Metamath Proof Explorer


Theorem subrgsubm

Description: A subring is a submonoid of the multiplicative monoid. (Contributed by Mario Carneiro, 15-Jun-2015)

Ref Expression
Hypothesis subrgsubm.1 ⊢ M = mulGrp R
Assertion subrgsubm ⊢ A ∈ SubRing ⁡ R → A ∈ SubMnd ⁡ M

Proof

Step Hyp Ref Expression
1 subrgsubm.1 ⊢ M = mulGrp R
2 eqid ⊢ Base R = Base R
3 2 subrgss ⊢ A ∈ SubRing ⁡ R → A ⊆ Base R
4 eqid ⊢ 1 R = 1 R
5 4 subrg1cl ⊢ A ∈ SubRing ⁡ R → 1 R ∈ A
6 subrgrcl ⊢ A ∈ SubRing ⁡ R → R ∈ Ring
7 eqid ⊢ R ↾ 𝑠 A = R ↾ 𝑠 A
8 7 1 mgpress ⊢ R ∈ Ring ∧ A ∈ SubRing ⁡ R → M ↾ 𝑠 A = mulGrp R ↾ 𝑠 A
9 6 8 mpancom ⊢ A ∈ SubRing ⁡ R → M ↾ 𝑠 A = mulGrp R ↾ 𝑠 A
10 7 subrgring ⊢ A ∈ SubRing ⁡ R → R ↾ 𝑠 A ∈ Ring
11 eqid ⊢ mulGrp R ↾ 𝑠 A = mulGrp R ↾ 𝑠 A
12 11 ringmgp ⊢ R ↾ 𝑠 A ∈ Ring → mulGrp R ↾ 𝑠 A ∈ Mnd
13 10 12 syl ⊢ A ∈ SubRing ⁡ R → mulGrp R ↾ 𝑠 A ∈ Mnd
14 9 13 eqeltrd ⊢ A ∈ SubRing ⁡ R → M ↾ 𝑠 A ∈ Mnd
15 1 ringmgp ⊢ R ∈ Ring → M ∈ Mnd
16 1 2 mgpbas ⊢ Base R = Base M
17 1 4 ringidval ⊢ 1 R = 0 M
18 eqid ⊢ M ↾ 𝑠 A = M ↾ 𝑠 A
19 16 17 18 issubm2 ⊢ M ∈ Mnd → A ∈ SubMnd ⁡ M ↔ A ⊆ Base R ∧ 1 R ∈ A ∧ M ↾ 𝑠 A ∈ Mnd
20 6 15 19 3syl ⊢ A ∈ SubRing ⁡ R → A ∈ SubMnd ⁡ M ↔ A ⊆ Base R ∧ 1 R ∈ A ∧ M ↾ 𝑠 A ∈ Mnd
21 3 5 14 20 mpbir3and ⊢ A ∈ SubRing ⁡ R → A ∈ SubMnd ⁡ M