Metamath Proof Explorer


Theorem hdmapip1

Description: Construct a proportional vector Y whose inner product with the original X equals one. (Contributed by NM, 13-Jun-2015)

Ref Expression
Hypotheses hdmapip1.h ⊢ H = LHyp ⁡ K
hdmapip1.u ⊢ U = DVecH ⁡ K ⁡ W
hdmapip1.v ⊢ V = Base U
hdmapip1.t ⊢ · ˙ = ⋅ U
hdmapip1.o ⊢ 0 ˙ = 0 U
hdmapip1.r ⊢ R = Scalar ⁡ U
hdmapip1.i ⊢ 1 ˙ = 1 R
hdmapip1.n ⊢ N = inv r ⁡ R
hdmapip1.s ⊢ S = HDMap ⁡ K ⁡ W
hdmapip1.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmapip1.x ⊢ φ → X ∈ V ∖ 0 ˙
hdmapip1.y ⊢ Y = N ⁡ S ⁡ X ⁡ X · ˙ X
Assertion hdmapip1 ⊢ φ → S ⁡ X ⁡ Y = 1 ˙

Proof

Step Hyp Ref Expression
1 hdmapip1.h ⊢ H = LHyp ⁡ K
2 hdmapip1.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmapip1.v ⊢ V = Base U
4 hdmapip1.t ⊢ · ˙ = ⋅ U
5 hdmapip1.o ⊢ 0 ˙ = 0 U
6 hdmapip1.r ⊢ R = Scalar ⁡ U
7 hdmapip1.i ⊢ 1 ˙ = 1 R
8 hdmapip1.n ⊢ N = inv r ⁡ R
9 hdmapip1.s ⊢ S = HDMap ⁡ K ⁡ W
10 hdmapip1.k ⊢ φ → K ∈ HL ∧ W ∈ H
11 hdmapip1.x ⊢ φ → X ∈ V ∖ 0 ˙
12 hdmapip1.y ⊢ Y = N ⁡ S ⁡ X ⁡ X · ˙ X
13 12 fveq2i ⊢ S ⁡ X ⁡ Y = S ⁡ X ⁡ N ⁡ S ⁡ X ⁡ X · ˙ X
14 eqid ⊢ Base R = Base R
15 eqid ⊢ ⋅ R = ⋅ R
16 11 eldifad ⊢ φ → X ∈ V
17 1 2 10 dvhlvec ⊢ φ → U ∈ LVec
18 6 lvecdrng ⊢ U ∈ LVec → R ∈ DivRing
19 17 18 syl ⊢ φ → R ∈ DivRing
20 1 2 3 6 14 9 10 16 16 hdmapipcl ⊢ φ → S ⁡ X ⁡ X ∈ Base R
21 eldifsni ⊢ X ∈ V ∖ 0 ˙ → X ≠ 0 ˙
22 11 21 syl ⊢ φ → X ≠ 0 ˙
23 eqid ⊢ 0 R = 0 R
24 1 2 3 5 6 23 9 10 16 hdmapip0 ⊢ φ → S ⁡ X ⁡ X = 0 R ↔ X = 0 ˙
25 24 necon3bid ⊢ φ → S ⁡ X ⁡ X ≠ 0 R ↔ X ≠ 0 ˙
26 22 25 mpbird ⊢ φ → S ⁡ X ⁡ X ≠ 0 R
27 14 23 8 drnginvrcl ⊢ R ∈ DivRing ∧ S ⁡ X ⁡ X ∈ Base R ∧ S ⁡ X ⁡ X ≠ 0 R → N ⁡ S ⁡ X ⁡ X ∈ Base R
28 19 20 26 27 syl3anc ⊢ φ → N ⁡ S ⁡ X ⁡ X ∈ Base R
29 1 2 3 4 6 14 15 9 10 16 16 28 hdmaplnm1 ⊢ φ → S ⁡ X ⁡ N ⁡ S ⁡ X ⁡ X · ˙ X = N ⁡ S ⁡ X ⁡ X ⋅ R S ⁡ X ⁡ X
30 14 23 15 7 8 drnginvrl ⊢ R ∈ DivRing ∧ S ⁡ X ⁡ X ∈ Base R ∧ S ⁡ X ⁡ X ≠ 0 R → N ⁡ S ⁡ X ⁡ X ⋅ R S ⁡ X ⁡ X = 1 ˙
31 19 20 26 30 syl3anc ⊢ φ → N ⁡ S ⁡ X ⁡ X ⋅ R S ⁡ X ⁡ X = 1 ˙
32 29 31 eqtrd ⊢ φ → S ⁡ X ⁡ N ⁡ S ⁡ X ⁡ X · ˙ X = 1 ˙
33 13 32 eqtrid ⊢ φ → S ⁡ X ⁡ Y = 1 ˙