Metamath Proof Explorer


Theorem recgt0

Description: The reciprocal of a positive number is positive. Exercise 4 of Apostol p. 21. (Contributed by NM, 25-Aug-1999) (Revised by Mario Carneiro, 27-May-2016)

Ref Expression
Assertion recgt0 ⊢ A ∈ ℝ ∧ 0 < A → 0 < 1 A

Proof

Step Hyp Ref Expression
1 simpl ⊢ A ∈ ℝ ∧ 0 < A → A ∈ ℝ
2 1 recnd ⊢ A ∈ ℝ ∧ 0 < A → A ∈ ℂ
3 gt0ne0 ⊢ A ∈ ℝ ∧ 0 < A → A ≠ 0
4 2 3 recne0d ⊢ A ∈ ℝ ∧ 0 < A → 1 A ≠ 0
5 4 necomd ⊢ A ∈ ℝ ∧ 0 < A → 0 ≠ 1 A
6 5 neneqd ⊢ A ∈ ℝ ∧ 0 < A → ¬ 0 = 1 A
7 0lt1 ⊢ 0 < 1
8 0re ⊢ 0 ∈ ℝ
9 1re ⊢ 1 ∈ ℝ
10 8 9 ltnsymi ⊢ 0 < 1 → ¬ 1 < 0
11 7 10 ax-mp ⊢ ¬ 1 < 0
12 simpll ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → A ∈ ℝ
13 3 adantr ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → A ≠ 0
14 12 13 rereccld ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 A ∈ ℝ
15 14 renegcld ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → − 1 A ∈ ℝ
16 simpr ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 A < 0
17 1 3 rereccld ⊢ A ∈ ℝ ∧ 0 < A → 1 A ∈ ℝ
18 17 adantr ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 A ∈ ℝ
19 18 lt0neg1d ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 A < 0 ↔ 0 < − 1 A
20 16 19 mpbid ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 0 < − 1 A
21 simplr ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 0 < A
22 15 12 20 21 mulgt0d ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 0 < − 1 A ⁢ A
23 2 adantr ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → A ∈ ℂ
24 23 13 reccld ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 A ∈ ℂ
25 24 23 mulneg1d ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → − 1 A ⁢ A = − 1 A ⁢ A
26 23 13 recid2d ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 A ⁢ A = 1
27 26 negeqd ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → − 1 A ⁢ A = − 1
28 25 27 eqtrd ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → − 1 A ⁢ A = − 1
29 22 28 breqtrd ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 0 < − 1
30 1red ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 ∈ ℝ
31 30 lt0neg1d ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 < 0 ↔ 0 < − 1
32 29 31 mpbird ⊢ A ∈ ℝ ∧ 0 < A ∧ 1 A < 0 → 1 < 0
33 32 ex ⊢ A ∈ ℝ ∧ 0 < A → 1 A < 0 → 1 < 0
34 11 33 mtoi ⊢ A ∈ ℝ ∧ 0 < A → ¬ 1 A < 0
35 ioran ⊢ ¬ 0 = 1 A ∨ 1 A < 0 ↔ ¬ 0 = 1 A ∧ ¬ 1 A < 0
36 6 34 35 sylanbrc ⊢ A ∈ ℝ ∧ 0 < A → ¬ 0 = 1 A ∨ 1 A < 0
37 axlttri ⊢ 0 ∈ ℝ ∧ 1 A ∈ ℝ → 0 < 1 A ↔ ¬ 0 = 1 A ∨ 1 A < 0
38 8 17 37 sylancr ⊢ A ∈ ℝ ∧ 0 < A → 0 < 1 A ↔ ¬ 0 = 1 A ∨ 1 A < 0
39 36 38 mpbird ⊢ A ∈ ℝ ∧ 0 < A → 0 < 1 A