Metamath Proof Explorer


Theorem map2psrpr

Description: Equivalence for positive signed real. (Contributed by NM, 17-May-1996) (Revised by Mario Carneiro, 15-Jun-2013) (New usage is discouraged.)

Ref Expression
Hypothesis map2psrpr.2 ⊢ C ∈ 𝑹
Assertion map2psrpr ⊢ C + 𝑹 -1 𝑹 < 𝑹 A ↔ ∃ x ∈ 𝑷 C + 𝑹 x 1 𝑷 ~ 𝑹 = A

Proof

Step Hyp Ref Expression
1 map2psrpr.2 ⊢ C ∈ 𝑹
2 ltrelsr ⊢ < 𝑹 ⊆ 𝑹 × 𝑹
3 2 brel ⊢ C + 𝑹 -1 𝑹 < 𝑹 A → C + 𝑹 -1 𝑹 ∈ 𝑹 ∧ A ∈ 𝑹
4 3 simprd ⊢ C + 𝑹 -1 𝑹 < 𝑹 A → A ∈ 𝑹
5 ltasr ⊢ C ∈ 𝑹 → -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A ↔ C + 𝑹 -1 𝑹 < 𝑹 C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A
6 1 5 ax-mp ⊢ -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A ↔ C + 𝑹 -1 𝑹 < 𝑹 C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A
7 pn0sr ⊢ C ∈ 𝑹 → C + 𝑹 C ⋅ 𝑹 -1 𝑹 = 0 𝑹
8 1 7 ax-mp ⊢ C + 𝑹 C ⋅ 𝑹 -1 𝑹 = 0 𝑹
9 8 oveq1i ⊢ C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A = 0 𝑹 + 𝑹 A
10 addasssr ⊢ C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A = C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A
11 addcomsr ⊢ 0 𝑹 + 𝑹 A = A + 𝑹 0 𝑹
12 9 10 11 3eqtr3i ⊢ C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A = A + 𝑹 0 𝑹
13 0idsr ⊢ A ∈ 𝑹 → A + 𝑹 0 𝑹 = A
14 12 13 eqtrid ⊢ A ∈ 𝑹 → C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A = A
15 14 breq2d ⊢ A ∈ 𝑹 → C + 𝑹 -1 𝑹 < 𝑹 C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A ↔ C + 𝑹 -1 𝑹 < 𝑹 A
16 6 15 bitrid ⊢ A ∈ 𝑹 → -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A ↔ C + 𝑹 -1 𝑹 < 𝑹 A
17 m1r ⊢ -1 𝑹 ∈ 𝑹
18 mulclsr ⊢ C ∈ 𝑹 ∧ -1 𝑹 ∈ 𝑹 → C ⋅ 𝑹 -1 𝑹 ∈ 𝑹
19 1 17 18 mp2an ⊢ C ⋅ 𝑹 -1 𝑹 ∈ 𝑹
20 addclsr ⊢ C ⋅ 𝑹 -1 𝑹 ∈ 𝑹 ∧ A ∈ 𝑹 → C ⋅ 𝑹 -1 𝑹 + 𝑹 A ∈ 𝑹
21 19 20 mpan ⊢ A ∈ 𝑹 → C ⋅ 𝑹 -1 𝑹 + 𝑹 A ∈ 𝑹
22 df-nr ⊢ 𝑹 = 𝑷 × 𝑷 / ~ 𝑹
23 breq2 ⊢ y z ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → -1 𝑹 < 𝑹 y z ~ 𝑹 ↔ -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A
24 eqeq2 ⊢ y z ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A
25 24 rexbidv ⊢ y z ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A
26 23 25 imbi12d ⊢ y z ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → -1 𝑹 < 𝑹 y z ~ 𝑹 → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A
27 df-m1r ⊢ -1 𝑹 = 1 𝑷 1 𝑷 + 𝑷 1 𝑷 ~ 𝑹
28 27 breq1i ⊢ -1 𝑹 < 𝑹 y z ~ 𝑹 ↔ 1 𝑷 1 𝑷 + 𝑷 1 𝑷 ~ 𝑹 < 𝑹 y z ~ 𝑹
29 addasspr ⊢ 1 𝑷 + 𝑷 1 𝑷 + 𝑷 y = 1 𝑷 + 𝑷 1 𝑷 + 𝑷 y
30 29 breq2i ⊢ 1 𝑷 + 𝑷 z < 𝑷 1 𝑷 + 𝑷 1 𝑷 + 𝑷 y ↔ 1 𝑷 + 𝑷 z < 𝑷 1 𝑷 + 𝑷 1 𝑷 + 𝑷 y
31 ltsrpr ⊢ 1 𝑷 1 𝑷 + 𝑷 1 𝑷 ~ 𝑹 < 𝑹 y z ~ 𝑹 ↔ 1 𝑷 + 𝑷 z < 𝑷 1 𝑷 + 𝑷 1 𝑷 + 𝑷 y
32 1pr ⊢ 1 𝑷 ∈ 𝑷
33 ltapr ⊢ 1 𝑷 ∈ 𝑷 → z < 𝑷 1 𝑷 + 𝑷 y ↔ 1 𝑷 + 𝑷 z < 𝑷 1 𝑷 + 𝑷 1 𝑷 + 𝑷 y
34 32 33 ax-mp ⊢ z < 𝑷 1 𝑷 + 𝑷 y ↔ 1 𝑷 + 𝑷 z < 𝑷 1 𝑷 + 𝑷 1 𝑷 + 𝑷 y
35 30 31 34 3bitr4i ⊢ 1 𝑷 1 𝑷 + 𝑷 1 𝑷 ~ 𝑹 < 𝑹 y z ~ 𝑹 ↔ z < 𝑷 1 𝑷 + 𝑷 y
36 28 35 bitri ⊢ -1 𝑹 < 𝑹 y z ~ 𝑹 ↔ z < 𝑷 1 𝑷 + 𝑷 y
37 ltexpri ⊢ z < 𝑷 1 𝑷 + 𝑷 y → ∃ x ∈ 𝑷 z + 𝑷 x = 1 𝑷 + 𝑷 y
38 36 37 sylbi ⊢ -1 𝑹 < 𝑹 y z ~ 𝑹 → ∃ x ∈ 𝑷 z + 𝑷 x = 1 𝑷 + 𝑷 y
39 enreceq ⊢ x ∈ 𝑷 ∧ 1 𝑷 ∈ 𝑷 ∧ y ∈ 𝑷 ∧ z ∈ 𝑷 → x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ x + 𝑷 z = 1 𝑷 + 𝑷 y
40 32 39 mpanl2 ⊢ x ∈ 𝑷 ∧ y ∈ 𝑷 ∧ z ∈ 𝑷 → x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ x + 𝑷 z = 1 𝑷 + 𝑷 y
41 addcompr ⊢ z + 𝑷 x = x + 𝑷 z
42 41 eqeq1i ⊢ z + 𝑷 x = 1 𝑷 + 𝑷 y ↔ x + 𝑷 z = 1 𝑷 + 𝑷 y
43 40 42 bitr4di ⊢ x ∈ 𝑷 ∧ y ∈ 𝑷 ∧ z ∈ 𝑷 → x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ z + 𝑷 x = 1 𝑷 + 𝑷 y
44 43 ancoms ⊢ y ∈ 𝑷 ∧ z ∈ 𝑷 ∧ x ∈ 𝑷 → x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ z + 𝑷 x = 1 𝑷 + 𝑷 y
45 44 rexbidva ⊢ y ∈ 𝑷 ∧ z ∈ 𝑷 → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = y z ~ 𝑹 ↔ ∃ x ∈ 𝑷 z + 𝑷 x = 1 𝑷 + 𝑷 y
46 38 45 imbitrrid ⊢ y ∈ 𝑷 ∧ z ∈ 𝑷 → -1 𝑹 < 𝑹 y z ~ 𝑹 → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = y z ~ 𝑹
47 22 26 46 ecoptocl ⊢ C ⋅ 𝑹 -1 𝑹 + 𝑹 A ∈ 𝑹 → -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A
48 21 47 syl ⊢ A ∈ 𝑹 → -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A
49 oveq2 ⊢ x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → C + 𝑹 x 1 𝑷 ~ 𝑹 = C + 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A
50 49 14 sylan9eqr ⊢ A ∈ 𝑹 ∧ x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → C + 𝑹 x 1 𝑷 ~ 𝑹 = A
51 50 ex ⊢ A ∈ 𝑹 → x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → C + 𝑹 x 1 𝑷 ~ 𝑹 = A
52 51 reximdv ⊢ A ∈ 𝑹 → ∃ x ∈ 𝑷 x 1 𝑷 ~ 𝑹 = C ⋅ 𝑹 -1 𝑹 + 𝑹 A → ∃ x ∈ 𝑷 C + 𝑹 x 1 𝑷 ~ 𝑹 = A
53 48 52 syld ⊢ A ∈ 𝑹 → -1 𝑹 < 𝑹 C ⋅ 𝑹 -1 𝑹 + 𝑹 A → ∃ x ∈ 𝑷 C + 𝑹 x 1 𝑷 ~ 𝑹 = A
54 16 53 sylbird ⊢ A ∈ 𝑹 → C + 𝑹 -1 𝑹 < 𝑹 A → ∃ x ∈ 𝑷 C + 𝑹 x 1 𝑷 ~ 𝑹 = A
55 4 54 mpcom ⊢ C + 𝑹 -1 𝑹 < 𝑹 A → ∃ x ∈ 𝑷 C + 𝑹 x 1 𝑷 ~ 𝑹 = A
56 1 mappsrpr ⊢ C + 𝑹 -1 𝑹 < 𝑹 C + 𝑹 x 1 𝑷 ~ 𝑹 ↔ x ∈ 𝑷
57 breq2 ⊢ C + 𝑹 x 1 𝑷 ~ 𝑹 = A → C + 𝑹 -1 𝑹 < 𝑹 C + 𝑹 x 1 𝑷 ~ 𝑹 ↔ C + 𝑹 -1 𝑹 < 𝑹 A
58 56 57 bitr3id ⊢ C + 𝑹 x 1 𝑷 ~ 𝑹 = A → x ∈ 𝑷 ↔ C + 𝑹 -1 𝑹 < 𝑹 A
59 58 biimpac ⊢ x ∈ 𝑷 ∧ C + 𝑹 x 1 𝑷 ~ 𝑹 = A → C + 𝑹 -1 𝑹 < 𝑹 A
60 59 rexlimiva ⊢ ∃ x ∈ 𝑷 C + 𝑹 x 1 𝑷 ~ 𝑹 = A → C + 𝑹 -1 𝑹 < 𝑹 A
61 55 60 impbii ⊢ C + 𝑹 -1 𝑹 < 𝑹 A ↔ ∃ x ∈ 𝑷 C + 𝑹 x 1 𝑷 ~ 𝑹 = A