Metamath Proof Explorer


Theorem hdmap1eq4N

Description: Convert mapdheq4 to use HDMap1 function. (Contributed by NM, 17-May-2015) (New usage is discouraged.)

Ref Expression
Hypotheses hdmap1eq2.h ⊢ H = LHyp ⁡ K
hdmap1eq2.u ⊢ U = DVecH ⁡ K ⁡ W
hdmap1eq2.v ⊢ V = Base U
hdmap1eq2.o ⊢ 0 ˙ = 0 U
hdmap1eq2.n ⊢ N = LSpan ⁡ U
hdmap1eq2.c ⊢ C = LCDual ⁡ K ⁡ W
hdmap1eq2.d ⊢ D = Base C
hdmap1eq2.l ⊢ L = LSpan ⁡ C
hdmap1eq2.m ⊢ M = mapd ⁡ K ⁡ W
hdmap1eq2.i ⊢ I = HDMap1 ⁡ K ⁡ W
hdmap1eq2.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmap1eq2.f ⊢ φ → F ∈ D
hdmap1eq2.mn ⊢ φ → M ⁡ N ⁡ X = L ⁡ F
hdmap1eq4.x ⊢ φ → X ∈ V ∖ 0 ˙
hdmap1eq4.y ⊢ φ → Y ∈ V ∖ 0 ˙
hdmap1eq4.z ⊢ φ → Z ∈ V ∖ 0 ˙
hdmap1eq4.ne ⊢ φ → N ⁡ Y ≠ N ⁡ Z
hdmap1eq4.xn ⊢ φ → ¬ X ∈ N ⁡ Y Z
hdmap1eq4.eg ⊢ φ → I ⁡ X F Y = G
hdmap1eq4.ee ⊢ φ → I ⁡ X F Z = B
Assertion hdmap1eq4N ⊢ φ → I ⁡ Y G Z = B

Proof

Step Hyp Ref Expression
1 hdmap1eq2.h ⊢ H = LHyp ⁡ K
2 hdmap1eq2.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmap1eq2.v ⊢ V = Base U
4 hdmap1eq2.o ⊢ 0 ˙ = 0 U
5 hdmap1eq2.n ⊢ N = LSpan ⁡ U
6 hdmap1eq2.c ⊢ C = LCDual ⁡ K ⁡ W
7 hdmap1eq2.d ⊢ D = Base C
8 hdmap1eq2.l ⊢ L = LSpan ⁡ C
9 hdmap1eq2.m ⊢ M = mapd ⁡ K ⁡ W
10 hdmap1eq2.i ⊢ I = HDMap1 ⁡ K ⁡ W
11 hdmap1eq2.k ⊢ φ → K ∈ HL ∧ W ∈ H
12 hdmap1eq2.f ⊢ φ → F ∈ D
13 hdmap1eq2.mn ⊢ φ → M ⁡ N ⁡ X = L ⁡ F
14 hdmap1eq4.x ⊢ φ → X ∈ V ∖ 0 ˙
15 hdmap1eq4.y ⊢ φ → Y ∈ V ∖ 0 ˙
16 hdmap1eq4.z ⊢ φ → Z ∈ V ∖ 0 ˙
17 hdmap1eq4.ne ⊢ φ → N ⁡ Y ≠ N ⁡ Z
18 hdmap1eq4.xn ⊢ φ → ¬ X ∈ N ⁡ Y Z
19 hdmap1eq4.eg ⊢ φ → I ⁡ X F Y = G
20 hdmap1eq4.ee ⊢ φ → I ⁡ X F Z = B
21 eqid ⊢ - U = - U
22 eqid ⊢ - C = - C
23 eqid ⊢ 0 C = 0 C
24 1 2 11 dvhlvec ⊢ φ → U ∈ LVec
25 14 eldifad ⊢ φ → X ∈ V
26 15 eldifad ⊢ φ → Y ∈ V
27 16 eldifad ⊢ φ → Z ∈ V
28 3 5 24 25 26 27 18 lspindpi ⊢ φ → N ⁡ X ≠ N ⁡ Y ∧ N ⁡ X ≠ N ⁡ Z
29 28 simpld ⊢ φ → N ⁡ X ≠ N ⁡ Y
30 1 2 3 4 5 6 7 8 9 10 11 12 13 29 14 26 hdmap1cl ⊢ φ → I ⁡ X F Y ∈ D
31 19 30 eqeltrrd ⊢ φ → G ∈ D
32 eqid ⊢ x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h
33 1 2 3 21 4 5 6 7 22 23 8 9 10 11 15 31 27 32 hdmap1valc ⊢ φ → I ⁡ Y G Z = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h ⁡ Y G Z
34 1 2 3 21 4 5 6 7 22 23 8 9 10 11 14 12 26 32 hdmap1valc ⊢ φ → I ⁡ X F Y = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h ⁡ X F Y
35 34 19 eqtr3d ⊢ φ → x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h ⁡ X F Y = G
36 1 2 3 21 4 5 6 7 22 23 8 9 10 11 14 12 27 32 hdmap1valc ⊢ φ → I ⁡ X F Z = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h ⁡ X F Z
37 36 20 eqtr3d ⊢ φ → x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h ⁡ X F Z = B
38 23 32 1 9 2 3 21 4 5 6 7 22 8 11 12 13 14 15 16 18 17 35 37 mapdheq4 ⊢ φ → x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ 0 C ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = L ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - U 2 nd ⁡ x = L ⁡ 2 nd ⁡ 1 st ⁡ x - C h ⁡ Y G Z = B
39 33 38 eqtrd ⊢ φ → I ⁡ Y G Z = B