Metamath Proof Explorer


Theorem nn0sumshdiglem2

Description: Lemma 2 for nn0sumshdig . (Contributed by AV, 7-Jun-2020)

Ref Expression
Assertion nn0sumshdiglem2 ⊢ L ∈ ℕ → ∀ a ∈ ℕ 0 # b ⁡ a = L → a = ∑ k ∈ 0 ..^ L k digit ⁡ 2 a ⁢ 2 k

Proof

Step Hyp Ref Expression
1 eqeq2 ⊢ x = 1 → # b ⁡ a = x ↔ # b ⁡ a = 1
2 oveq2 ⊢ x = 1 → 0 ..^ x = 0 ..^ 1
3 fzo01 ⊢ 0 ..^ 1 = 0
4 2 3 eqtrdi ⊢ x = 1 → 0 ..^ x = 0
5 4 sumeq1d ⊢ x = 1 → ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k = ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k
6 5 eqeq2d ⊢ x = 1 → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ a = ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k
7 1 6 imbi12d ⊢ x = 1 → # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ # b ⁡ a = 1 → a = ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k
8 7 ralbidv ⊢ x = 1 → ∀ a ∈ ℕ 0 # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ ∀ a ∈ ℕ 0 # b ⁡ a = 1 → a = ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k
9 eqeq2 ⊢ x = y → # b ⁡ a = x ↔ # b ⁡ a = y
10 oveq2 ⊢ x = y → 0 ..^ x = 0 ..^ y
11 10 sumeq1d ⊢ x = y → ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k = ∑ k ∈ 0 ..^ y k digit ⁡ 2 a ⁢ 2 k
12 11 eqeq2d ⊢ x = y → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ a = ∑ k ∈ 0 ..^ y k digit ⁡ 2 a ⁢ 2 k
13 9 12 imbi12d ⊢ x = y → # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ # b ⁡ a = y → a = ∑ k ∈ 0 ..^ y k digit ⁡ 2 a ⁢ 2 k
14 13 ralbidv ⊢ x = y → ∀ a ∈ ℕ 0 # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ ∀ a ∈ ℕ 0 # b ⁡ a = y → a = ∑ k ∈ 0 ..^ y k digit ⁡ 2 a ⁢ 2 k
15 eqeq2 ⊢ x = y + 1 → # b ⁡ a = x ↔ # b ⁡ a = y + 1
16 oveq2 ⊢ x = y + 1 → 0 ..^ x = 0 ..^ y + 1
17 16 sumeq1d ⊢ x = y + 1 → ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k = ∑ k ∈ 0 ..^ y + 1 k digit ⁡ 2 a ⁢ 2 k
18 17 eqeq2d ⊢ x = y + 1 → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ a = ∑ k ∈ 0 ..^ y + 1 k digit ⁡ 2 a ⁢ 2 k
19 15 18 imbi12d ⊢ x = y + 1 → # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ # b ⁡ a = y + 1 → a = ∑ k ∈ 0 ..^ y + 1 k digit ⁡ 2 a ⁢ 2 k
20 19 ralbidv ⊢ x = y + 1 → ∀ a ∈ ℕ 0 # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ ∀ a ∈ ℕ 0 # b ⁡ a = y + 1 → a = ∑ k ∈ 0 ..^ y + 1 k digit ⁡ 2 a ⁢ 2 k
21 eqeq2 ⊢ x = L → # b ⁡ a = x ↔ # b ⁡ a = L
22 oveq2 ⊢ x = L → 0 ..^ x = 0 ..^ L
23 22 sumeq1d ⊢ x = L → ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k = ∑ k ∈ 0 ..^ L k digit ⁡ 2 a ⁢ 2 k
24 23 eqeq2d ⊢ x = L → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ a = ∑ k ∈ 0 ..^ L k digit ⁡ 2 a ⁢ 2 k
25 21 24 imbi12d ⊢ x = L → # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ # b ⁡ a = L → a = ∑ k ∈ 0 ..^ L k digit ⁡ 2 a ⁢ 2 k
26 25 ralbidv ⊢ x = L → ∀ a ∈ ℕ 0 # b ⁡ a = x → a = ∑ k ∈ 0 ..^ x k digit ⁡ 2 a ⁢ 2 k ↔ ∀ a ∈ ℕ 0 # b ⁡ a = L → a = ∑ k ∈ 0 ..^ L k digit ⁡ 2 a ⁢ 2 k
27 0cnd ⊢ a ∈ ℕ 0 → 0 ∈ ℂ
28 2nn ⊢ 2 ∈ ℕ
29 28 a1i ⊢ a ∈ ℕ 0 → 2 ∈ ℕ
30 0zd ⊢ a ∈ ℕ 0 → 0 ∈ ℤ
31 nn0rp0 ⊢ a ∈ ℕ 0 → a ∈ 0 +∞
32 digvalnn0 ⊢ 2 ∈ ℕ ∧ 0 ∈ ℤ ∧ a ∈ 0 +∞ → 0 digit ⁡ 2 a ∈ ℕ 0
33 29 30 31 32 syl3anc ⊢ a ∈ ℕ 0 → 0 digit ⁡ 2 a ∈ ℕ 0
34 33 nn0cnd ⊢ a ∈ ℕ 0 → 0 digit ⁡ 2 a ∈ ℂ
35 1cnd ⊢ a ∈ ℕ 0 → 1 ∈ ℂ
36 34 35 mulcld ⊢ a ∈ ℕ 0 → 0 digit ⁡ 2 a ⋅ 1 ∈ ℂ
37 27 36 jca ⊢ a ∈ ℕ 0 → 0 ∈ ℂ ∧ 0 digit ⁡ 2 a ⋅ 1 ∈ ℂ
38 37 adantr ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → 0 ∈ ℂ ∧ 0 digit ⁡ 2 a ⋅ 1 ∈ ℂ
39 oveq1 ⊢ k = 0 → k digit ⁡ 2 a = 0 digit ⁡ 2 a
40 oveq2 ⊢ k = 0 → 2 k = 2 0
41 2cn ⊢ 2 ∈ ℂ
42 exp0 ⊢ 2 ∈ ℂ → 2 0 = 1
43 41 42 ax-mp ⊢ 2 0 = 1
44 40 43 eqtrdi ⊢ k = 0 → 2 k = 1
45 39 44 oveq12d ⊢ k = 0 → k digit ⁡ 2 a ⁢ 2 k = 0 digit ⁡ 2 a ⋅ 1
46 45 sumsn ⊢ 0 ∈ ℂ ∧ 0 digit ⁡ 2 a ⋅ 1 ∈ ℂ → ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k = 0 digit ⁡ 2 a ⋅ 1
47 38 46 syl ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k = 0 digit ⁡ 2 a ⋅ 1
48 34 adantr ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → 0 digit ⁡ 2 a ∈ ℂ
49 48 mulridd ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → 0 digit ⁡ 2 a ⋅ 1 = 0 digit ⁡ 2 a
50 blen1b ⊢ a ∈ ℕ 0 → # b ⁡ a = 1 ↔ a = 0 ∨ a = 1
51 50 biimpa ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → a = 0 ∨ a = 1
52 vex ⊢ a ∈ V
53 52 elpr ⊢ a ∈ 0 1 ↔ a = 0 ∨ a = 1
54 51 53 sylibr ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → a ∈ 0 1
55 0dig2pr01 ⊢ a ∈ 0 1 → 0 digit ⁡ 2 a = a
56 54 55 syl ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → 0 digit ⁡ 2 a = a
57 47 49 56 3eqtrrd ⊢ a ∈ ℕ 0 ∧ # b ⁡ a = 1 → a = ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k
58 57 ex ⊢ a ∈ ℕ 0 → # b ⁡ a = 1 → a = ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k
59 58 rgen ⊢ ∀ a ∈ ℕ 0 # b ⁡ a = 1 → a = ∑ k ∈ 0 k digit ⁡ 2 a ⁢ 2 k
60 nn0sumshdiglem1 ⊢ y ∈ ℕ → ∀ a ∈ ℕ 0 # b ⁡ a = y → a = ∑ k ∈ 0 ..^ y k digit ⁡ 2 a ⁢ 2 k → ∀ a ∈ ℕ 0 # b ⁡ a = y + 1 → a = ∑ k ∈ 0 ..^ y + 1 k digit ⁡ 2 a ⁢ 2 k
61 8 14 20 26 59 60 nnind ⊢ L ∈ ℕ → ∀ a ∈ ℕ 0 # b ⁡ a = L → a = ∑ k ∈ 0 ..^ L k digit ⁡ 2 a ⁢ 2 k