Metamath Proof Explorer


Theorem sigaclcu2

Description: A sigma-algebra is closed under countable union - indexing on NN (Contributed by Thierry Arnoux, 29-Dec-2016)

Ref Expression
Assertion sigaclcu2 S ran sigAlgebra k A S k A S

Proof

Step Hyp Ref Expression
1 dfiun2g k A S k A = x | k x = A
2 1 adantl S ran sigAlgebra k A S k A = x | k x = A
3 simpl S ran sigAlgebra k A S S ran sigAlgebra
4 abid x x | k x = A k x = A
5 eleq1a A S x = A x S
6 5 ralimi k A S k x = A x S
7 r19.23v k x = A x S k x = A x S
8 6 7 sylib k A S k x = A x S
9 8 imp k A S k x = A x S
10 9 adantll S ran sigAlgebra k A S k x = A x S
11 4 10 sylan2b S ran sigAlgebra k A S x x | k x = A x S
12 11 ralrimiva S ran sigAlgebra k A S x x | k x = A x S
13 nfab1 _ x x | k x = A
14 nfcv _ x S
15 13 14 dfss3f x | k x = A S x x | k x = A x S
16 12 15 sylibr S ran sigAlgebra k A S x | k x = A S
17 elpw2g S ran sigAlgebra x | k x = A 𝒫 S x | k x = A S
18 17 adantr S ran sigAlgebra k A S x | k x = A 𝒫 S x | k x = A S
19 16 18 mpbird S ran sigAlgebra k A S x | k x = A 𝒫 S
20 nnct ω
21 abrexct ω x | k x = A ω
22 20 21 mp1i S ran sigAlgebra k A S x | k x = A ω
23 sigaclcu S ran sigAlgebra x | k x = A 𝒫 S x | k x = A ω x | k x = A S
24 3 19 22 23 syl3anc S ran sigAlgebra k A S x | k x = A S
25 2 24 eqeltrd S ran sigAlgebra k A S k A S