Metamath Proof Explorer


Theorem lmhmf1o

Description: A bijective module homomorphism is also converse homomorphic. (Contributed by Stefan O'Rear, 25-Jan-2015)

Ref Expression
Hypotheses lmhmf1o.x ⊢ X = Base S
lmhmf1o.y ⊢ Y = Base T
Assertion lmhmf1o ⊢ F ∈ S LMHom T → F : X ⟶ 1-1 onto Y ↔ F -1 ∈ T LMHom S

Proof

Step Hyp Ref Expression
1 lmhmf1o.x ⊢ X = Base S
2 lmhmf1o.y ⊢ Y = Base T
3 eqid ⊢ ⋅ T = ⋅ T
4 eqid ⊢ ⋅ S = ⋅ S
5 eqid ⊢ Scalar ⁡ T = Scalar ⁡ T
6 eqid ⊢ Scalar ⁡ S = Scalar ⁡ S
7 eqid ⊢ Base Scalar ⁡ T = Base Scalar ⁡ T
8 lmhmlmod2 ⊢ F ∈ S LMHom T → T ∈ LMod
9 8 adantr ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → T ∈ LMod
10 lmhmlmod1 ⊢ F ∈ S LMHom T → S ∈ LMod
11 10 adantr ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → S ∈ LMod
12 6 5 lmhmsca ⊢ F ∈ S LMHom T → Scalar ⁡ T = Scalar ⁡ S
13 12 eqcomd ⊢ F ∈ S LMHom T → Scalar ⁡ S = Scalar ⁡ T
14 13 adantr ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → Scalar ⁡ S = Scalar ⁡ T
15 lmghm ⊢ F ∈ S LMHom T → F ∈ S GrpHom T
16 1 2 ghmf1o ⊢ F ∈ S GrpHom T → F : X ⟶ 1-1 onto Y ↔ F -1 ∈ T GrpHom S
17 15 16 syl ⊢ F ∈ S LMHom T → F : X ⟶ 1-1 onto Y ↔ F -1 ∈ T GrpHom S
18 17 biimpa ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → F -1 ∈ T GrpHom S
19 simpll ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F ∈ S LMHom T
20 14 fveq2d ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → Base Scalar ⁡ S = Base Scalar ⁡ T
21 20 eleq2d ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → a ∈ Base Scalar ⁡ S ↔ a ∈ Base Scalar ⁡ T
22 21 biimpar ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T → a ∈ Base Scalar ⁡ S
23 22 adantrr ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → a ∈ Base Scalar ⁡ S
24 f1ocnv ⊢ F : X ⟶ 1-1 onto Y → F -1 : Y ⟶ 1-1 onto X
25 f1of ⊢ F -1 : Y ⟶ 1-1 onto X → F -1 : Y ⟶ X
26 24 25 syl ⊢ F : X ⟶ 1-1 onto Y → F -1 : Y ⟶ X
27 26 adantl ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → F -1 : Y ⟶ X
28 27 ffvelcdmda ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ b ∈ Y → F -1 ⁡ b ∈ X
29 28 adantrl ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F -1 ⁡ b ∈ X
30 eqid ⊢ Base Scalar ⁡ S = Base Scalar ⁡ S
31 6 30 1 4 3 lmhmlin ⊢ F ∈ S LMHom T ∧ a ∈ Base Scalar ⁡ S ∧ F -1 ⁡ b ∈ X → F ⁡ a ⋅ S F -1 ⁡ b = a ⋅ T F ⁡ F -1 ⁡ b
32 19 23 29 31 syl3anc ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F ⁡ a ⋅ S F -1 ⁡ b = a ⋅ T F ⁡ F -1 ⁡ b
33 f1ocnvfv2 ⊢ F : X ⟶ 1-1 onto Y ∧ b ∈ Y → F ⁡ F -1 ⁡ b = b
34 33 ad2ant2l ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F ⁡ F -1 ⁡ b = b
35 34 oveq2d ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → a ⋅ T F ⁡ F -1 ⁡ b = a ⋅ T b
36 32 35 eqtrd ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F ⁡ a ⋅ S F -1 ⁡ b = a ⋅ T b
37 simplr ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F : X ⟶ 1-1 onto Y
38 11 adantr ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → S ∈ LMod
39 1 6 4 30 lmodvscl ⊢ S ∈ LMod ∧ a ∈ Base Scalar ⁡ S ∧ F -1 ⁡ b ∈ X → a ⋅ S F -1 ⁡ b ∈ X
40 38 23 29 39 syl3anc ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → a ⋅ S F -1 ⁡ b ∈ X
41 f1ocnvfv ⊢ F : X ⟶ 1-1 onto Y ∧ a ⋅ S F -1 ⁡ b ∈ X → F ⁡ a ⋅ S F -1 ⁡ b = a ⋅ T b → F -1 ⁡ a ⋅ T b = a ⋅ S F -1 ⁡ b
42 37 40 41 syl2anc ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F ⁡ a ⋅ S F -1 ⁡ b = a ⋅ T b → F -1 ⁡ a ⋅ T b = a ⋅ S F -1 ⁡ b
43 36 42 mpd ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y ∧ a ∈ Base Scalar ⁡ T ∧ b ∈ Y → F -1 ⁡ a ⋅ T b = a ⋅ S F -1 ⁡ b
44 2 3 4 5 6 7 9 11 14 18 43 islmhmd ⊢ F ∈ S LMHom T ∧ F : X ⟶ 1-1 onto Y → F -1 ∈ T LMHom S
45 1 2 lmhmf ⊢ F ∈ S LMHom T → F : X ⟶ Y
46 45 ffnd ⊢ F ∈ S LMHom T → F Fn X
47 46 adantr ⊢ F ∈ S LMHom T ∧ F -1 ∈ T LMHom S → F Fn X
48 2 1 lmhmf ⊢ F -1 ∈ T LMHom S → F -1 : Y ⟶ X
49 48 adantl ⊢ F ∈ S LMHom T ∧ F -1 ∈ T LMHom S → F -1 : Y ⟶ X
50 49 ffnd ⊢ F ∈ S LMHom T ∧ F -1 ∈ T LMHom S → F -1 Fn Y
51 dff1o4 ⊢ F : X ⟶ 1-1 onto Y ↔ F Fn X ∧ F -1 Fn Y
52 47 50 51 sylanbrc ⊢ F ∈ S LMHom T ∧ F -1 ∈ T LMHom S → F : X ⟶ 1-1 onto Y
53 44 52 impbida ⊢ F ∈ S LMHom T → F : X ⟶ 1-1 onto Y ↔ F -1 ∈ T LMHom S