Description: Lemma for lcmfdvds and lcmfunsn . These two theorems must be proven simultaneously by induction on the cardinality of a finite set Y , because they depend on each other. This can be seen by the two parts lcmfunsnlem1 and lcmfunsnlem2 of the induction step, each of them using both induction hypotheses. (Contributed by AV, 26-Aug-2020)
Ref | Expression | ||
---|---|---|---|
Assertion | lcmfunsnlem | |