 oveq2d ⊢ φ ∧ A = B → A N + A N = A N + B N
41 5 adantr ⊢ φ ∧ A = B → A N + B N = C N
42 37 40 41 3eqtrd ⊢ φ ∧ A = B → A N ⋅ 2 = C N
43 32 33 34 42 mvllmuld ⊢ φ ∧ A = B → 2 = C N A N
44 2cn ⊢ 2 ∈ ℂ
45 cxproot ⊢ 2 ∈ ℂ ∧ N ∈ ℕ → 2 1 N N = 2
46 44 20 45 sylancr ⊢ φ → 2 1 N N = 2
47 46 adantr ⊢ φ ∧ A = B → 2 1 N N = 2
48 3 nncnd ⊢ φ → C ∈ ℂ
49 1 nncnd ⊢ φ → A ∈ ℂ
50 1 nnne0d ⊢ φ → A ≠ 0
51 48 49 50 29 expdivd ⊢ φ → C A N = C N A N
52 51 adantr ⊢ φ ∧ A = B → C A N = C N A N
53 43 47 52 3eqtr4d ⊢ φ ∧ A = B → 2 1 N N = C A N
54 23 27 28 53 exp11nnd ⊢ φ ∧ A = B → 2 1 N = C A
55 16 54 mteqand ⊢ φ → A ≠ B