Metamath Proof Explorer


Theorem nlpineqsn

Description: For every point p of a subset A of X with no limit points, there exists an open set n that intersects A only at p . (Contributed by ML, 23-Mar-2021)

Ref Expression
Hypothesis nlpineqsn.x ⊢ X = ⋃ J
Assertion nlpineqsn ⊢ J ∈ Top ∧ A ⊆ X ∧ limPt ⁡ J ⁡ A = ∅ → ∀ p ∈ A ∃ n ∈ J p ∈ n ∧ n ∩ A = p

Proof

Step Hyp Ref Expression
1 nlpineqsn.x ⊢ X = ⋃ J
2 simp1 ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A → J ∈ Top
3 simp2 ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A → A ⊆ X
4 ssel2 ⊢ A ⊆ X ∧ p ∈ A → p ∈ X
5 4 3adant1 ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A → p ∈ X
6 2 3 5 3jca ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A → J ∈ Top ∧ A ⊆ X ∧ p ∈ X
7 noel ⊢ ¬ p ∈ ∅
8 eleq2 ⊢ limPt ⁡ J ⁡ A = ∅ → p ∈ limPt ⁡ J ⁡ A ↔ p ∈ ∅
9 7 8 mtbiri ⊢ limPt ⁡ J ⁡ A = ∅ → ¬ p ∈ limPt ⁡ J ⁡ A
10 9 adantl ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ X ∧ limPt ⁡ J ⁡ A = ∅ → ¬ p ∈ limPt ⁡ J ⁡ A
11 1 islp3 ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ X → p ∈ limPt ⁡ J ⁡ A ↔ ∀ n ∈ J p ∈ n → n ∩ A ∖ p ≠ ∅
12 11 adantr ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ X ∧ limPt ⁡ J ⁡ A = ∅ → p ∈ limPt ⁡ J ⁡ A ↔ ∀ n ∈ J p ∈ n → n ∩ A ∖ p ≠ ∅
13 10 12 mtbid ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ X ∧ limPt ⁡ J ⁡ A = ∅ → ¬ ∀ n ∈ J p ∈ n → n ∩ A ∖ p ≠ ∅
14 nne ⊢ ¬ n ∩ A ∖ p ≠ ∅ ↔ n ∩ A ∖ p = ∅
15 14 anbi2i ⊢ p ∈ n ∧ ¬ n ∩ A ∖ p ≠ ∅ ↔ p ∈ n ∧ n ∩ A ∖ p = ∅
16 annim ⊢ p ∈ n ∧ ¬ n ∩ A ∖ p ≠ ∅ ↔ ¬ p ∈ n → n ∩ A ∖ p ≠ ∅
17 15 16 bitr3i ⊢ p ∈ n ∧ n ∩ A ∖ p = ∅ ↔ ¬ p ∈ n → n ∩ A ∖ p ≠ ∅
18 17 rexbii ⊢ ∃ n ∈ J p ∈ n ∧ n ∩ A ∖ p = ∅ ↔ ∃ n ∈ J ¬ p ∈ n → n ∩ A ∖ p ≠ ∅
19 rexnal ⊢ ∃ n ∈ J ¬ p ∈ n → n ∩ A ∖ p ≠ ∅ ↔ ¬ ∀ n ∈ J p ∈ n → n ∩ A ∖ p ≠ ∅
20 18 19 bitri ⊢ ∃ n ∈ J p ∈ n ∧ n ∩ A ∖ p = ∅ ↔ ¬ ∀ n ∈ J p ∈ n → n ∩ A ∖ p ≠ ∅
21 13 20 sylibr ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ X ∧ limPt ⁡ J ⁡ A = ∅ → ∃ n ∈ J p ∈ n ∧ n ∩ A ∖ p = ∅
22 6 21 sylan ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A ∧ limPt ⁡ J ⁡ A = ∅ → ∃ n ∈ J p ∈ n ∧ n ∩ A ∖ p = ∅
23 indif2 ⊢ n ∩ A ∖ p = n ∩ A ∖ p
24 23 eqeq1i ⊢ n ∩ A ∖ p = ∅ ↔ n ∩ A ∖ p = ∅
25 ssdif0 ⊢ n ∩ A ⊆ p ↔ n ∩ A ∖ p = ∅
26 24 25 bitr4i ⊢ n ∩ A ∖ p = ∅ ↔ n ∩ A ⊆ p
27 elin ⊢ p ∈ n ∩ A ↔ p ∈ n ∧ p ∈ A
28 sssn ⊢ n ∩ A ⊆ p ↔ n ∩ A = ∅ ∨ n ∩ A = p
29 n0i ⊢ p ∈ n ∩ A → ¬ n ∩ A = ∅
30 biorf ⊢ ¬ n ∩ A = ∅ → n ∩ A = p ↔ n ∩ A = ∅ ∨ n ∩ A = p
31 29 30 syl ⊢ p ∈ n ∩ A → n ∩ A = p ↔ n ∩ A = ∅ ∨ n ∩ A = p
32 28 31 bitr4id ⊢ p ∈ n ∩ A → n ∩ A ⊆ p ↔ n ∩ A = p
33 27 32 sylbir ⊢ p ∈ n ∧ p ∈ A → n ∩ A ⊆ p ↔ n ∩ A = p
34 26 33 bitrid ⊢ p ∈ n ∧ p ∈ A → n ∩ A ∖ p = ∅ ↔ n ∩ A = p
35 34 ancoms ⊢ p ∈ A ∧ p ∈ n → n ∩ A ∖ p = ∅ ↔ n ∩ A = p
36 35 pm5.32da ⊢ p ∈ A → p ∈ n ∧ n ∩ A ∖ p = ∅ ↔ p ∈ n ∧ n ∩ A = p
37 36 rexbidv ⊢ p ∈ A → ∃ n ∈ J p ∈ n ∧ n ∩ A ∖ p = ∅ ↔ ∃ n ∈ J p ∈ n ∧ n ∩ A = p
38 37 3ad2ant3 ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A → ∃ n ∈ J p ∈ n ∧ n ∩ A ∖ p = ∅ ↔ ∃ n ∈ J p ∈ n ∧ n ∩ A = p
39 38 adantr ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A ∧ limPt ⁡ J ⁡ A = ∅ → ∃ n ∈ J p ∈ n ∧ n ∩ A ∖ p = ∅ ↔ ∃ n ∈ J p ∈ n ∧ n ∩ A = p
40 22 39 mpbid ⊢ J ∈ Top ∧ A ⊆ X ∧ p ∈ A ∧ limPt ⁡ J ⁡ A = ∅ → ∃ n ∈ J p ∈ n ∧ n ∩ A = p
41 40 3an1rs ⊢ J ∈ Top ∧ A ⊆ X ∧ limPt ⁡ J ⁡ A = ∅ ∧ p ∈ A → ∃ n ∈ J p ∈ n ∧ n ∩ A = p
42 41 ralrimiva ⊢ J ∈ Top ∧ A ⊆ X ∧ limPt ⁡ J ⁡ A = ∅ → ∀ p ∈ A ∃ n ∈ J p ∈ n ∧ n ∩ A = p