Metamath Proof Explorer


Theorem drngnidl

Description: A division ring has only the two trivial ideals. (Contributed by Stefan O'Rear, 3-Jan-2015) (Revised by Wolf Lammen, 6-Sep-2020)

Ref Expression
Hypotheses drngnidl.b ⊢ B = Base R
drngnidl.z ⊢ 0 ˙ = 0 R
drngnidl.u ⊢ U = LIdeal ⁡ R
Assertion drngnidl ⊢ R ∈ DivRing → U = 0 ˙ B

Proof

Step Hyp Ref Expression
1 drngnidl.b ⊢ B = Base R
2 drngnidl.z ⊢ 0 ˙ = 0 R
3 drngnidl.u ⊢ U = LIdeal ⁡ R
4 animorrl ⊢ R ∈ DivRing ∧ a ∈ U ∧ a = 0 ˙ → a = 0 ˙ ∨ a = B
5 drngring ⊢ R ∈ DivRing → R ∈ Ring
6 5 ad2antrr ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → R ∈ Ring
7 simplr ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → a ∈ U
8 simpr ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → a ≠ 0 ˙
9 3 2 lidlnz ⊢ R ∈ Ring ∧ a ∈ U ∧ a ≠ 0 ˙ → ∃ b ∈ a b ≠ 0 ˙
10 6 7 8 9 syl3anc ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → ∃ b ∈ a b ≠ 0 ˙
11 simpll ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → R ∈ DivRing
12 1 3 lidlss ⊢ a ∈ U → a ⊆ B
13 12 adantl ⊢ R ∈ DivRing ∧ a ∈ U → a ⊆ B
14 13 sselda ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a → b ∈ B
15 14 adantrr ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → b ∈ B
16 simprr ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → b ≠ 0 ˙
17 eqid ⊢ ⋅ R = ⋅ R
18 eqid ⊢ 1 R = 1 R
19 eqid ⊢ inv r ⁡ R = inv r ⁡ R
20 1 2 17 18 19 drnginvrl ⊢ R ∈ DivRing ∧ b ∈ B ∧ b ≠ 0 ˙ → inv r ⁡ R ⁡ b ⋅ R b = 1 R
21 11 15 16 20 syl3anc ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → inv r ⁡ R ⁡ b ⋅ R b = 1 R
22 5 ad2antrr ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → R ∈ Ring
23 simplr ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → a ∈ U
24 1 2 19 drnginvrcl ⊢ R ∈ DivRing ∧ b ∈ B ∧ b ≠ 0 ˙ → inv r ⁡ R ⁡ b ∈ B
25 11 15 16 24 syl3anc ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → inv r ⁡ R ⁡ b ∈ B
26 simprl ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → b ∈ a
27 3 1 17 lidlmcl ⊢ R ∈ Ring ∧ a ∈ U ∧ inv r ⁡ R ⁡ b ∈ B ∧ b ∈ a → inv r ⁡ R ⁡ b ⋅ R b ∈ a
28 22 23 25 26 27 syl22anc ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → inv r ⁡ R ⁡ b ⋅ R b ∈ a
29 21 28 eqeltrrd ⊢ R ∈ DivRing ∧ a ∈ U ∧ b ∈ a ∧ b ≠ 0 ˙ → 1 R ∈ a
30 29 rexlimdvaa ⊢ R ∈ DivRing ∧ a ∈ U → ∃ b ∈ a b ≠ 0 ˙ → 1 R ∈ a
31 30 imp ⊢ R ∈ DivRing ∧ a ∈ U ∧ ∃ b ∈ a b ≠ 0 ˙ → 1 R ∈ a
32 10 31 syldan ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → 1 R ∈ a
33 3 1 18 lidl1el ⊢ R ∈ Ring ∧ a ∈ U → 1 R ∈ a ↔ a = B
34 5 33 sylan ⊢ R ∈ DivRing ∧ a ∈ U → 1 R ∈ a ↔ a = B
35 34 adantr ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → 1 R ∈ a ↔ a = B
36 32 35 mpbid ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → a = B
37 36 olcd ⊢ R ∈ DivRing ∧ a ∈ U ∧ a ≠ 0 ˙ → a = 0 ˙ ∨ a = B
38 4 37 pm2.61dane ⊢ R ∈ DivRing ∧ a ∈ U → a = 0 ˙ ∨ a = B
39 vex ⊢ a ∈ V
40 39 elpr ⊢ a ∈ 0 ˙ B ↔ a = 0 ˙ ∨ a = B
41 38 40 sylibr ⊢ R ∈ DivRing ∧ a ∈ U → a ∈ 0 ˙ B
42 41 ex ⊢ R ∈ DivRing → a ∈ U → a ∈ 0 ˙ B
43 42 ssrdv ⊢ R ∈ DivRing → U ⊆ 0 ˙ B
44 3 2 lidl0 ⊢ R ∈ Ring → 0 ˙ ∈ U
45 3 1 lidl1 ⊢ R ∈ Ring → B ∈ U
46 44 45 prssd ⊢ R ∈ Ring → 0 ˙ B ⊆ U
47 5 46 syl ⊢ R ∈ DivRing → 0 ˙ B ⊆ U
48 43 47 eqssd ⊢ R ∈ DivRing → U = 0 ˙ B