Metamath Proof Explorer


Theorem psgnuni

Description: If the same permutation can be written in more than one way as a product of transpositions, the parity of those products must agree; otherwise the product of one with the inverse of the other would be an odd representation of the identity. (Contributed by Stefan O'Rear, 27-Aug-2015)

Ref Expression
Hypotheses psgnuni.g ⊢ G = SymGrp ⁡ D
psgnuni.t ⊢ T = ran ⁡ pmTrsp ⁡ D
psgnuni.d ⊢ φ → D ∈ V
psgnuni.w ⊢ φ → W ∈ Word T
psgnuni.x ⊢ φ → X ∈ Word T
psgnuni.e ⊢ φ → ∑ G W = ∑ G X
Assertion psgnuni ⊢ φ → − 1 W = − 1 X

Proof

Step Hyp Ref Expression
1 psgnuni.g ⊢ G = SymGrp ⁡ D
2 psgnuni.t ⊢ T = ran ⁡ pmTrsp ⁡ D
3 psgnuni.d ⊢ φ → D ∈ V
4 psgnuni.w ⊢ φ → W ∈ Word T
5 psgnuni.x ⊢ φ → X ∈ Word T
6 psgnuni.e ⊢ φ → ∑ G W = ∑ G X
7 lencl ⊢ W ∈ Word T → W ∈ ℕ 0
8 4 7 syl ⊢ φ → W ∈ ℕ 0
9 8 nn0zd ⊢ φ → W ∈ ℤ
10 m1expcl ⊢ W ∈ ℤ → − 1 W ∈ ℤ
11 9 10 syl ⊢ φ → − 1 W ∈ ℤ
12 11 zcnd ⊢ φ → − 1 W ∈ ℂ
13 lencl ⊢ X ∈ Word T → X ∈ ℕ 0
14 5 13 syl ⊢ φ → X ∈ ℕ 0
15 14 nn0zd ⊢ φ → X ∈ ℤ
16 m1expcl ⊢ X ∈ ℤ → − 1 X ∈ ℤ
17 15 16 syl ⊢ φ → − 1 X ∈ ℤ
18 17 zcnd ⊢ φ → − 1 X ∈ ℂ
19 neg1cn ⊢ − 1 ∈ ℂ
20 neg1ne0 ⊢ − 1 ≠ 0
21 expne0i ⊢ − 1 ∈ ℂ ∧ − 1 ≠ 0 ∧ X ∈ ℤ → − 1 X ≠ 0
22 19 20 15 21 mp3an12i ⊢ φ → − 1 X ≠ 0
23 m1expaddsub ⊢ W ∈ ℤ ∧ X ∈ ℤ → − 1 W − X = − 1 W + X
24 9 15 23 syl2anc ⊢ φ → − 1 W − X = − 1 W + X
25 expsub ⊢ − 1 ∈ ℂ ∧ − 1 ≠ 0 ∧ W ∈ ℤ ∧ X ∈ ℤ → − 1 W − X = − 1 W − 1 X
26 19 20 25 mpanl12 ⊢ W ∈ ℤ ∧ X ∈ ℤ → − 1 W − X = − 1 W − 1 X
27 9 15 26 syl2anc ⊢ φ → − 1 W − X = − 1 W − 1 X
28 revcl ⊢ X ∈ Word T → reverse ⁡ X ∈ Word T
29 5 28 syl ⊢ φ → reverse ⁡ X ∈ Word T
30 ccatlen ⊢ W ∈ Word T ∧ reverse ⁡ X ∈ Word T → W ++ reverse ⁡ X = W + reverse ⁡ X
31 4 29 30 syl2anc ⊢ φ → W ++ reverse ⁡ X = W + reverse ⁡ X
32 revlen ⊢ X ∈ Word T → reverse ⁡ X = X
33 5 32 syl ⊢ φ → reverse ⁡ X = X
34 33 oveq2d ⊢ φ → W + reverse ⁡ X = W + X
35 31 34 eqtr2d ⊢ φ → W + X = W ++ reverse ⁡ X
36 35 oveq2d ⊢ φ → − 1 W + X = − 1 W ++ reverse ⁡ X
37 ccatcl ⊢ W ∈ Word T ∧ reverse ⁡ X ∈ Word T → W ++ reverse ⁡ X ∈ Word T
38 4 29 37 syl2anc ⊢ φ → W ++ reverse ⁡ X ∈ Word T
39 6 fveq2d ⊢ φ → inv g ⁡ G ⁡ ∑ G W = inv g ⁡ G ⁡ ∑ G X
40 eqid ⊢ inv g ⁡ G = inv g ⁡ G
41 2 1 40 symgtrinv ⊢ D ∈ V ∧ X ∈ Word T → inv g ⁡ G ⁡ ∑ G X = ∑ G reverse ⁡ X
42 3 5 41 syl2anc ⊢ φ → inv g ⁡ G ⁡ ∑ G X = ∑ G reverse ⁡ X
43 39 42 eqtr2d ⊢ φ → ∑ G reverse ⁡ X = inv g ⁡ G ⁡ ∑ G W
44 43 oveq2d ⊢ φ → ∑ G W + G ∑ G reverse ⁡ X = ∑ G W + G inv g ⁡ G ⁡ ∑ G W
45 1 symggrp ⊢ D ∈ V → G ∈ Grp
46 3 45 syl ⊢ φ → G ∈ Grp
47 grpmnd ⊢ G ∈ Grp → G ∈ Mnd
48 3 45 47 3syl ⊢ φ → G ∈ Mnd
49 eqid ⊢ Base G = Base G
50 2 1 49 symgtrf ⊢ T ⊆ Base G
51 sswrd ⊢ T ⊆ Base G → Word T ⊆ Word Base G
52 50 51 ax-mp ⊢ Word T ⊆ Word Base G
53 52 4 sselid ⊢ φ → W ∈ Word Base G
54 49 gsumwcl ⊢ G ∈ Mnd ∧ W ∈ Word Base G → ∑ G W ∈ Base G
55 48 53 54 syl2anc ⊢ φ → ∑ G W ∈ Base G
56 eqid ⊢ + G = + G
57 eqid ⊢ 0 G = 0 G
58 49 56 57 40 grprinv ⊢ G ∈ Grp ∧ ∑ G W ∈ Base G → ∑ G W + G inv g ⁡ G ⁡ ∑ G W = 0 G
59 46 55 58 syl2anc ⊢ φ → ∑ G W + G inv g ⁡ G ⁡ ∑ G W = 0 G
60 44 59 eqtrd ⊢ φ → ∑ G W + G ∑ G reverse ⁡ X = 0 G
61 52 29 sselid ⊢ φ → reverse ⁡ X ∈ Word Base G
62 49 56 gsumccat ⊢ G ∈ Mnd ∧ W ∈ Word Base G ∧ reverse ⁡ X ∈ Word Base G → ∑ G W ++ reverse ⁡ X = ∑ G W + G ∑ G reverse ⁡ X
63 48 53 61 62 syl3anc ⊢ φ → ∑ G W ++ reverse ⁡ X = ∑ G W + G ∑ G reverse ⁡ X
64 1 symgid ⊢ D ∈ V → I ↾ D = 0 G
65 3 64 syl ⊢ φ → I ↾ D = 0 G
66 60 63 65 3eqtr4d ⊢ φ → ∑ G W ++ reverse ⁡ X = I ↾ D
67 1 2 3 38 66 psgnunilem4 ⊢ φ → − 1 W ++ reverse ⁡ X = 1
68 36 67 eqtrd ⊢ φ → − 1 W + X = 1
69 24 27 68 3eqtr3d ⊢ φ → − 1 W − 1 X = 1
70 12 18 22 69 diveq1d ⊢ φ → − 1 W = − 1 X