Metamath Proof Explorer


Theorem canthnumlem

Description: Lemma for canthnum . (Contributed by Mario Carneiro, 19-May-2015)

Ref Expression
Hypotheses canth4.1 ⊢ W = x r | x ⊆ A ∧ r ⊆ x × x ∧ r We x ∧ ∀ y ∈ x F ⁡ r -1 y = y
canth4.2 ⊢ B = ⋃ dom ⁡ W
canth4.3 ⊢ C = W ⁡ B -1 F ⁡ B
Assertion canthnumlem ⊢ A ∈ V → ¬ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A

Proof

Step Hyp Ref Expression
1 canth4.1 ⊢ W = x r | x ⊆ A ∧ r ⊆ x × x ∧ r We x ∧ ∀ y ∈ x F ⁡ r -1 y = y
2 canth4.2 ⊢ B = ⋃ dom ⁡ W
3 canth4.3 ⊢ C = W ⁡ B -1 F ⁡ B
4 f1f ⊢ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → F : 𝒫 A ∩ dom ⁡ card ⟶ A
5 ssid ⊢ 𝒫 A ∩ dom ⁡ card ⊆ 𝒫 A ∩ dom ⁡ card
6 1 2 3 canth4 ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ A ∧ 𝒫 A ∩ dom ⁡ card ⊆ 𝒫 A ∩ dom ⁡ card → B ⊆ A ∧ C ⊂ B ∧ F ⁡ B = F ⁡ C
7 5 6 mp3an3 ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ A → B ⊆ A ∧ C ⊂ B ∧ F ⁡ B = F ⁡ C
8 4 7 sylan2 ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ⊆ A ∧ C ⊂ B ∧ F ⁡ B = F ⁡ C
9 8 simp3d ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → F ⁡ B = F ⁡ C
10 simpr ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A
11 8 simp1d ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ⊆ A
12 elpw2g ⊢ A ∈ V → B ∈ 𝒫 A ↔ B ⊆ A
13 12 adantr ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ∈ 𝒫 A ↔ B ⊆ A
14 11 13 mpbird ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ∈ 𝒫 A
15 eqid ⊢ B = B
16 eqid ⊢ W ⁡ B = W ⁡ B
17 15 16 pm3.2i ⊢ B = B ∧ W ⁡ B = W ⁡ B
18 simpl ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → A ∈ V
19 10 4 syl ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → F : 𝒫 A ∩ dom ⁡ card ⟶ A
20 19 ffvelcdmda ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A ∧ x ∈ 𝒫 A ∩ dom ⁡ card → F ⁡ x ∈ A
21 1 18 20 2 fpwwe ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B W W ⁡ B ∧ F ⁡ B ∈ B ↔ B = B ∧ W ⁡ B = W ⁡ B
22 17 21 mpbiri ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B W W ⁡ B ∧ F ⁡ B ∈ B
23 22 simpld ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B W W ⁡ B
24 1 18 fpwwelem ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B W W ⁡ B ↔ B ⊆ A ∧ W ⁡ B ⊆ B × B ∧ W ⁡ B We B ∧ ∀ y ∈ B F ⁡ W ⁡ B -1 y = y
25 23 24 mpbid ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ⊆ A ∧ W ⁡ B ⊆ B × B ∧ W ⁡ B We B ∧ ∀ y ∈ B F ⁡ W ⁡ B -1 y = y
26 25 simprld ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → W ⁡ B We B
27 fvex ⊢ W ⁡ B ∈ V
28 weeq1 ⊢ r = W ⁡ B → r We B ↔ W ⁡ B We B
29 27 28 spcev ⊢ W ⁡ B We B → ∃ r r We B
30 26 29 syl ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → ∃ r r We B
31 ween ⊢ B ∈ dom ⁡ card ↔ ∃ r r We B
32 30 31 sylibr ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ∈ dom ⁡ card
33 14 32 elind ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ∈ 𝒫 A ∩ dom ⁡ card
34 8 simp2d ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ⊂ B
35 34 pssssd ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ⊆ B
36 35 11 sstrd ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ⊆ A
37 elpw2g ⊢ A ∈ V → C ∈ 𝒫 A ↔ C ⊆ A
38 37 adantr ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ∈ 𝒫 A ↔ C ⊆ A
39 36 38 mpbird ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ∈ 𝒫 A
40 ssnum ⊢ B ∈ dom ⁡ card ∧ C ⊆ B → C ∈ dom ⁡ card
41 32 35 40 syl2anc ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ∈ dom ⁡ card
42 39 41 elind ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ∈ 𝒫 A ∩ dom ⁡ card
43 f1fveq ⊢ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A ∧ B ∈ 𝒫 A ∩ dom ⁡ card ∧ C ∈ 𝒫 A ∩ dom ⁡ card → F ⁡ B = F ⁡ C ↔ B = C
44 10 33 42 43 syl12anc ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → F ⁡ B = F ⁡ C ↔ B = C
45 9 44 mpbid ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B = C
46 34 pssned ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → C ≠ B
47 46 necomd ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → B ≠ C
48 47 neneqd ⊢ A ∈ V ∧ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A → ¬ B = C
49 45 48 pm2.65da ⊢ A ∈ V → ¬ F : 𝒫 A ∩ dom ⁡ card ⟶ 1-1 A