Metamath Proof Explorer


Theorem onetansqsecsq

Description: Prove the tangent squared secant squared identity ( 1 + ( ( tanA ) ^ 2 ) ) = ( ( secA ) ^ 2 ) ) . (Contributed by David A. Wheeler, 25-May-2015)

Ref Expression
Assertion onetansqsecsq ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 + tan ⁡ A 2 = sec ⁡ A 2

Proof

Step Hyp Ref Expression
1 coscl ⊢ A ∈ ℂ → cos ⁡ A ∈ ℂ
2 sqeq0 ⊢ cos ⁡ A ∈ ℂ → cos ⁡ A 2 = 0 ↔ cos ⁡ A = 0
3 1 2 syl ⊢ A ∈ ℂ → cos ⁡ A 2 = 0 ↔ cos ⁡ A = 0
4 3 necon3bid ⊢ A ∈ ℂ → cos ⁡ A 2 ≠ 0 ↔ cos ⁡ A ≠ 0
5 4 biimpar ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → cos ⁡ A 2 ≠ 0
6 1 sqcld ⊢ A ∈ ℂ → cos ⁡ A 2 ∈ ℂ
7 divid ⊢ cos ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 cos ⁡ A 2 = 1
8 6 7 sylan ⊢ A ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 cos ⁡ A 2 = 1
9 5 8 syldan ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → cos ⁡ A 2 cos ⁡ A 2 = 1
10 9 eqcomd ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 = cos ⁡ A 2 cos ⁡ A 2
11 tanval ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → tan ⁡ A = sin ⁡ A cos ⁡ A
12 11 oveq1d ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → tan ⁡ A 2 = sin ⁡ A cos ⁡ A 2
13 2nn0 ⊢ 2 ∈ ℕ 0
14 sincl ⊢ A ∈ ℂ → sin ⁡ A ∈ ℂ
15 expdiv ⊢ sin ⁡ A ∈ ℂ ∧ cos ⁡ A ∈ ℂ ∧ cos ⁡ A ≠ 0 ∧ 2 ∈ ℕ 0 → sin ⁡ A cos ⁡ A 2 = sin ⁡ A 2 cos ⁡ A 2
16 14 15 syl3an1 ⊢ A ∈ ℂ ∧ cos ⁡ A ∈ ℂ ∧ cos ⁡ A ≠ 0 ∧ 2 ∈ ℕ 0 → sin ⁡ A cos ⁡ A 2 = sin ⁡ A 2 cos ⁡ A 2
17 13 16 mp3an3 ⊢ A ∈ ℂ ∧ cos ⁡ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sin ⁡ A cos ⁡ A 2 = sin ⁡ A 2 cos ⁡ A 2
18 17 3impb ⊢ A ∈ ℂ ∧ cos ⁡ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sin ⁡ A cos ⁡ A 2 = sin ⁡ A 2 cos ⁡ A 2
19 1 18 syl3an2 ⊢ A ∈ ℂ ∧ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sin ⁡ A cos ⁡ A 2 = sin ⁡ A 2 cos ⁡ A 2
20 19 3anidm12 ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sin ⁡ A cos ⁡ A 2 = sin ⁡ A 2 cos ⁡ A 2
21 12 20 eqtrd ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → tan ⁡ A 2 = sin ⁡ A 2 cos ⁡ A 2
22 10 21 oveq12d ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 + tan ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
23 14 sqcld ⊢ A ∈ ℂ → sin ⁡ A 2 ∈ ℂ
24 divdir ⊢ cos ⁡ A 2 ∈ ℂ ∧ sin ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
25 6 24 syl3an1 ⊢ A ∈ ℂ ∧ sin ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
26 23 25 syl3an2 ⊢ A ∈ ℂ ∧ A ∈ ℂ ∧ cos ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
27 26 3anidm12 ⊢ A ∈ ℂ ∧ cos ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
28 27 3impb ⊢ A ∈ ℂ ∧ cos ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
29 6 28 syl3an2 ⊢ A ∈ ℂ ∧ A ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
30 29 3anidm12 ⊢ A ∈ ℂ ∧ cos ⁡ A 2 ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
31 5 30 syldan ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = cos ⁡ A 2 cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
32 22 31 eqtr4d ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 + tan ⁡ A 2 = cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2
33 23 6 addcomd ⊢ A ∈ ℂ → sin ⁡ A 2 + cos ⁡ A 2 = cos ⁡ A 2 + sin ⁡ A 2
34 sincossq ⊢ A ∈ ℂ → sin ⁡ A 2 + cos ⁡ A 2 = 1
35 33 34 eqtr3d ⊢ A ∈ ℂ → cos ⁡ A 2 + sin ⁡ A 2 = 1
36 35 oveq1d ⊢ A ∈ ℂ → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = 1 cos ⁡ A 2
37 36 adantr ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → cos ⁡ A 2 + sin ⁡ A 2 cos ⁡ A 2 = 1 cos ⁡ A 2
38 32 37 eqtrd ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 + tan ⁡ A 2 = 1 cos ⁡ A 2
39 secval ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sec ⁡ A = 1 cos ⁡ A
40 39 oveq1d ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sec ⁡ A 2 = 1 cos ⁡ A 2
41 ax-1cn ⊢ 1 ∈ ℂ
42 expdiv ⊢ 1 ∈ ℂ ∧ cos ⁡ A ∈ ℂ ∧ cos ⁡ A ≠ 0 ∧ 2 ∈ ℕ 0 → 1 cos ⁡ A 2 = 1 2 cos ⁡ A 2
43 41 13 42 mp3an13 ⊢ cos ⁡ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 cos ⁡ A 2 = 1 2 cos ⁡ A 2
44 1 43 sylan ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 cos ⁡ A 2 = 1 2 cos ⁡ A 2
45 sq1 ⊢ 1 2 = 1
46 45 oveq1i ⊢ 1 2 cos ⁡ A 2 = 1 cos ⁡ A 2
47 44 46 eqtrdi ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 cos ⁡ A 2 = 1 cos ⁡ A 2
48 40 47 eqtrd ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sec ⁡ A 2 = 1 cos ⁡ A 2
49 38 48 eqtr4d ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → 1 + tan ⁡ A 2 = sec ⁡ A 2