Metamath Proof Explorer


Theorem cdj3lem2b

Description: Lemma for cdj3i . The first-component function S is bounded if the subspaces are completely disjoint. (Contributed by NM, 26-May-2005) (New usage is discouraged.)

Ref Expression
Hypotheses cdj3lem2.1 ⊢ A ∈ S ℋ
cdj3lem2.2 ⊢ B ∈ S ℋ
cdj3lem2.3 ⊢ S = x ∈ A + ℋ B ⟼ ι z ∈ A | ∃ w ∈ B x = z + ℎ w
Assertion cdj3lem2b ⊢ ∃ v ∈ ℝ 0 < v ∧ ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → ∃ v ∈ ℝ 0 < v ∧ ∀ u ∈ A + ℋ B norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u

Proof

Step Hyp Ref Expression
1 cdj3lem2.1 ⊢ A ∈ S ℋ
2 cdj3lem2.2 ⊢ B ∈ S ℋ
3 cdj3lem2.3 ⊢ S = x ∈ A + ℋ B ⟼ ι z ∈ A | ∃ w ∈ B x = z + ℎ w
4 1 2 cdj3lem1 ⊢ ∃ v ∈ ℝ 0 < v ∧ ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → A ∩ B = 0 ℋ
5 1 2 shseli ⊢ u ∈ A + ℋ B ↔ ∃ t ∈ A ∃ h ∈ B u = t + ℎ h
6 5 biimpi ⊢ u ∈ A + ℋ B → ∃ t ∈ A ∃ h ∈ B u = t + ℎ h
7 fveq2 ⊢ x = t → norm ℎ ⁡ x = norm ℎ ⁡ t
8 7 oveq1d ⊢ x = t → norm ℎ ⁡ x + norm ℎ ⁡ y = norm ℎ ⁡ t + norm ℎ ⁡ y
9 fvoveq1 ⊢ x = t → norm ℎ ⁡ x + ℎ y = norm ℎ ⁡ t + ℎ y
10 9 oveq2d ⊢ x = t → v ⁢ norm ℎ ⁡ x + ℎ y = v ⁢ norm ℎ ⁡ t + ℎ y
11 8 10 breq12d ⊢ x = t → norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y ↔ norm ℎ ⁡ t + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ t + ℎ y
12 fveq2 ⊢ y = h → norm ℎ ⁡ y = norm ℎ ⁡ h
13 12 oveq2d ⊢ y = h → norm ℎ ⁡ t + norm ℎ ⁡ y = norm ℎ ⁡ t + norm ℎ ⁡ h
14 oveq2 ⊢ y = h → t + ℎ y = t + ℎ h
15 14 fveq2d ⊢ y = h → norm ℎ ⁡ t + ℎ y = norm ℎ ⁡ t + ℎ h
16 15 oveq2d ⊢ y = h → v ⁢ norm ℎ ⁡ t + ℎ y = v ⁢ norm ℎ ⁡ t + ℎ h
17 13 16 breq12d ⊢ y = h → norm ℎ ⁡ t + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ t + ℎ y ↔ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h
18 11 17 rspc2v ⊢ t ∈ A ∧ h ∈ B → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h
19 1 2 3 cdj3lem2 ⊢ t ∈ A ∧ h ∈ B ∧ A ∩ B = 0 ℋ → S ⁡ t + ℎ h = t
20 19 3expa ⊢ t ∈ A ∧ h ∈ B ∧ A ∩ B = 0 ℋ → S ⁡ t + ℎ h = t
21 20 fveq2d ⊢ t ∈ A ∧ h ∈ B ∧ A ∩ B = 0 ℋ → norm ℎ ⁡ S ⁡ t + ℎ h = norm ℎ ⁡ t
22 21 ad2ant2r ⊢ t ∈ A ∧ h ∈ B ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h ∧ A ∩ B = 0 ℋ ∧ v ∈ ℝ → norm ℎ ⁡ S ⁡ t + ℎ h = norm ℎ ⁡ t
23 2 sheli ⊢ h ∈ B → h ∈ ℋ
24 normge0 ⊢ h ∈ ℋ → 0 ≤ norm ℎ ⁡ h
25 23 24 syl ⊢ h ∈ B → 0 ≤ norm ℎ ⁡ h
26 25 adantl ⊢ t ∈ A ∧ h ∈ B → 0 ≤ norm ℎ ⁡ h
27 1 sheli ⊢ t ∈ A → t ∈ ℋ
28 normcl ⊢ t ∈ ℋ → norm ℎ ⁡ t ∈ ℝ
29 27 28 syl ⊢ t ∈ A → norm ℎ ⁡ t ∈ ℝ
30 normcl ⊢ h ∈ ℋ → norm ℎ ⁡ h ∈ ℝ
31 23 30 syl ⊢ h ∈ B → norm ℎ ⁡ h ∈ ℝ
32 addge01 ⊢ norm ℎ ⁡ t ∈ ℝ ∧ norm ℎ ⁡ h ∈ ℝ → 0 ≤ norm ℎ ⁡ h ↔ norm ℎ ⁡ t ≤ norm ℎ ⁡ t + norm ℎ ⁡ h
33 29 31 32 syl2an ⊢ t ∈ A ∧ h ∈ B → 0 ≤ norm ℎ ⁡ h ↔ norm ℎ ⁡ t ≤ norm ℎ ⁡ t + norm ℎ ⁡ h
34 26 33 mpbid ⊢ t ∈ A ∧ h ∈ B → norm ℎ ⁡ t ≤ norm ℎ ⁡ t + norm ℎ ⁡ h
35 34 adantr ⊢ t ∈ A ∧ h ∈ B ∧ v ∈ ℝ → norm ℎ ⁡ t ≤ norm ℎ ⁡ t + norm ℎ ⁡ h
36 29 ad2antrr ⊢ t ∈ A ∧ h ∈ B ∧ v ∈ ℝ → norm ℎ ⁡ t ∈ ℝ
37 readdcl ⊢ norm ℎ ⁡ t ∈ ℝ ∧ norm ℎ ⁡ h ∈ ℝ → norm ℎ ⁡ t + norm ℎ ⁡ h ∈ ℝ
38 29 31 37 syl2an ⊢ t ∈ A ∧ h ∈ B → norm ℎ ⁡ t + norm ℎ ⁡ h ∈ ℝ
39 38 adantr ⊢ t ∈ A ∧ h ∈ B ∧ v ∈ ℝ → norm ℎ ⁡ t + norm ℎ ⁡ h ∈ ℝ
40 hvaddcl ⊢ t ∈ ℋ ∧ h ∈ ℋ → t + ℎ h ∈ ℋ
41 27 23 40 syl2an ⊢ t ∈ A ∧ h ∈ B → t + ℎ h ∈ ℋ
42 normcl ⊢ t + ℎ h ∈ ℋ → norm ℎ ⁡ t + ℎ h ∈ ℝ
43 41 42 syl ⊢ t ∈ A ∧ h ∈ B → norm ℎ ⁡ t + ℎ h ∈ ℝ
44 remulcl ⊢ v ∈ ℝ ∧ norm ℎ ⁡ t + ℎ h ∈ ℝ → v ⁢ norm ℎ ⁡ t + ℎ h ∈ ℝ
45 43 44 sylan2 ⊢ v ∈ ℝ ∧ t ∈ A ∧ h ∈ B → v ⁢ norm ℎ ⁡ t + ℎ h ∈ ℝ
46 45 ancoms ⊢ t ∈ A ∧ h ∈ B ∧ v ∈ ℝ → v ⁢ norm ℎ ⁡ t + ℎ h ∈ ℝ
47 letr ⊢ norm ℎ ⁡ t ∈ ℝ ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ∈ ℝ ∧ v ⁢ norm ℎ ⁡ t + ℎ h ∈ ℝ → norm ℎ ⁡ t ≤ norm ℎ ⁡ t + norm ℎ ⁡ h ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h → norm ℎ ⁡ t ≤ v ⁢ norm ℎ ⁡ t + ℎ h
48 36 39 46 47 syl3anc ⊢ t ∈ A ∧ h ∈ B ∧ v ∈ ℝ → norm ℎ ⁡ t ≤ norm ℎ ⁡ t + norm ℎ ⁡ h ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h → norm ℎ ⁡ t ≤ v ⁢ norm ℎ ⁡ t + ℎ h
49 35 48 mpand ⊢ t ∈ A ∧ h ∈ B ∧ v ∈ ℝ → norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h → norm ℎ ⁡ t ≤ v ⁢ norm ℎ ⁡ t + ℎ h
50 49 imp ⊢ t ∈ A ∧ h ∈ B ∧ v ∈ ℝ ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h → norm ℎ ⁡ t ≤ v ⁢ norm ℎ ⁡ t + ℎ h
51 50 an32s ⊢ t ∈ A ∧ h ∈ B ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h ∧ v ∈ ℝ → norm ℎ ⁡ t ≤ v ⁢ norm ℎ ⁡ t + ℎ h
52 51 adantrl ⊢ t ∈ A ∧ h ∈ B ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h ∧ A ∩ B = 0 ℋ ∧ v ∈ ℝ → norm ℎ ⁡ t ≤ v ⁢ norm ℎ ⁡ t + ℎ h
53 22 52 eqbrtrd ⊢ t ∈ A ∧ h ∈ B ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h ∧ A ∩ B = 0 ℋ ∧ v ∈ ℝ → norm ℎ ⁡ S ⁡ t + ℎ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h
54 2fveq3 ⊢ u = t + ℎ h → norm ℎ ⁡ S ⁡ u = norm ℎ ⁡ S ⁡ t + ℎ h
55 fveq2 ⊢ u = t + ℎ h → norm ℎ ⁡ u = norm ℎ ⁡ t + ℎ h
56 55 oveq2d ⊢ u = t + ℎ h → v ⁢ norm ℎ ⁡ u = v ⁢ norm ℎ ⁡ t + ℎ h
57 54 56 breq12d ⊢ u = t + ℎ h → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u ↔ norm ℎ ⁡ S ⁡ t + ℎ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h
58 53 57 syl5ibrcom ⊢ t ∈ A ∧ h ∈ B ∧ norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h ∧ A ∩ B = 0 ℋ ∧ v ∈ ℝ → u = t + ℎ h → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
59 58 exp31 ⊢ t ∈ A ∧ h ∈ B → norm ℎ ⁡ t + norm ℎ ⁡ h ≤ v ⁢ norm ℎ ⁡ t + ℎ h → A ∩ B = 0 ℋ ∧ v ∈ ℝ → u = t + ℎ h → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
60 18 59 syld ⊢ t ∈ A ∧ h ∈ B → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → A ∩ B = 0 ℋ ∧ v ∈ ℝ → u = t + ℎ h → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
61 60 com14 ⊢ u = t + ℎ h → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → A ∩ B = 0 ℋ ∧ v ∈ ℝ → t ∈ A ∧ h ∈ B → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
62 61 com4t ⊢ A ∩ B = 0 ℋ ∧ v ∈ ℝ → t ∈ A ∧ h ∈ B → u = t + ℎ h → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
63 62 rexlimdvv ⊢ A ∩ B = 0 ℋ ∧ v ∈ ℝ → ∃ t ∈ A ∃ h ∈ B u = t + ℎ h → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
64 6 63 syl5com ⊢ u ∈ A + ℋ B → A ∩ B = 0 ℋ ∧ v ∈ ℝ → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
65 64 com3l ⊢ A ∩ B = 0 ℋ ∧ v ∈ ℝ → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → u ∈ A + ℋ B → norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
66 65 ralrimdv ⊢ A ∩ B = 0 ℋ ∧ v ∈ ℝ → ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → ∀ u ∈ A + ℋ B norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
67 66 anim2d ⊢ A ∩ B = 0 ℋ ∧ v ∈ ℝ → 0 < v ∧ ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → 0 < v ∧ ∀ u ∈ A + ℋ B norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
68 67 reximdva ⊢ A ∩ B = 0 ℋ → ∃ v ∈ ℝ 0 < v ∧ ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → ∃ v ∈ ℝ 0 < v ∧ ∀ u ∈ A + ℋ B norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u
69 4 68 mpcom ⊢ ∃ v ∈ ℝ 0 < v ∧ ∀ x ∈ A ∀ y ∈ B norm ℎ ⁡ x + norm ℎ ⁡ y ≤ v ⁢ norm ℎ ⁡ x + ℎ y → ∃ v ∈ ℝ 0 < v ∧ ∀ u ∈ A + ℋ B norm ℎ ⁡ S ⁡ u ≤ v ⁢ norm ℎ ⁡ u