Metamath Proof Explorer


Theorem lcmineqlem21

Description: The lcm inequality lemma without base cases 7 and 8. (Contributed by metakunt, 12-May-2024)

Ref Expression
Hypotheses lcmineqlem21.1 ⊢ φ → N ∈ ℕ
lcmineqlem21.2 ⊢ φ → 4 ≤ N
Assertion lcmineqlem21 ⊢ φ → 2 2 ⋅ N + 2 ≤ lcm _ ⁡ 1 … 2 ⋅ N + 1

Proof

Step Hyp Ref Expression
1 lcmineqlem21.1 ⊢ φ → N ∈ ℕ
2 lcmineqlem21.2 ⊢ φ → 4 ≤ N
3 2nn0 ⊢ 2 ∈ ℕ 0
4 3 a1i ⊢ φ → 2 ∈ ℕ 0
5 4 nn0red ⊢ φ → 2 ∈ ℝ
6 1 nnnn0d ⊢ φ → N ∈ ℕ 0
7 4 6 nn0mulcld ⊢ φ → 2 ⋅ N ∈ ℕ 0
8 7 4 nn0addcld ⊢ φ → 2 ⋅ N + 2 ∈ ℕ 0
9 5 8 reexpcld ⊢ φ → 2 2 ⋅ N + 2 ∈ ℝ
10 1 nnred ⊢ φ → N ∈ ℝ
11 2rp ⊢ 2 ∈ ℝ +
12 11 a1i ⊢ φ → 2 ∈ ℝ +
13 2z ⊢ 2 ∈ ℤ
14 13 a1i ⊢ φ → 2 ∈ ℤ
15 1 nnzd ⊢ φ → N ∈ ℤ
16 14 15 zmulcld ⊢ φ → 2 ⋅ N ∈ ℤ
17 12 16 rpexpcld ⊢ φ → 2 2 ⋅ N ∈ ℝ +
18 17 rpred ⊢ φ → 2 2 ⋅ N ∈ ℝ
19 10 18 remulcld ⊢ φ → N ⁢ 2 2 ⋅ N ∈ ℝ
20 fz1ssnn ⊢ 1 … 2 ⋅ N + 1 ⊆ ℕ
21 fzfi ⊢ 1 … 2 ⋅ N + 1 ∈ Fin
22 lcmfnncl ⊢ 1 … 2 ⋅ N + 1 ⊆ ℕ ∧ 1 … 2 ⋅ N + 1 ∈ Fin → lcm _ ⁡ 1 … 2 ⋅ N + 1 ∈ ℕ
23 20 21 22 mp2an ⊢ lcm _ ⁡ 1 … 2 ⋅ N + 1 ∈ ℕ
24 23 a1i ⊢ φ → lcm _ ⁡ 1 … 2 ⋅ N + 1 ∈ ℕ
25 24 nnred ⊢ φ → lcm _ ⁡ 1 … 2 ⋅ N + 1 ∈ ℝ
26 4re ⊢ 4 ∈ ℝ
27 26 a1i ⊢ φ → 4 ∈ ℝ
28 27 10 17 lemul1d ⊢ φ → 4 ≤ N ↔ 4 ⁢ 2 2 ⋅ N ≤ N ⁢ 2 2 ⋅ N
29 2 28 mpbid ⊢ φ → 4 ⁢ 2 2 ⋅ N ≤ N ⁢ 2 2 ⋅ N
30 2cnd ⊢ φ → 2 ∈ ℂ
31 30 4 7 expaddd ⊢ φ → 2 2 ⋅ N + 2 = 2 2 ⋅ N ⁢ 2 2
32 sq2 ⊢ 2 2 = 4
33 32 oveq2i ⊢ 2 2 ⋅ N ⁢ 2 2 = 2 2 ⋅ N ⋅ 4
34 31 33 eqtrdi ⊢ φ → 2 2 ⋅ N + 2 = 2 2 ⋅ N ⋅ 4
35 17 rpcnd ⊢ φ → 2 2 ⋅ N ∈ ℂ
36 27 recnd ⊢ φ → 4 ∈ ℂ
37 35 36 mulcomd ⊢ φ → 2 2 ⋅ N ⋅ 4 = 4 ⁢ 2 2 ⋅ N
38 34 37 eqtrd ⊢ φ → 2 2 ⋅ N + 2 = 4 ⁢ 2 2 ⋅ N
39 38 breq1d ⊢ φ → 2 2 ⋅ N + 2 ≤ N ⁢ 2 2 ⋅ N ↔ 4 ⁢ 2 2 ⋅ N ≤ N ⁢ 2 2 ⋅ N
40 29 39 mpbird ⊢ φ → 2 2 ⋅ N + 2 ≤ N ⁢ 2 2 ⋅ N
41 1 lcmineqlem20 ⊢ φ → N ⁢ 2 2 ⋅ N ≤ lcm _ ⁡ 1 … 2 ⋅ N + 1
42 9 19 25 40 41 letrd ⊢ φ → 2 2 ⋅ N + 2 ≤ lcm _ ⁡ 1 … 2 ⋅ N + 1