Metamath Proof Explorer


Theorem shatomistici

Description: The lattice of Hilbert subspaces is atomistic, i.e. any element is the supremum of its atoms. Part of proof of Theorem 16.9 of MaedaMaeda p. 70. (Contributed by NM, 26-Nov-2004) (New usage is discouraged.)

Ref Expression
Hypothesis shatomistic.1 ⊢ A ∈ S ℋ
Assertion shatomistici ⊢ A = span ⁡ ⋃ x ∈ HAtoms | x ⊆ A

Proof

Step Hyp Ref Expression
1 shatomistic.1 ⊢ A ∈ S ℋ
2 eleq1 ⊢ y = 0 ℎ → y ∈ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A ↔ 0 ℎ ∈ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
3 1 sheli ⊢ y ∈ A → y ∈ ℋ
4 spansnsh ⊢ y ∈ ℋ → span ⁡ y ∈ S ℋ
5 spanid ⊢ span ⁡ y ∈ S ℋ → span ⁡ span ⁡ y = span ⁡ y
6 3 4 5 3syl ⊢ y ∈ A → span ⁡ span ⁡ y = span ⁡ y
7 6 adantr ⊢ y ∈ A ∧ y ≠ 0 ℎ → span ⁡ span ⁡ y = span ⁡ y
8 spansna ⊢ y ∈ ℋ ∧ y ≠ 0 ℎ → span ⁡ y ∈ HAtoms
9 3 8 sylan ⊢ y ∈ A ∧ y ≠ 0 ℎ → span ⁡ y ∈ HAtoms
10 spansnss ⊢ A ∈ S ℋ ∧ y ∈ A → span ⁡ y ⊆ A
11 1 10 mpan ⊢ y ∈ A → span ⁡ y ⊆ A
12 11 adantr ⊢ y ∈ A ∧ y ≠ 0 ℎ → span ⁡ y ⊆ A
13 sseq1 ⊢ x = span ⁡ y → x ⊆ A ↔ span ⁡ y ⊆ A
14 13 elrab ⊢ span ⁡ y ∈ x ∈ HAtoms | x ⊆ A ↔ span ⁡ y ∈ HAtoms ∧ span ⁡ y ⊆ A
15 9 12 14 sylanbrc ⊢ y ∈ A ∧ y ≠ 0 ℎ → span ⁡ y ∈ x ∈ HAtoms | x ⊆ A
16 elssuni ⊢ span ⁡ y ∈ x ∈ HAtoms | x ⊆ A → span ⁡ y ⊆ ⋃ x ∈ HAtoms | x ⊆ A
17 atssch ⊢ HAtoms ⊆ C ℋ
18 chsssh ⊢ C ℋ ⊆ S ℋ
19 17 18 sstri ⊢ HAtoms ⊆ S ℋ
20 rabss2 ⊢ HAtoms ⊆ S ℋ → x ∈ HAtoms | x ⊆ A ⊆ x ∈ S ℋ | x ⊆ A
21 uniss ⊢ x ∈ HAtoms | x ⊆ A ⊆ x ∈ S ℋ | x ⊆ A → ⋃ x ∈ HAtoms | x ⊆ A ⊆ ⋃ x ∈ S ℋ | x ⊆ A
22 19 20 21 mp2b ⊢ ⋃ x ∈ HAtoms | x ⊆ A ⊆ ⋃ x ∈ S ℋ | x ⊆ A
23 unimax ⊢ A ∈ S ℋ → ⋃ x ∈ S ℋ | x ⊆ A = A
24 1 23 ax-mp ⊢ ⋃ x ∈ S ℋ | x ⊆ A = A
25 1 shssii ⊢ A ⊆ ℋ
26 24 25 eqsstri ⊢ ⋃ x ∈ S ℋ | x ⊆ A ⊆ ℋ
27 22 26 sstri ⊢ ⋃ x ∈ HAtoms | x ⊆ A ⊆ ℋ
28 spanss ⊢ ⋃ x ∈ HAtoms | x ⊆ A ⊆ ℋ ∧ span ⁡ y ⊆ ⋃ x ∈ HAtoms | x ⊆ A → span ⁡ span ⁡ y ⊆ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
29 27 28 mpan ⊢ span ⁡ y ⊆ ⋃ x ∈ HAtoms | x ⊆ A → span ⁡ span ⁡ y ⊆ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
30 15 16 29 3syl ⊢ y ∈ A ∧ y ≠ 0 ℎ → span ⁡ span ⁡ y ⊆ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
31 7 30 eqsstrrd ⊢ y ∈ A ∧ y ≠ 0 ℎ → span ⁡ y ⊆ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
32 spansnid ⊢ y ∈ ℋ → y ∈ span ⁡ y
33 3 32 syl ⊢ y ∈ A → y ∈ span ⁡ y
34 33 adantr ⊢ y ∈ A ∧ y ≠ 0 ℎ → y ∈ span ⁡ y
35 31 34 sseldd ⊢ y ∈ A ∧ y ≠ 0 ℎ → y ∈ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
36 spancl ⊢ ⋃ x ∈ HAtoms | x ⊆ A ⊆ ℋ → span ⁡ ⋃ x ∈ HAtoms | x ⊆ A ∈ S ℋ
37 sh0 ⊢ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A ∈ S ℋ → 0 ℎ ∈ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
38 27 36 37 mp2b ⊢ 0 ℎ ∈ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
39 38 a1i ⊢ y ∈ A → 0 ℎ ∈ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
40 2 35 39 pm2.61ne ⊢ y ∈ A → y ∈ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
41 40 ssriv ⊢ A ⊆ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A
42 spanss ⊢ ⋃ x ∈ S ℋ | x ⊆ A ⊆ ℋ ∧ ⋃ x ∈ HAtoms | x ⊆ A ⊆ ⋃ x ∈ S ℋ | x ⊆ A → span ⁡ ⋃ x ∈ HAtoms | x ⊆ A ⊆ span ⁡ ⋃ x ∈ S ℋ | x ⊆ A
43 26 22 42 mp2an ⊢ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A ⊆ span ⁡ ⋃ x ∈ S ℋ | x ⊆ A
44 24 fveq2i ⊢ span ⁡ ⋃ x ∈ S ℋ | x ⊆ A = span ⁡ A
45 spanid ⊢ A ∈ S ℋ → span ⁡ A = A
46 1 45 ax-mp ⊢ span ⁡ A = A
47 44 46 eqtri ⊢ span ⁡ ⋃ x ∈ S ℋ | x ⊆ A = A
48 43 47 sseqtri ⊢ span ⁡ ⋃ x ∈ HAtoms | x ⊆ A ⊆ A
49 41 48 eqssi ⊢ A = span ⁡ ⋃ x ∈ HAtoms | x ⊆ A