Metamath Proof Explorer


Theorem isdrngrd

Description: Properties that characterize a division ring among rings: it should be nonzero, have no nonzero zero-divisors, and every nonzero element x should have a right-inverse I ( x ) . See isdrngd for the characterization using left-inverses. (Contributed by NM, 10-Aug-2013) Remove hypothesis. (Revised by SN, 19-Feb-2025)

Ref Expression
Hypotheses isdrngd.b ⊢ φ → B = Base R
isdrngd.t ⊢ φ → · ˙ = ⋅ R
isdrngd.z ⊢ φ → 0 ˙ = 0 R
isdrngd.u ⊢ φ → 1 ˙ = 1 R
isdrngd.r ⊢ φ → R ∈ Ring
isdrngd.n ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ y ∈ B ∧ y ≠ 0 ˙ → x · ˙ y ≠ 0 ˙
isdrngd.o ⊢ φ → 1 ˙ ≠ 0 ˙
isdrngd.i ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → I ∈ B
isdrngrd.k ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → x · ˙ I = 1 ˙
Assertion isdrngrd ⊢ φ → R ∈ DivRing

Proof

Step Hyp Ref Expression
1 isdrngd.b ⊢ φ → B = Base R
2 isdrngd.t ⊢ φ → · ˙ = ⋅ R
3 isdrngd.z ⊢ φ → 0 ˙ = 0 R
4 isdrngd.u ⊢ φ → 1 ˙ = 1 R
5 isdrngd.r ⊢ φ → R ∈ Ring
6 isdrngd.n ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ y ∈ B ∧ y ≠ 0 ˙ → x · ˙ y ≠ 0 ˙
7 isdrngd.o ⊢ φ → 1 ˙ ≠ 0 ˙
8 isdrngd.i ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → I ∈ B
9 isdrngrd.k ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → x · ˙ I = 1 ˙
10 eqid ⊢ opp r ⁡ R = opp r ⁡ R
11 eqid ⊢ Base R = Base R
12 10 11 opprbas ⊢ Base R = Base opp r ⁡ R
13 1 12 eqtrdi ⊢ φ → B = Base opp r ⁡ R
14 eqidd ⊢ φ → ⋅ opp r ⁡ R = ⋅ opp r ⁡ R
15 eqid ⊢ 0 R = 0 R
16 10 15 oppr0 ⊢ 0 R = 0 opp r ⁡ R
17 3 16 eqtrdi ⊢ φ → 0 ˙ = 0 opp r ⁡ R
18 eqid ⊢ 1 R = 1 R
19 10 18 oppr1 ⊢ 1 R = 1 opp r ⁡ R
20 4 19 eqtrdi ⊢ φ → 1 ˙ = 1 opp r ⁡ R
21 10 opprring ⊢ R ∈ Ring → opp r ⁡ R ∈ Ring
22 5 21 syl ⊢ φ → opp r ⁡ R ∈ Ring
23 eleq1w ⊢ y = x → y ∈ B ↔ x ∈ B
24 neeq1 ⊢ y = x → y ≠ 0 ˙ ↔ x ≠ 0 ˙
25 23 24 anbi12d ⊢ y = x → y ∈ B ∧ y ≠ 0 ˙ ↔ x ∈ B ∧ x ≠ 0 ˙
26 25 3anbi2d ⊢ y = x → φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙ ↔ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙
27 oveq1 ⊢ y = x → y ⋅ opp r ⁡ R z = x ⋅ opp r ⁡ R z
28 27 neeq1d ⊢ y = x → y ⋅ opp r ⁡ R z ≠ 0 ˙ ↔ x ⋅ opp r ⁡ R z ≠ 0 ˙
29 26 28 imbi12d ⊢ y = x → φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙ → y ⋅ opp r ⁡ R z ≠ 0 ˙ ↔ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙ → x ⋅ opp r ⁡ R z ≠ 0 ˙
30 eleq1w ⊢ x = z → x ∈ B ↔ z ∈ B
31 neeq1 ⊢ x = z → x ≠ 0 ˙ ↔ z ≠ 0 ˙
32 30 31 anbi12d ⊢ x = z → x ∈ B ∧ x ≠ 0 ˙ ↔ z ∈ B ∧ z ≠ 0 ˙
33 32 3anbi3d ⊢ x = z → φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ x ∈ B ∧ x ≠ 0 ˙ ↔ φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙
34 oveq2 ⊢ x = z → y ⋅ opp r ⁡ R x = y ⋅ opp r ⁡ R z
35 34 neeq1d ⊢ x = z → y ⋅ opp r ⁡ R x ≠ 0 ˙ ↔ y ⋅ opp r ⁡ R z ≠ 0 ˙
36 33 35 imbi12d ⊢ x = z → φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ x ∈ B ∧ x ≠ 0 ˙ → y ⋅ opp r ⁡ R x ≠ 0 ˙ ↔ φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙ → y ⋅ opp r ⁡ R z ≠ 0 ˙
37 2 3ad2ant1 ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ y ∈ B ∧ y ≠ 0 ˙ → · ˙ = ⋅ R
38 37 oveqd ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ y ∈ B ∧ y ≠ 0 ˙ → x · ˙ y = x ⋅ R y
39 eqid ⊢ ⋅ R = ⋅ R
40 eqid ⊢ ⋅ opp r ⁡ R = ⋅ opp r ⁡ R
41 11 39 10 40 opprmul ⊢ y ⋅ opp r ⁡ R x = x ⋅ R y
42 38 41 eqtr4di ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ y ∈ B ∧ y ≠ 0 ˙ → x · ˙ y = y ⋅ opp r ⁡ R x
43 42 6 eqnetrrd ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ y ∈ B ∧ y ≠ 0 ˙ → y ⋅ opp r ⁡ R x ≠ 0 ˙
44 43 3com23 ⊢ φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ x ∈ B ∧ x ≠ 0 ˙ → y ⋅ opp r ⁡ R x ≠ 0 ˙
45 36 44 chvarvv ⊢ φ ∧ y ∈ B ∧ y ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙ → y ⋅ opp r ⁡ R z ≠ 0 ˙
46 29 45 chvarvv ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ ∧ z ∈ B ∧ z ≠ 0 ˙ → x ⋅ opp r ⁡ R z ≠ 0 ˙
47 11 39 10 40 opprmul ⊢ I ⋅ opp r ⁡ R x = x ⋅ R I
48 2 adantr ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → · ˙ = ⋅ R
49 48 oveqd ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → x · ˙ I = x ⋅ R I
50 49 9 eqtr3d ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → x ⋅ R I = 1 ˙
51 47 50 eqtrid ⊢ φ ∧ x ∈ B ∧ x ≠ 0 ˙ → I ⋅ opp r ⁡ R x = 1 ˙
52 13 14 17 20 22 46 7 8 51 isdrngd ⊢ φ → opp r ⁡ R ∈ DivRing
53 10 opprdrng ⊢ R ∈ DivRing ↔ opp r ⁡ R ∈ DivRing
54 52 53 sylibr ⊢ φ → R ∈ DivRing