Metamath Proof Explorer


Theorem hmphindis

Description: Homeomorphisms preserve topological indiscreteness. (Contributed by FL, 18-Aug-2008) (Revised by Mario Carneiro, 10-Sep-2015)

Ref Expression
Hypothesis hmphdis.1 ⊢ X = ⋃ J
Assertion hmphindis ⊢ J ≃ ∅ A → J = ∅ X

Proof

Step Hyp Ref Expression
1 hmphdis.1 ⊢ X = ⋃ J
2 dfsn2 ⊢ ∅ = ∅ ∅
3 indislem ⊢ ∅ I ⁡ A = ∅ A
4 preq2 ⊢ I ⁡ A = ∅ → ∅ I ⁡ A = ∅ ∅
5 4 2 eqtr4di ⊢ I ⁡ A = ∅ → ∅ I ⁡ A = ∅
6 3 5 eqtr3id ⊢ I ⁡ A = ∅ → ∅ A = ∅
7 6 breq2d ⊢ I ⁡ A = ∅ → J ≃ ∅ A ↔ J ≃ ∅
8 7 biimpac ⊢ J ≃ ∅ A ∧ I ⁡ A = ∅ → J ≃ ∅
9 hmph0 ⊢ J ≃ ∅ ↔ J = ∅
10 8 9 sylib ⊢ J ≃ ∅ A ∧ I ⁡ A = ∅ → J = ∅
11 10 unieqd ⊢ J ≃ ∅ A ∧ I ⁡ A = ∅ → ⋃ J = ⋃ ∅
12 0ex ⊢ ∅ ∈ V
13 12 unisn ⊢ ⋃ ∅ = ∅
14 13 eqcomi ⊢ ∅ = ⋃ ∅
15 11 1 14 3eqtr4g ⊢ J ≃ ∅ A ∧ I ⁡ A = ∅ → X = ∅
16 15 preq2d ⊢ J ≃ ∅ A ∧ I ⁡ A = ∅ → ∅ X = ∅ ∅
17 2 10 16 3eqtr4a ⊢ J ≃ ∅ A ∧ I ⁡ A = ∅ → J = ∅ X
18 hmphen ⊢ J ≃ ∅ A → J ≈ ∅ A
19 necom ⊢ I ⁡ A ≠ ∅ ↔ ∅ ≠ I ⁡ A
20 fvex ⊢ I ⁡ A ∈ V
21 enpr2 ⊢ ∅ ∈ V ∧ I ⁡ A ∈ V ∧ ∅ ≠ I ⁡ A → ∅ I ⁡ A ≈ 2 𝑜
22 12 20 21 mp3an12 ⊢ ∅ ≠ I ⁡ A → ∅ I ⁡ A ≈ 2 𝑜
23 19 22 sylbi ⊢ I ⁡ A ≠ ∅ → ∅ I ⁡ A ≈ 2 𝑜
24 23 adantl ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → ∅ I ⁡ A ≈ 2 𝑜
25 3 24 eqbrtrrid ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → ∅ A ≈ 2 𝑜
26 entr ⊢ J ≈ ∅ A ∧ ∅ A ≈ 2 𝑜 → J ≈ 2 𝑜
27 18 25 26 syl2an2r ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → J ≈ 2 𝑜
28 hmphtop1 ⊢ J ≃ ∅ A → J ∈ Top
29 28 adantr ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → J ∈ Top
30 1 toptopon ⊢ J ∈ Top ↔ J ∈ TopOn ⁡ X
31 29 30 sylib ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → J ∈ TopOn ⁡ X
32 en2top ⊢ J ∈ TopOn ⁡ X → J ≈ 2 𝑜 ↔ J = ∅ X ∧ X ≠ ∅
33 31 32 syl ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → J ≈ 2 𝑜 ↔ J = ∅ X ∧ X ≠ ∅
34 27 33 mpbid ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → J = ∅ X ∧ X ≠ ∅
35 34 simpld ⊢ J ≃ ∅ A ∧ I ⁡ A ≠ ∅ → J = ∅ X
36 17 35 pm2.61dane ⊢ J ≃ ∅ A → J = ∅ X