Metamath Proof Explorer


Theorem jensenlem1

Description: Lemma for jensen . (Contributed by Mario Carneiro, 4-Jun-2016)

Ref Expression
Hypotheses jensen.1 ⊢ φ → D ⊆ ℝ
jensen.2 ⊢ φ → F : D ⟶ ℝ
jensen.3 ⊢ φ ∧ a ∈ D ∧ b ∈ D → a b ⊆ D
jensen.4 ⊢ φ → A ∈ Fin
jensen.5 ⊢ φ → T : A ⟶ 0 +∞
jensen.6 ⊢ φ → X : A ⟶ D
jensen.7 ⊢ φ → 0 < ∑ ℂ fld T
jensen.8 ⊢ φ ∧ x ∈ D ∧ y ∈ D ∧ t ∈ 0 1 → F ⁡ t ⁢ x + 1 − t ⁢ y ≤ t ⁢ F ⁡ x + 1 − t ⁢ F ⁡ y
jensenlem.1 ⊢ φ → ¬ z ∈ B
jensenlem.2 ⊢ φ → B ∪ z ⊆ A
jensenlem.s ⊢ S = ∑ ℂ fld T ↾ B
jensenlem.l ⊢ L = ∑ ℂ fld T ↾ B ∪ z
Assertion jensenlem1 ⊢ φ → L = S + T ⁡ z

Proof

Step Hyp Ref Expression
1 jensen.1 ⊢ φ → D ⊆ ℝ
2 jensen.2 ⊢ φ → F : D ⟶ ℝ
3 jensen.3 ⊢ φ ∧ a ∈ D ∧ b ∈ D → a b ⊆ D
4 jensen.4 ⊢ φ → A ∈ Fin
5 jensen.5 ⊢ φ → T : A ⟶ 0 +∞
6 jensen.6 ⊢ φ → X : A ⟶ D
7 jensen.7 ⊢ φ → 0 < ∑ ℂ fld T
8 jensen.8 ⊢ φ ∧ x ∈ D ∧ y ∈ D ∧ t ∈ 0 1 → F ⁡ t ⁢ x + 1 − t ⁢ y ≤ t ⁢ F ⁡ x + 1 − t ⁢ F ⁡ y
9 jensenlem.1 ⊢ φ → ¬ z ∈ B
10 jensenlem.2 ⊢ φ → B ∪ z ⊆ A
11 jensenlem.s ⊢ S = ∑ ℂ fld T ↾ B
12 jensenlem.l ⊢ L = ∑ ℂ fld T ↾ B ∪ z
13 cnfldbas ⊢ ℂ = Base ℂ fld
14 cnfldadd ⊢ + = + ℂ fld
15 cnring ⊢ ℂ fld ∈ Ring
16 ringcmn ⊢ ℂ fld ∈ Ring → ℂ fld ∈ CMnd
17 15 16 mp1i ⊢ φ → ℂ fld ∈ CMnd
18 10 unssad ⊢ φ → B ⊆ A
19 4 18 ssfid ⊢ φ → B ∈ Fin
20 rge0ssre ⊢ 0 +∞ ⊆ ℝ
21 ax-resscn ⊢ ℝ ⊆ ℂ
22 20 21 sstri ⊢ 0 +∞ ⊆ ℂ
23 18 sselda ⊢ φ ∧ x ∈ B → x ∈ A
24 5 ffvelcdmda ⊢ φ ∧ x ∈ A → T ⁡ x ∈ 0 +∞
25 23 24 syldan ⊢ φ ∧ x ∈ B → T ⁡ x ∈ 0 +∞
26 22 25 sselid ⊢ φ ∧ x ∈ B → T ⁡ x ∈ ℂ
27 10 unssbd ⊢ φ → z ⊆ A
28 vex ⊢ z ∈ V
29 28 snss ⊢ z ∈ A ↔ z ⊆ A
30 27 29 sylibr ⊢ φ → z ∈ A
31 5 30 ffvelcdmd ⊢ φ → T ⁡ z ∈ 0 +∞
32 22 31 sselid ⊢ φ → T ⁡ z ∈ ℂ
33 fveq2 ⊢ x = z → T ⁡ x = T ⁡ z
34 13 14 17 19 26 30 9 32 33 gsumunsn ⊢ φ → ∑ ℂ fld x ∈ B ∪ z T ⁡ x = ∑ ℂ fld x ∈ B T ⁡ x + T ⁡ z
35 5 10 feqresmpt ⊢ φ → T ↾ B ∪ z = x ∈ B ∪ z ⟼ T ⁡ x
36 35 oveq2d ⊢ φ → ∑ ℂ fld T ↾ B ∪ z = ∑ ℂ fld x ∈ B ∪ z T ⁡ x
37 5 18 feqresmpt ⊢ φ → T ↾ B = x ∈ B ⟼ T ⁡ x
38 37 oveq2d ⊢ φ → ∑ ℂ fld T ↾ B = ∑ ℂ fld x ∈ B T ⁡ x
39 38 oveq1d ⊢ φ → ∑ ℂ fld T ↾ B + T ⁡ z = ∑ ℂ fld x ∈ B T ⁡ x + T ⁡ z
40 34 36 39 3eqtr4d ⊢ φ → ∑ ℂ fld T ↾ B ∪ z = ∑ ℂ fld T ↾ B + T ⁡ z
41 11 oveq1i ⊢ S + T ⁡ z = ∑ ℂ fld T ↾ B + T ⁡ z
42 40 12 41 3eqtr4g ⊢ φ → L = S + T ⁡ z